265^65 > 36^60 nha

Ta có : 265^65 = 265^60.265^5
Mà 265^60 > 36^60
=> 265^60.265^5 > 36^60 (Vì 265^5>0)
=> 256^65>36^60
Hok tốt ~~~

Nãy vội viết lộn nha: 
Ta có : 265^65 = 265^60.265^5
Mà 265^60 > 36^60
=> 265^60.265^5 > 36^60 (Vì 265^5>0)
=> 265^65>36^60

Hok tốt~~~

\(A=\sqrt[]{50}+\sqrt[]{65}\Rightarrow A^2=50+65+2\sqrt[]{50.65}=115+2\sqrt[]{5.10.5.13=}115+10\sqrt[]{130}\left(1\right)\)

\(B=\sqrt[]{15}+\sqrt[]{115}\Rightarrow B^2=15+115+2\sqrt[]{15.115}=15+115+2\sqrt[]{3.5.5.23}=15+115+10\sqrt[]{69}\left(2\right)\)Ta có  \(10\sqrt[]{130}< 10\sqrt[]{69.2}=10\sqrt[]{2}\sqrt[]{69}< 15+10\sqrt[]{69}\left(3\right)\)

\(\left(1\right),\left(2\right),\left(3\right)\Rightarrow A^2< B^2\Rightarrow A< B\)

\(\Rightarrow\sqrt[]{50}+\sqrt[]{65}< \sqrt[]{15}+\sqrt[]{115}\)

So sánh gì thế em, em nhập đủ đề vào hi

400

,.....................................

135 + 86 + 65 - 36 + 17 + 50 + 83 

= ( 135 + 65 ) + 86 - 36 + ( 17 + 83 ) + 50

= 200 + 86 - 36 + 100 + 50

= 286 - 136 + 50

= 286 - 186

= 100

135 + 86 + 65 - 36 + 17 + 50 + 83 

= ( 135 + 65 ) + 86 - 36 + ( 17 + 83 ) + 50

= 200 + 86 - 36 + 100 + 50

= 286 - 136 + 50

= 286 - 186

= 100

\(ƯCLN\left(15,50\right)=5\\ ƯC\left(15,50\right)=Ư\left(5\right)=\left\{...\right\}\\ ƯCLN\left(36,48\right)=12\\ ƯC\left(36,48\right)=Ư\left(12\right)=\left\{...\right\}\\ ƯCLN\left(20,65\right)=5\\ ƯC\left(20,65\right)=Ư\left(5\right)=\left\{...\right\}\)

226

ai tk mk mk tk lại

thanks

=226

chán quá có ai 

kb ko 

mk hl zùi

= 50 + ( 65 + 75 ) + 36

= 50 + 140 + 36

= 190 + 36

= 226

Ta có:

\(3^{50}>3^{48}\)   (1)

\(3^{48}=\left(3^4\right)^{12}=81^{12}\)

\(4^{36}=\left(4^3\right)^{12}=64^{12}\)

Do \(81>64\Rightarrow81^{12}>64^{12}\)

\(\Rightarrow3^{48}>4^{36}\)   (2)

Từ (1) và (2) \(\Rightarrow3^{50}>4^{36}\)

a) 9                      

b) 39

bạn tự phân tích ra thừa số nguyên tố rồi tự tìm

50 ; 75 => 25

24 ; 36 => 12

70 ; 85 => 5

84 ; 56 => 28

42 ; 140 ; 168 => 14

20 ; 30 ; 60 => 20

100 ; 140 ; 280 => 20

65 ; 108 ; 425 => 1

\(a,\dfrac{52}{32}=\dfrac{13}{8}\\ \dfrac{55}{65}=\dfrac{11}{13}\\ MSC:104\\ =>\dfrac{13}{8}=\dfrac{13.13}{8.13}=\dfrac{169}{104}\\ \dfrac{11}{13}=\dfrac{11.8}{13.8}=\dfrac{88}{104}\)

\(b,\dfrac{72}{64}=\dfrac{9}{8}\\ \dfrac{54}{81}=\dfrac{2}{3}\\ MSC:24\\ \dfrac{9}{8}=\dfrac{9.3}{8.3}=\dfrac{27}{24}\\ \dfrac{2}{3}=\dfrac{2.8}{3.8}=\dfrac{16}{24}\\ c,\dfrac{24}{36}=\dfrac{2}{3}\\ \dfrac{12}{30}=\dfrac{2}{5}\\ MSC:15\\ \dfrac{2}{3}=\dfrac{2.5}{3.5}=\dfrac{10}{15}\\ \dfrac{2}{5}=\dfrac{2.3}{3.5}=\dfrac{6}{15}\)

\(d,\dfrac{80}{40}=2\\ \dfrac{45}{63}=\dfrac{5}{7}\\ MSC:7\\ 2=\dfrac{14}{7}\\ e,\dfrac{150}{50}=3\\ \dfrac{100}{200}=\dfrac{1}{2}\\ MSC:2\\ 3=\dfrac{6}{2}\\ f,\dfrac{54}{81}=\dfrac{2}{3}\\ \dfrac{69}{93}=\dfrac{23}{21}\\ MSC:21\\ \dfrac{2}{3}=\dfrac{2.7}{3.7}=\dfrac{14}{21}\)

\(a.\dfrac{52}{32}\text{=}\dfrac{13}{8};\dfrac{55}{65}\text{=}\dfrac{11}{13}\)

\(\dfrac{13.13}{13.8}\text{=}\dfrac{169}{104};\dfrac{11.8}{13.8}\text{=}\dfrac{88}{104}\)

\(c.\dfrac{24}{36}\text{=}\dfrac{2}{3};\dfrac{12}{30}\text{=}\dfrac{2}{5}\)

\(\dfrac{2.5}{3.5}\text{=}\dfrac{10}{15};\dfrac{2.3}{5.3}\text{=}\dfrac{6}{15}\)

\(b.\dfrac{72}{64}\text{=}\dfrac{9.3}{8.3}\text{=}\dfrac{27}{24};\dfrac{54}{81}\text{=}\dfrac{2.8}{3.8}\text{=}\dfrac{16}{24}\)

\(d.\dfrac{80}{40}\text{=}\dfrac{2.63}{63}\text{=}\dfrac{126}{63};\dfrac{45}{63}\)

\(e.\dfrac{150}{50}\text{=}\dfrac{3.2}{2}\text{=}\dfrac{6}{2};\dfrac{100}{200}\text{=}\dfrac{1}{2}\)

\(f.\dfrac{54}{81}\text{=}\dfrac{2.31}{3.31}\text{=}\dfrac{62}{93};\dfrac{69}{93}\)