tính hợp lí
(21/31+2013/6039)-(44/53-10/31)-9/53
C1, Tính hợp lí:
1, (21/31 + 2013/6039) - (44/53 - 10/31) - 9/53
C2, Tìm x:
1, x + 30% x = -1,31
2, (4,5 - 2x). (-1 4/7) = 11/14
Câu 1:
\(=\dfrac{21}{31}+\dfrac{1}{3}-\dfrac{44}{53}+\dfrac{10}{31}-\dfrac{9}{53}=\dfrac{1}{3}\)
Câu 2:
1: =>1,3x=-1,31
=>130x=-131
=>x=-131/130
2: =>(4,5-2x)=11/14:(-11/7)=-7/14=-1/2=-0,5
=>2x=5
=>x=5/2
(21/31+2013/6039) - (44/53-10/31)-9/53
Tính
\(\left(\frac{21}{31}+\frac{2013}{6039}\right)-\left(\frac{44}{53}-\frac{10}{31}\right)-\frac{9}{53}\)
\(=\frac{21}{31}+\frac{1}{3}-\frac{44}{53}+\frac{10}{31}-\frac{9}{53}\)
\(=\left(\frac{21}{31}+\frac{10}{31}\right)+\left(-\frac{44}{53}-\frac{9}{53}\right)+\frac{1}{3}\)
\(=1+\left(-1\right)+\frac{1}{3}=0+\frac{1}{3}=\frac{1}{3}.\)
Tính hợp lí:
a.-3/4+3/7+-1/4+4/9+4/7
b. -7/9.4/11+-7/9.7/11+52/9
c. (21/31+2013/6039)-(44/53-10/31)-9/53
Giúp vs ak!!!
a, -3/4 + 3/7 + -1/4 + 4/9 + 4/7
=(−34+−14)+(37+47)+49(−34+−14)+(37+47)+49
=−1+1+49−1+1+49
=49
b. \(\dfrac{-7}{9}.\dfrac{4}{11}+\dfrac{-7}{9}.\dfrac{7}{11}+\dfrac{52}{9}\)
= \(\dfrac{-7}{9}.\left(\dfrac{4}{11}+\dfrac{7}{11}\right)+\dfrac{52}{9}\)
= \(\dfrac{-7}{9}.1+\dfrac{52}{9}\)
= \(\dfrac{-7}{9}+\dfrac{52}{9}\)
= \(\dfrac{45}{9}\)
Chúc bạn học tốt!! ^^
\(a\)) \(\dfrac{-3}{4}+\dfrac{3}{7}+\dfrac{-1}{4}+\dfrac{4}{9}+\dfrac{4}{7}\)
\(=\left(\dfrac{-3}{4}+\dfrac{-1}{4}\right)+\left(\dfrac{3}{7}+\dfrac{4}{7}\right)+\dfrac{4}{9}\)
\(=-1+1+\dfrac{4}{9}\)
\(=0+\dfrac{4}{9}=\dfrac{4}{9}\)
Giúp với :
( 21/31 + 2013/6039 ) - ( 44/53 -10/31 ) - 9/53
Toán Hè
Hỏi cho voi
bỏ ngoặc: 21/31+2013/6039-44/53+10/31-9/53
ta có ; (21/31+10/31)-(44/53+9/53)+1/3
1-1+1/3=1/3
(21/31+2013/6039)-(44/53-10/31)-9/53
=21/31+1/3-44/53+10/31-9/53
=(21/31+10/31)-(44/53+9/53)+1/3
=31/31-53/53+1/3
=1-1+1/3
=0+1/3
=1/3!!!
Tính hợp lý:
a, -3/4 + 3/7 + -1/4 + 4/9 + 4/7
b, -7/9 x 4/11 + -7/9 x 7/11 + 5 và 7/9
c, ( 21/31 + 2013/6039 ) - ( 44/53 - 10/31) - /53
a, -3/4 + 3/7 + -1/4 + 4/9 + 4/7
=\(\left(\frac{-3}{4}+\frac{-1}{4}\right)+\left(\frac{3}{7}+\frac{4}{7}\right)+\frac{4}{9}\)
=\(-1+1+\frac{4}{9}\)
=\(\frac{4}{9}\)
b, -7/9 x 4/11 + -7/9 x 7/11 + 5 và 7/9
\(=\frac{7}{9}x\frac{-4}{11}+\frac{7}{9}x\frac{-7}{11}+5x\frac{7}{9}\)
\(=\frac{7}{9}x\left(\frac{-4}{11}+\frac{-7}{11}+5\right)\)
\(=\frac{7}{9}x4\)
\(=\frac{28}{9}\)
c, ( 21/31 + 2013/6039 ) - ( 44/53 - 10/31) - /53
\(\left(\frac{21}{31}+\frac{2013}{6039}\right)-\left(\frac{44}{53}-\frac{10}{31}\right)-\frac{9}{53}\)
Thực hiện phép tính
= 21/31 + 1/3 - 44/53 + 10/31 -9/53
= [21/31+10/31] - [44/53 + 9/53] +1/3
= 1-1+1/3 = 1/3
\(\frac{21}{31}+\frac{2013}{6039}-\frac{44}{53}-\frac{10}{31}-\frac{9}{53}\)
\(\left(\frac{21}{31}-\frac{10}{31}\right)-\left(\frac{44}{53}+\frac{9}{53}\right)+\frac{1}{3}\)
\(\frac{11}{31}-1+\frac{1}{3}\)
\(\frac{-29}{93}\)
1.(21/31+2013/6039)-(44/53-10/31)-9/3
2.Tìm X
(4,5-2x).(-1và4/7)=11/14
C1, Tính hợp lí:
1, (21/31 + 2013/6039) - (44/53 - 10/31) - 9/53
C2, Tìm x:
1, x + 30% x = -1,31
2, (4,5 - 2x). (-1 4/7) = 11/14
C3: 1 ô tô đã đi 120 km trong 3h. H thứ nhất ô tô đi đc 1/2 quãng đường; h thứ hai ô tô đi dc 2/5 quãng đường còn lại.
a, Tính quãng đường ô tô đi trong mỗi giờ
b, Quãng đường đi trong giờ thứ ba chiếm mấy phần trăm cả đoạn đường.
Câu 2:
1:=>1,3x=-1,31
=>x=-131/130
2: =>\(\left(4.5-2x\right)=\dfrac{11}{14}:\dfrac{-11}{7}=\dfrac{-1}{2}=-0.5\)
=>2x=5
=>x=5/2