Ta có ; \(\frac{-7}{25}.\frac{11}{13}+\frac{-7}{25}.\frac{2}{13}-\frac{18}{25}\)

\(=\frac{-7}{25}.\left(\frac{11}{13}+\frac{2}{13}\right)-\frac{18}{25}\)

\(=\frac{-7}{25}.1-\frac{18}{25}\)

\(=\frac{-7}{25}-\frac{18}{25}=\frac{-25}{25}=-1\)

mk ko ghi lại đầu bài nhé

=-7/25.(11/13+2/13)-18/25

=-7/25.1-18/25

=-7/25-18/25

=-25/25

=-1  

~ chúc bạn học toots~ k mk nha

Thanks mina-san nhiều ~!♥ Arigatou gozaimatsu~

= -7/25 x ( 11/13 + 2/13 ) - 18/25

= - 7/25 x 1 - 18/25 

= -7/25 - 18/25 

= -1

nhớ tích cho mình nha mình cảm ơn rất nhìu^^

\(=\dfrac{-7}{25}\left(\dfrac{11}{13}+\dfrac{2}{13}\right)-\dfrac{18}{25}=-1\)

( -7/25 + -7/25 ) . ( 11/13 + 2/13 ) - 18/25

-14/25 . 1 - 18/25

= -32/25

=7/25.(11/13+2/13)- 18/25

=7/25.1-18/25

=7/25-18/25

=-11/25

\(=-\frac{7}{25}.\left(\frac{11}{13}+\frac{2}{13}\right)-\frac{18}{25}\)

\(=-\frac{7}{25}.1-\frac{18}{25}\)

\(=-\frac{7}{25}-\frac{18}{25}\)

\(=1\)

\(1)\)\(-\dfrac{10}{11}.\dfrac{8}{9}+\dfrac{7}{18}.\dfrac{10}{11}\)

\(=\dfrac{10}{11}\left(-\dfrac{8}{9}+\dfrac{7}{18}\right)\)

\(=\dfrac{10}{11}\left(\dfrac{-16}{18}+\dfrac{7}{18}\right)\)

\(=\dfrac{10}{11}.\left(-\dfrac{1}{2}\right)=-\dfrac{5}{11}\)

\(2)\)\(\dfrac{12}{25}.\dfrac{23}{7}-\dfrac{12}{7}.\dfrac{13}{25}\)

\(=\dfrac{12}{7}.\dfrac{23}{25}-\dfrac{12}{7}.\dfrac{13}{25}\)

\(=\dfrac{12}{7}.\left(\dfrac{23}{25}-\dfrac{13}{25}\right)\)

\(=\dfrac{12}{7}.\dfrac{2}{5}=\dfrac{24}{35}\)

\(3)\)\(\dfrac{3}{7}.\dfrac{16}{15}-\dfrac{2}{15}.\dfrac{-3}{7}\)

\(=\dfrac{3}{7}.\dfrac{16}{15}-\dfrac{3}{7}.\dfrac{-2}{15}\)

\(=\dfrac{3}{7}.\left(\dfrac{16}{15}+\dfrac{2}{15}\right)\)

\(=\dfrac{3}{7}.\dfrac{18}{15}=\dfrac{18}{35}\)

\(4)\)\(-\dfrac{4}{13}.\dfrac{5}{17}+\dfrac{-12}{13}.\dfrac{4}{17}\)

\(=-\dfrac{4}{13}.\dfrac{5}{17}+\dfrac{-4}{13}.\dfrac{12}{17}\)

\(=-\dfrac{4}{13}.\left(\dfrac{5}{17}+\dfrac{12}{17}\right)\)

\(=-\dfrac{4}{13}.\dfrac{17}{17}=-\dfrac{4}{13}\)

`#040911`

`1)`

`-10/11 * 8/9 + 7/18 . 10/11`

`= 10/11 * (-8/9 + 7/18)`

`= 10/11 * (-1/2)`

`= -5/11`

`2)`

`12/25 * 23/7 - 12/7 *13/25`

`= 12/7 * 23/25 - 12/7 * 13/25`

`= 12/7 * (23/25 - 13/25)`

`= 12/7 * 2/5`

`= 24/35`

`3)`

`3/7 * 16/15 - 2/15 * (-3)/7`

`= 3/7 * (16/15 + 2/15)`

`= 3/7 * 6/5`

`= 18/35`

`4)`

`-4/13 * 5/17 + (-12)/13 * 4/17`

`= -4/17 * 5/13 + (-12)/13 * 4/17`

`= 4/17 * (-5/13 - 12/13)`

`= 4/17 * (-17)/13`

`= -4/13`

\(a)-7/25*(11/13+2/13)-18/25=-7/25*1-18/25=-7/25-18/25=-25/25=-1\)

\(=-\dfrac{7}{25}\left(\dfrac{11}{13}+\dfrac{2}{13}\right)-\dfrac{18}{25}=-\dfrac{7}{25}.1-\dfrac{18}{25}=-\dfrac{25}{25}=-1\)

\(\dfrac{-7}{25}.\dfrac{11}{13}+\dfrac{-7}{25}.\dfrac{2}{13}-\dfrac{18}{25}\\ =\dfrac{-7}{25}\left(\dfrac{11}{13}+\dfrac{2}{13}\right)-\dfrac{18}{25}\\ =\dfrac{-7}{25}.\dfrac{13}{13}-\dfrac{18}{25}\\ =\dfrac{-7}{25}.1-\dfrac{18}{25}\\ =\dfrac{-7}{25}-\dfrac{18}{25}\\ =\dfrac{-25}{25}\\ =-1\)

`Answer:`

a. \(-\frac{17}{30}-\frac{11}{-15}+-\frac{7}{12}\)

\(=-\frac{17}{30}+\frac{11}{15}-\frac{7}{12}\)

\(=-\frac{17}{30}+\frac{22}{30}-\frac{7}{12}\)

\(=\frac{1}{6}-\frac{7}{12}\)

\(=-\frac{5}{12}\)

b. \(-\frac{5}{9}+\frac{5}{9}:\left(\frac{5}{3}-\frac{25}{12}\right)\)

\(=-\frac{5}{9}+\frac{5}{9}:\left(-\frac{5}{12}\right)\)

\(=\frac{5}{9}.\left(-1\right)+\frac{5}{9}.\left(-\frac{12}{5}\right)\)

\(=\frac{5}{9}.\left(-1-\frac{12}{5}\right)\)

\(=\frac{5}{9}.\frac{-17}{5}\)

\(=-\frac{17}{9}\)

c. \(-\frac{7}{25}.\frac{11}{13}+-\frac{7}{25}-\frac{2}{13}-\frac{18}{25}\)

\(=\frac{77}{325}-\left(\frac{7}{25}+\frac{18}{25}\right)-\frac{2}{13}\)

\(=\frac{77}{325}-1-\frac{2}{13}\)

\(=-\frac{452}{325}\)

Giải:

\(-\dfrac{7}{25}.\dfrac{11}{13}+\dfrac{-7}{25}.\dfrac{2}{13}+2018\dfrac{7}{25}\)

\(=-\dfrac{7}{25}.\dfrac{11}{13}+\dfrac{-7}{25}.\dfrac{2}{13}+2018+\dfrac{7}{25}\)

\(=-\dfrac{7}{25}.\left(\dfrac{11}{13}+\dfrac{2}{13}\right)+2018+\dfrac{7}{25}\)

\(=-\dfrac{7}{25}.1+2018+\dfrac{7}{25}\)

\(=-\dfrac{7}{25}+2018+\dfrac{7}{25}\)

\(=2018\)

Vậy ...