Bài 3 là hỗn số hả em?

Bài 1: 

a) Ta có: \(\dfrac{2}{5}\cdot x+\dfrac{1}{3}=\dfrac{1}{5}\)

\(\Leftrightarrow\dfrac{2}{5}\cdot x=\dfrac{1}{5}-\dfrac{1}{3}=\dfrac{-2}{15}\)

\(\Leftrightarrow x=\dfrac{-2}{15}:\dfrac{2}{5}=\dfrac{-2}{15}\cdot\dfrac{5}{2}\)

hay \(x=-\dfrac{1}{3}\)

Vậy: \(x=-\dfrac{1}{3}\)

b) Ta có: \(\dfrac{1}{5}+\dfrac{5}{3}:x=\dfrac{1}{2}\)

\(\Leftrightarrow\dfrac{5}{3}:x=\dfrac{1}{2}-\dfrac{1}{5}=\dfrac{3}{10}\)

\(\Leftrightarrow x=\dfrac{5}{3}:\dfrac{3}{10}=\dfrac{5}{3}\cdot\dfrac{10}{3}\)

hay \(x=\dfrac{50}{9}\)

Vậy: \(x=\dfrac{50}{9}\)

c) Ta có: \(\dfrac{4}{9}-\dfrac{5}{3}\cdot x=-2\)

\(\Leftrightarrow\dfrac{5}{3}x=\dfrac{4}{9}+2=\dfrac{22}{9}\)

\(\Leftrightarrow x=\dfrac{22}{9}:\dfrac{5}{3}=\dfrac{22}{9}\cdot\dfrac{3}{5}\)

hay \(x=\dfrac{22}{15}\)

Vậy: \(x=\dfrac{22}{15}\)

d) Ta có: \(\dfrac{5}{7}:x-3=\dfrac{-2}{7}\)

\(\Leftrightarrow\dfrac{5}{7}:x=\dfrac{-2}{7}+3=\dfrac{19}{21}\)

\(\Leftrightarrow x=\dfrac{5}{7}:\dfrac{19}{21}=\dfrac{5}{7}\cdot\dfrac{21}{19}\)

hay \(x=\dfrac{15}{19}\)

Vậy:\(x=\dfrac{15}{19}\)

a) 2x - 5 = -19

2x= -19+5

2x= -14

x= -14:2

x= -7

Vậy...

b) |x + 2| = 17

TH1: x+2= -17

x= -17 -2

x= -19

TH2: x+2=17

x= 17-2

x= 15

Vậy...

c) c)(x + 5).(x - 9) = 0

=> ( x+5) = 0 hoặc ( x-9) =0

Nếu x+5= 0 thì x= 0-5 => x = -5

Nếu x-9 = 0 thì x = 0+9=> x =9

Vậy...

d) 5x -14 = x-34

5x -14 -x = 34

4x-14= -34

4x= -34+14

4x= - 20

x= -20:4

x= -5

Vậy...

a) x = 4

b) x = -8

c) | x | - 9 = -2 + 17

| x | = 15 + 9

| x | = 24

x = 24 hoặc x = -24

d) |x – 9| = -2 + 17

|x – 9| = 15

x – 9 = 15 hoặc x – 9 = -15

x = 24 hoặc x = -6

\(\dfrac{x}{17}+\dfrac{19}{34}=2\dfrac{1}{2}\)

\(\Rightarrow\dfrac{x}{17}+\dfrac{19}{24}=\dfrac{5}{2}\)

\(\Rightarrow\dfrac{x}{17}=\dfrac{33}{17}\Rightarrow x=33\)

a) x + 9 = 2 - 17

x + 9 = - 15

x = -15 – 9

x = -24

Vậy x = -24

b) x - 17 = (-11) . (-5)

x – 17 = 55

x = 17 + 55

x = 72

c)| x – 5 | = (-4)2

| x – 5 | = 16

x – 5 = 16 hoặc x – 5 = -16

x = 21 hoặc x = -11

a)  3x – 15 = 25 – 5x 

=> 3x + 5x = 25 + 15

=> 8x = 40

=> x = 5

 b) 3x - 17 = 2x – 7     

=> 3x - 2x = -7 + 17

=> x = 10

 c) 2x – 17 =  – (3x – 18)

=> 2x - 17 = -3x + 18

=> 2x + 3x = 18 + 17

=> 5x = 35

=> x = 7

d) 3x – 14 = 2(x – 9) + 1

=> 3x - 14 = 2x - 18 + 1

=> 3x - 2x = -18 + 1 + 14

=> x = -3

f) (x – 5)² = 9          

\(\Rightarrow\left[{}\begin{matrix}x-5=3\\x-5=-3\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=8\\x=2\end{matrix}\right.\)

a) Ta có: \(3x-15=25-5x\)

\(\Leftrightarrow3x-15-25+5x=0\)

\(\Leftrightarrow8x-40=0\)

\(\Leftrightarrow8x=40\)

hay x=5

Vậy: x=5

b) Ta có: \(3x-17=2x-7\)

\(\Leftrightarrow3x-17-2x+7=0\)

\(\Leftrightarrow x-10=0\)

hay x=10

Vậy: x=10

c) Ta có: \(2x-17=-\left(3x-18\right)\)

\(\Leftrightarrow2x-17=-3x+18\)

\(\Leftrightarrow2x-17+3x-18=0\)

\(\Leftrightarrow5x-35=0\)

\(\Leftrightarrow5x=35\)

hay x=7

Vậy: x=7

d) Ta có: \(3x-14=2\left(x-9\right)+1\)

\(\Leftrightarrow3x-14=2x-18+1\)

\(\Leftrightarrow3x-14-2x+18-1=0\)

\(\Leftrightarrow x+3=0\)

\(\Leftrightarrow x=-3\)

Vậy: x=-3

f) Ta có: \(\left(x-5\right)^2=9\)

\(\Leftrightarrow\left[{}\begin{matrix}x-5=3\\x-5=-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=8\\x=2\end{matrix}\right.\)

Vậy: \(x\in\left\{2;8\right\}\)

Bài 2. Tìm x, biết :                                

a) \(3x-15=25-5x\)

\(\Leftrightarrow8x=40\)

\(\Leftrightarrow x=5\)

Vậy x = 5

b) \(3x-17=2x-7\)

\(\Leftrightarrow x=10\)

Vậy x = 10

c) \(2x-17=-\left(3x-18\right)\)

\(\Leftrightarrow2x-17=18-3x\)

\(\Leftrightarrow5x=35\)

\(\Leftrightarrow x=7\)

Vậy x = 7

d) \(3x-14=2\left(x-9\right)+1\)

\(\Leftrightarrow3x-14=2x-18+1\)

\(\Leftrightarrow3x-14=2x-17\)

\(\Leftrightarrow x=-3\)

Vậy x = -3

e) \(\left(x-5\right)^2=9\)

\(\Rightarrow\left[{}\begin{matrix}x-5=3\\x-5=-3\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=8\\x=2\end{matrix}\right.\)

Vậy x = {8; 2}

1

a ) 

( 9407 - 7274 ) : y = 8058 : 34 

       2133         : y =    237 

                         y =     2133 : 237 

                        y =      9

b )

y x 128 - y x 17 - y x 11 = 576000

y x ( 128 - 17 - 11 )       = 576000

y x         100                  = 576000

y                                   = 576000 : 100

y                                  = 5760 

2

a )

( 125 x 36 ) : ( 5 x 9 ) =

    4500       :      45    =

         100

b )

1/10 + 2/10 + 3/10 + 4/10 + 5/10 + 6/10 + 7/10 + 8/10 + 9/10=

( 1/10 + 9/10 ) + ( 2/10 + 8/10 ) + ( 3/10 + 7/10 ) + ( 4/10 + 6/ 10 ) + 5/10=

          1            +            1          +            1           +          1             + 0,5 =

                                    4,

Chúc bạn học giỏi nhé !

bài 5:

tìm y:

y + 1 = 123

y = 123 - 1

y = 122