[ ( 6x - 39 ) ;3 ] . 28 = 5628
X x 13 = 39
( x - 15 ) - 75 = 0
6x - 39 = 201
575 - ( 6x +70 ) = 445
X x 13 = 39
X = 39 : 13
X = 3
( x - 15 ) - 75 = 0
x - 15 = 0 + 75
x - 15 = 75
x = 75 + 15
x = 90
6x - 39 = 201
6x = 201 + 39
6x = 240
x = 40
X x 13 = 39
X = 39 : 13
X = 3
( x - 15 ) - 75 = 0
x - 15 = 0 + 75
x - 15 = 75
x = 75 + 15
x = 90
6x - 39 = 201
6x = 201 + 39
6x = 240
x = 240 : 6
x = 40
575 - ( 6x +70 ) = 445
6x + 70 = 575 - 445
6x + 70 = 130
6x = 130 - 70
6x = 60
x = 60 : 6
x = 10
X x 13 = 39
X = 39 : 13
X = 3
( x - 15 ) - 75 = 0
x - 15 = 75
x = 75 - 15
x = 50
6x - 39 = 201
6x = 162
x = 162 : 6
x = 27
575 - ( 6x +70 ) = 445
6x + 70 = 575 - 445
6x + 70 = 130
6x = 60
x = 10
(6x - 39) : 3 = 21
(6x - 39) : 3 = 21
\(\Rightarrow\) 2x - 13 = 21
\(\Rightarrow\) 2x = 34
\(\Rightarrow\) x = 17
Vậy x = 17
\(\left(6x-39\right):3=21\\ 6x-39=63\\ 6x=102\\ x=17\)
(6x- 39).28=5628
(6x-39).28=5628
6x-39=5628:28
6x-39=201
6x=201+39
6x=240
x=40
(6x - 39) = 5628 : 28
6x - 39 = 201
6x = 201 + 39
6x = 240
x = 240 : 6
Vậy x = 40
a, 25xy2 + 15y2
b, 6x(x-y) + 3xy - 3y2
phân tích các đa thức trên thành nhân tử
- '' giúp mik vs mik đang cần gấp''
a: \(=5y^2\left(5x+3\right)\)
b: \(=6x\left(x-y\right)+3y\left(x-y\right)\)
\(=3\left(x-y\right)\left(2x+y\right)\)
\(a,25xy^2+15y^2=5y^2\left(5x+3\right)\\ b,6x\left(x-y\right)+3xy-3y^2=6x\left(x-y\right)+3y\left(x-y\right)=\left(6x+3y\right)\left(x-y\right)=3\left(2x+y\right)\left(x-y\right)\)
a)25xy2+15y2=5y2(5x+3)
b)6x(x-y)+3xy-3y2=6x(x-y)+(3xy-3y2)=6x(x-y)+3y(x-y)=(x-y)(6x+3y)=3(x-y)(2x+y)
(6x-39):3=201
(6x - 39) : 3 = 201
6x - 39 = 201 . 3
6x - 39 = 603
6x = 603 + 39
6x = 642
x = 642 : 6
x = 107
bạn Công chúa nguyễn làm thiếu bước dòi nè!!
((6x - 39( : 7) x 4 = 12
(6x -39) .28= 56.28
( 6x - 39 ) . 28 = 56 . 28
<=>( 6x - 39 ) . 28 = 1568
<=> 6x - 39 = 56
<=> 6x = 95
<=> x = 95 : 6
<=> x = 95/6
(6x -39) .28= 56.28
=>6x -39= 56
=>6x = 56+39=95
=> 6x=95 : 6 =95/6
( 6x - 39 ) . 28 = 56 . 28
6x - 39 = 56 . 28 : 28
6x - 39 = 56
6x = 56 + 39
x = 95 : 6
x = 95/6
(6x- 39) : 3-8x25=1
=> (6x - 39) : 3 - 200 = 1
=> (6x - 39) : 3 = 201
=> 6x - 39 = 603
=> 6x = 642
=> x = 107
[(6x-39) :3]x28=5628
(6x-39):3=5628:28=201
6x-39=201.3=603
6x=603+39=642
x=107
Tìm gì vậy bạn
chứ nói ko làm sao giải được
[(6x-39) :3]=5628:28
[(6x-39) :3]=201
(6x-39)=201x3
(6x-39)=603
6x =603+39
6x =642
x =642:6
x =107
x =