Bài 1 tính hợp lí
a) 2017.;1-2018)+2018.2017+(-1)*2017
b) 7/19 8/11+3/11:19/7-2/-19
c) (6 và 4/9+3 và 7/11)-5 và4/9
Bài 2 tìm x
a) 5/6-x=-5/12-1/-4
b) x-2 trên phần -5=6/7
c) 1/2.x-3/4.x=-5/6
bài 2 : tính hợp lí
a)29,42+20,58-34,23+(-25,77)
b) (-212,49)-(87,51-99,9)
a) \(\left(29,42+20,58\right)-\left(34,23+25,77\right)\)
\(=50-60=-10\)
b) \(-\left(212,49+87,51\right)+99,9\)
\(=-300+99,9=-200,1\)
A)29.42+20.58−34.23+(−25.77)29.42+20.58−34.23+(−25.77)
=29.42+20.58−34.23−25.77
=29.42+20.58−34.23−25.77
=(29.42+20.58)−(34.23+25.77)
=(29.42+20.58)−(34.23+25.77)
=50−60=50−60
=−10=−10
B).(−212.49)−(87.51−99.9)(−212.49)−(87.51−99.9)
=−212.49−87.51+99.9
=−212.49−87.51+99.9
=−(212.49+87.51)+99.9
=−(212.49+87.51)+99.9
=−300+99.9=−300+99.9
=−(300−99.9)=−(300−99.9)
=−200.1
Bài 1:tính hợp lí
a)80-(4x5 mũ 2-3x2 mũ 3)
b)125-2x[56-48:(15-7)]
Xong rùi đó>:)) :D
a) 80-(4x5^2-3x2^3)
= 80-(4x25-3x8)
= 80-(100-24)
= 80-76
= 4
b) 125-2x[56-48:(15-7)]
= 125-2x[56-48:8]
= 125-2x[56-6]
=125-2x50
=125-100
=25.
Bài 3. Thực hiện tính hợp lí
a) 47.36+47.64 b) (−43+1315−126)−(1315+57)
𝑎) 19.35−19.2+67.19 b) (−25+117)+(−117)+25
a, = 47 . ( 36 + 64 )
= 47 . 100 = 4700
b, = -43 + 1315 - 126 - 1315 - 57
= ( - 43 - 57 ) - 126
= - 100 - 126
= -226
c, = 19 . ( 35 - 2 + 67 )
= 19 . 100 = 1900
d, = -25 + 117 - 117 + 25
= 0
Tính hợp lí
a) 1 - 2 + 3 - 4 + 5 - 6 +...+ 2021 - 2022
`1 - 2 + 3 - 4 + 5 - 6 +...+ 2021 - 2022`
`= (1 - 2) + (3 - 4) + (5 - 6) +...+ (2021 - 2022)`
`= (-1) + (-1) + (-1) + ... + (-1) ` [có `2022 : 2 = 1011` nhóm]
`= (-1) xx 1011 = -1011`
1.Tính 1 cách hợp lí
a)3119.121-3119.11.11
b)24.(123+87)+(87+123).76
a) \(3119\cdot121-3119\cdot11\cdot11\\ =3119\left(121-11\cdot11\right)\\ =3119\left(121-121\right)\\ =3119\cdot0=0\)
b) \(24\cdot\left(123+87\right)+\left(87+123\right)\cdot76\\ =\left(123+87\right)\left(24+76\right)\\ =210\cdot100=21000\)
1.Tính 1 cách hợp lí
a, 232-(581+132-331)
b,[12+(-57)] - [-57-(-12)]
a: \(232-\left(581+132-331\right)\)
\(=232-581-132+331\)
\(=\left(232-132\right)+\left(-581+331\right)\)
\(=100-250\)
=-150
b: \(\left[12+\left(-57\right)\right]-\left[-57-\left(-12\right)\right]\)
\(=12+\left(-57\right)+57+\left(-12\right)\)
\(=\left(12-12\right)+\left(57-57\right)\)
=0+0
=0
Bài 1:Tính hợp lí
a)-12,5+17,55-3,5+2,45
b)0,175-(\(2\dfrac{1}{3}\)+0,175)
c)\(\dfrac{5}{13}\).\(\dfrac{-3}{10}\)+\(\dfrac{3}{10}\).\(\dfrac{-8}{13}\)+(-0,7)
Bài 2:Tìm x biết
a)x+\(\dfrac{2}{5}\)=2,4
b)2x-\(\dfrac{4}{5}\)=-1,5
c)11-(15+11)=x-(25-9)
Bài 3:Cho A=\(\dfrac{1}{2^2}\)+\(\dfrac{1}{3^2}\)+\(\dfrac{1}{4^2}\)+\(\dfrac{1}{5^2}\)+....+\(\dfrac{1}{100^2}\)
Chứng tỏ A<1
2:
a: x=2,4-0,4=2
b: =>2x=-1,5+0,8=-0,7
=>x=-0,35
c: =>x-16=-15
=>x=1
Tính hợp lí
a) 1/2 x 1 x 1/3 x 10 x 7/35 x 3/4
\(\dfrac{1}{2}\cdot1\cdot\dfrac{1}{3}\cdot10\cdot\dfrac{7}{35}\cdot\dfrac{3}{4}\)
\(=\dfrac{1}{2}\cdot10\cdot\dfrac{1}{5}\cdot1\cdot\dfrac{1}{3}\cdot\dfrac{3}{4}\)
\(=\dfrac{10}{10}\cdot\dfrac{1}{4}=\dfrac{1}{4}\)
Bài 1:cho giá trị của biểu thức
A= (7-3/4 + 1/3) - (6+ 5/4 - 4/3) - (5-7/4 + 5/3)
hãy tính giá trị biểu thức.
Bài 2:Thực hiện hép tính sau một cách hợp lí
a, 1/3 . -4/5 + 1/3 . -6/5
giúp mình với ạ
2:
a: \(=\dfrac{1}{3}\left(-\dfrac{4}{5}-\dfrac{6}{5}\right)=-\dfrac{1}{3}\cdot2=-\dfrac{2}{3}\)
1:
\(A=7-\dfrac{3}{4}+\dfrac{1}{3}-6-\dfrac{5}{4}+\dfrac{4}{3}-5+\dfrac{7}{4}-\dfrac{5}{3}\)
\(=-4-\dfrac{1}{4}=-\dfrac{17}{4}\)
Bài 1:
\(A=\left(7-\dfrac{3}{4}+\dfrac{1}{3}\right)-\left(6+\dfrac{5}{4}-\dfrac{4}{3}\right)-\left(5-\dfrac{7}{4}+\dfrac{5}{3}\right)\)
\(A=7-\dfrac{3}{4}+\dfrac{1}{3}-6-\dfrac{5}{4}+\dfrac{4}{3}-5+\dfrac{7}{4}-\dfrac{5}{3}\)
\(A=\left(7-6-5\right)-\left(\dfrac{3}{4}+\dfrac{5}{4}-\dfrac{7}{4}\right)+\left(\dfrac{1}{3}+\dfrac{4}{3}-\dfrac{5}{3}\right)\)
\(A=-4-\dfrac{3+5-7}{4}+\dfrac{1+4-5}{3}\)
\(A=-4-\dfrac{1}{4}+\dfrac{0}{3}\)
\(A=-\dfrac{16}{4}-\dfrac{1}{4}+0\)
\(A=\dfrac{-16-1}{4}\)
\(A=-\dfrac{17}{4}\)
Bài 2:
\(\dfrac{1}{3}\cdot-\dfrac{4}{5}+\dfrac{1}{3}\cdot-\dfrac{6}{5}\)
\(=\dfrac{1}{3}\cdot\left(-\dfrac{4}{5}-\dfrac{6}{5}\right)\)
\(=\dfrac{1}{3}\cdot\dfrac{-4-6}{5}\)
\(=\dfrac{1}{3}\cdot\dfrac{-10}{5}\)
\(=\dfrac{1}{3}\cdot-2\)
\(=-\dfrac{2}{3}\)
Bài 2: Tính hợp lí
a) 32.(- 64) – 64.68 b) - 54.76 + 12.(- 76) – 76.(- 36) | c) 8.19 – 42.(- 19) + 38.5 d) 74.(- 41) + 41.24 | e) – 43.38 + 12.(- 43) – 50.(- 43) f) 32 – 42.(- 16) + 48.5 – (- 16) |
a: =-64(32+68)=64x100=-6400
b: =76(-54-12+36)=76x(-30)=-2380
c: =19x50+38x5=950+190=1140