76-[26+(16-2x7)³]

= 76 - [26 + (16-14)³ ]

= 76 - [26+2³ ]

= 76 - [26+8]

= 76 - 26 - 8

= 50 -8

=42

` 3xx 7/10 + 7/10 xx 5 +2 xx 7/10`

`=7/10 xx (3+5+2)`

`= 7/10 xx 10`

`=7`

\(3\times\dfrac{7}{10}+\dfrac{7}{10}\times5+2\times\dfrac{7}{10}=\dfrac{7}{10}\times\left(3+5+2\right)=\dfrac{7}{10}\times10=7\)

7

= 7/10 x ( 3 + 5 + 2 )

=7/10 x 10

= 7

3x7/10+7/10x5+2x7/10

=7/10x(3+5+2)

=7/10x10

=7

(Dấu . là dấu nhân nha e, tại e mới học lớp 4 nên chưa biết)

\(3.\frac{7}{10}+\frac{7}{10}.5+2.\frac{7}{10}=\frac{7}{10}.\left(3+5+2\right)=\frac{7}{10}.10=7\)

\(=\dfrac{7-2}{2.7}+\dfrac{12-7}{7.12}+...+\dfrac{102-97}{97.102}\)

\(=\dfrac{1}{2}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{12}+...+\dfrac{1}{97}-\dfrac{1}{102}\)

\(=\dfrac{1}{2}-\dfrac{1}{102}=\dfrac{25}{51}\)

\(=\dfrac{7-2}{2.7}+\dfrac{12-7}{7.12}+...+\dfrac{97-92}{92.97}\)

\(=\dfrac{1}{2}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{12}+...+\dfrac{1}{92}-\dfrac{1}{97}\)

\(=\dfrac{1}{2}-\dfrac{1}{97}=\dfrac{95}{194}\)

Mình xin được sửa lại vì câu đầu mình nhầm đề bài ạ

\(3\times\dfrac{7}{10}+\dfrac{7}{10}\times5+2\times\dfrac{7}{10}\)

\(=\dfrac{7}{10}\times\left(3+5+2\right)\)

\(=\dfrac{7}{10}\times10=7\)

7

=7/10×(3+5+2)=7/10×(3+5+2)

\(=\dfrac{7}{10}\times\left(3+5+2\right)=7\)

Đáp án của mình là: 7

Giúp với 

Ta có:\(\dfrac{20}{2\times7}+\dfrac{20}{7\times12}+\dfrac{20}{12\times17}+\dfrac{20}{17\times22}+\dfrac{20}{22\times27}+\dfrac{20}{27\times32}\)

 \(=4\times\left(\dfrac{5}{2\times7}+\dfrac{5}{7\times12}+\dfrac{5}{12\times17}+\dfrac{5}{17\times22}+\dfrac{5}{22\times27}+\dfrac{5}{27\times32}\right)\)

    \(=4\times\left(\dfrac{1}{2}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{12}+\dfrac{1}{12}-\dfrac{1}{17}+\dfrac{1}{17}-\dfrac{1}{22}+\dfrac{1}{22}-\dfrac{1}{27}+\dfrac{1}{27}-\dfrac{1}{32}\right)\)

\(=4\times\left(\dfrac{1}{2}-\dfrac{1}{32}\right)=4\times\dfrac{15}{32}=\dfrac{30}{16}\)

\(\dfrac{20}{2\cdot7}+\dfrac{20}{7\cdot12}+\dfrac{20}{12\cdot17}+\dfrac{20}{17\cdot22}+\dfrac{20}{22\cdot27}+\dfrac{20}{27\cdot32}\) ( * là nhân nha )

20 x ( \(\dfrac{1}{2\cdot7}+\dfrac{1}{7\cdot12}+\dfrac{1}{12\cdot17}+\dfrac{1}{17\cdot22}+\dfrac{1}{22\cdot27}+\dfrac{1}{27\cdot32}\) )

20 x ( \(\dfrac{1}{2}+\dfrac{1}{7}-\dfrac{1}{7}+\dfrac{1}{12}-\dfrac{1}{12}+\dfrac{1}{17}-\dfrac{1}{17}+\dfrac{1}{22}-\dfrac{1}{22}+\dfrac{1}{27}-\dfrac{1}{27}+\dfrac{1}{32}\) )

20 x ( \(\dfrac{1}{2}-\dfrac{1}{32}\) ) 

20 x \(\dfrac{15}{32}\) = \(\dfrac{300}{32}=\dfrac{75}{8}\)