ĐỀ : Cho \(M=\dfrac{54.107-53}{53.107-54}\); \(N=\dfrac{135.269-133}{134.269-135}\)
So sánh M vs N
SS A vs B
\(A=\dfrac{54.107-53}{53.107+54}\)
\(B=\dfrac{135.169-133}{134.269+135}\)
\(A=\dfrac{54.107-53}{53.107+54}=\dfrac{53.107+107-53}{53.107+54}=\dfrac{53.107+54}{53.107+54}=1\\ B=\dfrac{135.169-133}{134.269+135}=\dfrac{135.169-133}{134.269+134+1}=\dfrac{135.169-133}{134.270+1}=\dfrac{135.169-133}{268.135+1}< 1\\ Vậy:B< A\left(A=1\right).hay.A>B\)
so sánh A=54.107-53/53.107+54 và B=135.269-133/134.269+135
So sánh
A= 54.107-53/53.107+54
B= 135.269-133/134.269+135
so sánh
A=54.107-53/53.107+54 và B=135.269-133/134.269+135
A<B . K CHO MÌNH NHA
So sánh
G=54.107-53/53.107+54 và H=135.269-133/134.269+135
So sanh phan so:
a)54.107-53/53.107+54=A
B=135.269-133/134.269+135
Ta thấy :
A=\(\frac{54.107-53}{53.107+54}=\frac{53.107+107-53}{53.107+54}=\frac{53.107+54}{53.107+54}=1\)
B=\(\frac{135.269-133}{134.269+135}=\frac{134.269+269-133}{134.269+135}=\frac{134.269+136}{134.269+135}>1\)
Vậy A < B
Không thực hiện phép tinh ở mẫu dùng tính chất để so sánh các phân số sau :
a)A= \(\dfrac{53.71-18}{71.52+53}\) và \(\dfrac{54.107-53}{53.107+54}\)
\(\dfrac{53.71-53}{71.52+18}=\dfrac{53.70}{70.52+52+18}=\dfrac{53.70}{52.70+70}=\dfrac{53.70}{53.70}=1\)
B=\(\dfrac{54.106+54-54}{53.106+53+53}=\dfrac{54.106}{53.106+106}=\dfrac{54.106}{54.106}=1\)
Vì =1 và B=1 nên A=B