muốn rút gọn phân số đó ta làm như sau:

\(\frac{2^3\cdot3}{2^2\cdot3^2\cdot5}\)=\(\frac{2}{3\cdot5}\)=\(\frac{2}{15}\)

\(\dfrac{2^3.3^4}{2^3.3^2.5}=\dfrac{1.3^2}{1.1.5}=\dfrac{9}{5}\)

Ta có :2^3.3^4/2^2.3^2.5=2.3^2/1.1.5=2.9/5=\(\dfrac{18}{5}\)

Ta có:

\(\frac{2^3.3^4}{2^2.3^2.5}=\frac{2.3^2}{5}=\frac{18}{5}\)

\(\frac{2^4.5^2.11^2.7}{2^3.5^3.7^2.11}=\frac{2.11}{5.7}=\frac{22}{35}\)

Ta có:

\(\frac{2^2.2.3^2.3^2}{2^2.3^2.5}\) =\(\frac{2.3^2}{5}\) =\(\frac{18}{5}\)

Vậy

Ta cã: \(\frac{2^3.3^4}{2^2.3^2.5}\)

\(=\frac{2^2.2.3^2.3^2}{2^2.3^2.5}\)

\(=\frac{2.3^2}{5}\)

\(=\frac{18}{5}\)

ta có

a=2^3.3

b=2.3^2.5^2

c=2^2.3^4.5^2a

=>(a,b,c)=2.3=6

vay UCLN(a,b,c)=6

đó là 6

\(=\frac{2.3^2}{5}=\frac{18}{5}\)

\(\frac{2^3.3^4}{2^2.3^2.5}=\frac{2^2.3^2.2.3^2}{2^2.3^2.5}=\frac{2^2.3^2.18}{2^2.3^2.5}=\frac{18}{5}\)

\(\frac{2^3.3}{2^2.3^2.5}=\frac{2^2.2^1.3}{2^2.3.3.5}=\frac{2}{3.5}=\frac{2}{15}\)

\(\frac{2^3.3}{2^2.3^2.5}=\frac{24}{180}=\frac{2}{15}\)

\(\frac{2^3.3^4}{2^2.3^2.5}=\frac{2^2.3^2.2.3^2}{2^2.3^2.5}=\frac{2.3^2}{5}=\frac{18}{5}\)

Giúp mình với

\(\frac{2^3.3^4}{2^2.3^2.5}=\frac{2.3^2}{1.1.5}=\frac{2.9}{5}=\frac{18}{5}\)

\(\frac{\sqrt{2^3\cdot3^4\cdot5^5\cdot6^6\cdot7^7}}{2^2\cdot3^2\cdot5^6\cdot6^3\cdot7^3}=\frac{2\cdot3^2\cdot5^2\cdot6^3\cdot7^3\cdot\sqrt{2\cdot5\cdot7}}{2^2\cdot3^2\cdot5^6\cdot6^3\cdot7^3}=\frac{\sqrt{2\cdot5\cdot7}}{2\cdot5^4}=\frac{\sqrt{70}}{1250}\)