bang 12vi:

2+4+6+8+10+12=42

a;80x-64=160

80x=224

x=14/5

b;x-4=42:6

x-4=7

x=11

c;40-x=16*2

40-x=32

x=8

d;20-x=8:4

20-x=2

x=18

`# \text {Ryo}`

`a)`

`80x - 2^2 . 2^4 = 160`

`\Rightarrow 80x - 2^6 = 160`

`\Rightarrow 80x - 64 = 160`

`\Rightarrow 80x = 224`

`\Rightarrow x = 224 \div 80`

`\Rightarrow x = 2,8`

Vậy, `x = 2,8`

`b)`

`(x - 4).6 = 42`

`\Rightarrow x - 4 = 42 \div 6`

`\Rightarrow x - 4 = 7`

`\Rightarrow x = 7 + 4`

`\Rightarrow x = 11`

Vậy, `x = 11`

`c)`

`(40 - x) \div 2 = 16`

`\Rightarrow 40 - x = 16 . 2`

`\Rightarrow 40 - x = 32`

`\Rightarrow x = 40 - 32`

`\Rightarrow x = 8`

Vậy, `x = 8`

`d)`

`(20 - x) . 4 = 8`

`\Rightarrow 20 - x = 8 \div 4`

`\Rightarrow 20 - x = 2`

`\Rightarrow x = 20 - 2`

`\Rightarrow x = 18`

Vậy, `x = 18.`

cú tuii

lên google nhé

Ủa chứ đây khum phải gg hay gì ba._.

tui lớp 5 mà 

tích em nha

1: x=3/4-1/2=3/4-2/4=1/4

2: x-1/5=2/11

=>x=2/11+1/5=21/55

3: x-5/6=16/42-8/56

=>x-5/6=8/21-4/28=5/21

=>x=5/21+5/6=15/14

4: x/5=5/6-19/30

=>x/5=25/30-19/30=6/30=1/5

=>x=1

5: =>|x|=1/3+1/4=7/12

=>x=7/12 hoặc x=-7/12

6: x=-1/2+3/4

=>x=3/4-1/2=1/4

11: x-(-6/12)=9/48

=>x+1/2=3/16

=>x=3/16-1/2=-5/16

1)x= 1/4

2)x= 2/11+ 1/5

   x= 21/55

3)x - 5/6 = 5/21

   x         = 5/21+5/6

   x         = 15/14

4)x/5 = 5/6 + -19/30

   x:5 = 1/5

   x    = 1/5.5

   x    = 1

5) |x| - 1/4 = 6/18

    |x|           = 6/18 - 1/4

    |x|            =7/12

⇒x= 7/12 hoặc -7/12

6)x = -1/2 +3/4

   x= 1/4

7) x/15 = 3/5 + -2/3

   x:15  = -1/15

  x        = -1/15. 15

  x        = -1

8)11/8 + 13/6 = 85/x  

       85/24      = 85/x

  ⇒      x           = 24

9) x - 7/8 = 13/12

   x          = 13/12 + 7/8

   x          = 47/24

10)x - -6/15 = 4/27  

     x            = 4/27 + (-6/15)

    x             = -34/135

11) -(-6/12)+x = 9/48

                    x= 9/48 - 6/12

                    x = -5/16

12) x - 4/6 = 5/25 + -7/15

      x -4/6  =  -4/15

     x           = -4/15 + 4/6

    x             = 2/5

a) \(\frac{1}{2}+\frac{2}{3}x=\frac{4}{5}\)

\(x=\frac{\left(\frac{4}{5}-\frac{1}{2}\right)}{\frac{2}{3}}\)

\(x=\frac{9}{20}\)

b) \(\left|x+\frac{3}{4}\right|-\frac{1}{2}=0\)

\(\left|x+\frac{3}{4}\right|=0+\frac{1}{2}\)

\(\left|x+\frac{3}{4}\right|=\frac{1}{2}\)

\(\Rightarrow\hept{\begin{cases}x+\frac{3}{4}=\frac{1}{2}\\x+\frac{3}{4}=-\frac{1}{2}\end{cases}\Rightarrow\hept{\begin{cases}x=\frac{-1}{4}\\x=\frac{-5}{4}\end{cases}}}\)

Vậy x=-1/4 hoặc x=-5/4

c) \(\left(x+\frac{1}{3}\right)^3=\frac{-1}{8}\)

\(\Leftrightarrow x+\frac{1}{3}=\frac{-1}{8}=\frac{\left(-1\right)^3}{2^3}=\frac{-1}{2}\)

\(x=\frac{-1}{2}-\frac{1}{3}\)

\(x=\frac{-5}{6}\)

\(\frac{1}{2}+\frac{2}{3}x=\frac{4}{5}\)

\(\frac{2}{3}x=\frac{4}{5}-\frac{1}{2}\)

\(\frac{2}{3}x=\frac{3}{10}\)

\(x=\frac{3}{10}:\frac{2}{3}\)

\(x=\frac{9}{20}\)

b) l x + 3/4 l - 1/2 = 0

    l x + 3/4 l = 1/2

TH1 : \(x+\frac{3}{4}\le0\)                           TH2: \(x+\frac{3}{4}\ge0\)

=> \(x+\frac{3}{4}=-\frac{1}{2}\)                             =>   \(x+\frac{3}{4}=\frac{1}{2}\)

   \(x=-\frac{1}{2}-\frac{3}{4}\)                                            \(x=\frac{1}{2}-\frac{3}{4}\)

       \(x=-\frac{5}{4}\)                                                  \(x=-\frac{1}{4}\)

c) ( x + 1/3 )³ = ( -1/8 )

( x + 1/3 ) ³ = ( -1/3 )³

=> x + 1/3 = -1/3

x = -1/3 - 1/3

x = -2/3

1+40/x=21

40/x=21-1

40/x=20

x=40/20

x=2

a, x=1; y=2 => 12

x=2; y=1 => 21

b, x=1; y=5 => 15

x=5; y=1 => 51

c, x=1; y=6 => 16

x=6;y=1 => 61

x=2; y=3=> 23

x=3; y=2 => 32

d, x=1; y=8 => 18

x=2; y=4 => 24

x=4; y=2 => 42

x=8; y=1 => 81

5, 

x=3; y=4 => 34

x=4; y=3 => 43

x=2; y=6 => 26

x=6; y=2 => 62

1 , 10

2 , 8

3 , 5

4 , 2

5 , 1

6 ,

1/ `|x|=10<=> x=\pm 10`

2/ `|x-8|=0<=>x-8=0<=>x=8`

3/ `7+|x|=12<=>|x|=5<=>x=\pm 5`

4/ `|x+1|=3`

$\Leftrightarrow\left[\begin{array}{1}x+1=3\\x+1=-3\end{array}\right.\\\Leftrightarrow\left[\begin{array}{1}x=3\\x=-4\end{array}\right.$

5/ `15-x=16-(14-42)`

`<=>15-x=16+28`

`<=>15-x=44`

`<=>x=-29`

6/ `210-(x-12)=168`

`<=>210-x+12=168`

`<=>222-x=168`

`<=>x=54`

1.

\(\left|x\right|=10\Leftrightarrow x=\pm10\)

2.

\(\left|x-8\right|=0\Leftrightarrow x-8=0\Leftrightarrow x=8\)

3.

\(7+\left|x\right|=12\Leftrightarrow\left|x\right|=5\Leftrightarrow x=\pm5\)