\(\left(x-1\right)+\left(x-2\right)+....+\left(x-100\right)=4950\)

\(\Leftrightarrow\left(x+x+....+x\right)+\left(1+2+...+100\right)=4950\)

\(\Leftrightarrow100x-\frac{\left(100+1\right)\left[\left(100-1\right):1+1\right]}{2}=4950\)

\(\Leftrightarrow100x-5050=4950\)

\(\Leftrightarrow x=100\)

Vậy ...

100x-(1+2+3+....+100)=4950

100x-5050=4950

100x=10000

x=100

(x - 1) + (x - 2) + (x - 3) + ...+ (x - 100) = 4950 

X x100-(1+2+3+......+100)=4950

X x100-5050=4950

X x100=4950+5050

X x100=10000

x=10000:100

x=100

a, | x+3 | = -27/11 × 22/-9

=> |x + 3| = 6

=> x + 3 = 6 hoặc x + 3 = -6

=> x = 3 hoặc x = -9

vậy_

b, (x-3) × (2x - 7) = 0

=> x - 3 = 0 hoặc 2x - 7 = 0

=> x = 3 hoặc x = 7/2

vậy_

c, (x-1) + (x-2) + (x-3) + ... + (x-100) = 4950

=> x - 1 + x - 2 + x - 3 + ... + x - 100 = 4950

=> 100x - (1 + 2 + 3 + ... + 100) = 4950

=> 100x - (1 + 100).100 : 2 = 4950

=> 100x - 5050 = 4950

=> 100x = 10000

=> x = 10

(X-1)+(X-2)+(X-3)+...+(X-100)=4950

=>(X+X+...+X)-(1+2+3+...+100)=4950

=>100X-[(100+1).100:2]=4950

=>100X-[101.100:2]=4950

=>100X-[10100:2]=4950

=>100X-5050=4950

=>100X=4950+5050

=>100X=10000

=>X=10000:100

=>X=100

\(\left(x-1\right)+\left(x-2\right)+\left(x-3\right)+...+\left(x-100\right)=4950\\ \Leftrightarrow100x-\left(1+2+3+...+100\right)=4950\\ \Leftrightarrow100x-\frac{\left(100+1\right)100}{2}=4950\\ \Leftrightarrow100x-5050=4950\\ \Rightarrow100x=-100\\ \Rightarrow x=-1\)

tìm x biết

( x-1) + ( x-2) + (x-3) +....+ (x-100) = 4950

⇔\(\left(x+x+x+....+x\right)-\left(1+2+3+....+100\right)=4950\)

⇔\(\left(x.100\right)-\left(1+100\right).100:2=4950\)

⇔\(\left(x.100\right)-5050=4950\)

⇔\(100x=4950+5050\)

⇔\(100x=10000\)

⇔ \(x=100\)

ta có  1+5+9+13+...+\(x\)=4950

\(\Rightarrow\) \(\frac{(x+1).x}{2}=4950\)

\(\Rightarrow\) \(x.(x+1)=9900\)

\(\Rightarrow\)\(x=99\)

Vậy x=99

chúc bạn học tốt

nhanh giùm cái

câu nay bạn dung phuong phap

1 + 2 + 3 + .... + x = 4950

=> x(x+1) = 4950.2

=> x(x+1) = 9900

=> x(x+1) = 99.100

=> x = 99

ta có công thức : 1+2+...+n=\(\frac{n\left(n+1\right)}{2}\)

=>1+2+3+..+x=\(\frac{x\left(x+1\right)}{2}\)=4950

<=> (x+1)x=4950.2=9900

<=> x²+x-9900=0

<=> x=99( nhận)

hoặc x=-100 loại

vậy x=99