\(25\sqrt{\dfrac{x-3}{25}}-7\sqrt{\dfrac{4x-12}{9}}-7\sqrt{x^2-9}+18\sqrt{\dfrac{9x^2-81}{81}}=0\left(x\ge3\right)\)

\(=25\sqrt{\dfrac{1}{25}.\left(x-3\right)}-7\sqrt{\dfrac{4}{9}.\left(x-3\right)}-7\sqrt{x^2-9}+18\sqrt{\dfrac{1}{9}.\left(x^2-9\right)}=0\)

\(=5\sqrt{x-3}-\dfrac{14}{3}\sqrt{x-3}-7\sqrt{x^2-9}+6\sqrt{x^2-9}=0\)

\(\Rightarrow\dfrac{1}{3}\sqrt{x-3}-\sqrt{\left(x-3\right)\left(x+3\right)}=0\Rightarrow\sqrt{x-3}-3\sqrt{\left(x-3\right)\left(x+3\right)}=0\)

\(\Rightarrow\sqrt{x-3}\left(1-3\sqrt{x+3}\right)=0\Rightarrow\left[{}\begin{matrix}\sqrt{x-3}=0\\1=3\sqrt{x+3}\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=3\\x=-\dfrac{26}{9}\left(l\right)\end{matrix}\right.\)

Do \(\left|x-\dfrac{2}{3}\right|\ge0;\forall x\)

Mà \(-\dfrac{26}{\sqrt{81}}< 0\)

\(\Rightarrow\) Không tồn tại x để \(\left|x-\dfrac{2}{3}\right|< -\dfrac{26}{\sqrt{81}}\)

Hay ko tồn tại số nguyên x thỏa mãn đề bài

=>\(5\cdot\dfrac{3\sqrt{x-3}}{5}-7\cdot\dfrac{2\sqrt{x-3}}{3}-7\cdot\sqrt{x^2-9}+18\cdot\sqrt{\dfrac{9}{81}\left(x^2-9\right)}=0\)

=>\(3\cdot\sqrt{x-3}-\dfrac{14}{3}\sqrt{x-3}=7\cdot\sqrt{x^2-9}-18\cdot\dfrac{3}{9}\cdot\sqrt{x^2-9}\)

=>\(-\dfrac{5}{3}\sqrt{x-3}=\sqrt{x^2-9}\)

=>\(\sqrt{x-3}\left(\sqrt{x+3}+\dfrac{5}{3}\right)=0\)

=>x-3=0

=>x=3

a: ĐKXĐ: 3x^2+15/-6>=0

=>3x^2+15<=0(vô lý)

b: ĐKXĐ: -81/-x^2-12>=0

=>-x^2-12<0

=>-x^2<12

=>x^2>-12(luôn đúng)

c: ĐKXĐ: 31(x^2+21)/3>=0

=>x^2+21>=0(luôn đúng)

d: ĐKXĐ: -12/x^2+11>=0

=>x^2+11<0(vô lý)

e: ĐKXĐ: 21/-x^2-17>=0

=>-x^2-17>0

=>x^2+17<0(vô lý)

a )   x :   − 7   –  6  =   − 15  x :   − 7   =   − 9 x  =   − 9 . − 7   x  =  63

b ) x :  12  –  12  =   − 37 x :  12  =   − 25 x  =   − 25 . 12 x  = 3 00

c ) x :   − 25   +  81  =  85 x :   − 25   =  4 x  =  4 . − 25 x  = − 1 00

(x + 2) + (x + 5) +(x + 7) +(x + 12) + (x + 19) + (x + 31) + (x + 50) + (x + 81) + (x + 131) = 347

8x+(2+5+7+12+19+31+50+81+131)=347

8x+338=347

8x=9

Vậy =9/8

chúc bạn học tốt ^-^

[ ( 6 . x - 39 ) : 7 ] . 4 = 12

[ ( 6 . x - 39 ) : 7 ] = 12 : 4

( 6 . x - 39 ) : 7 = 3

6 . x - 39 = 3 . 7

a) (x : 3 - 4) . 5 = 15

x : 3 - 4 = 15 : 5

x : 3 - 4 = 3

x : 3 = 3 + 4

x : 3 = 7

x = 7 . 3

x = 21.

6 . x - 39 = 21

6 . x = 21 + 39

6 . x = 60

x = 60 : 6

x = 10

Vậy x = 10

9.3x+1 = 81

= 81

[(6x-39):7].4=12                  (x:3-4).5=15                     9.3x+1=81

 (6x-39):7    =12:4=3            x:3-4    =15:5=3               27x+1=81

  6x-39         =3.7  =21          x:3       =3+4=7                    x+1=81:27=3

  6x              =21+39=60       x          =7.3=21                   x     =3-1=2

    x              =60:6   =10