= ( -25) x 1 +72 x (-25) + (-25) x27

= (- 25) x ( 1 + 72 + 27 )

= (-25) x 100

=-2500 

b 

c 37 x ( 25 + 37 ) - 27 x ( 37 + 25 )

= 37 x 25 + 37 x 37 -27x37 -27x25

= ( 37 x25 -27x25 )+(37x37-27+37)

=25 x ( 37 -27 ) + 37 x (37 - 27)

= 25 x10 + 37x10 

= 250 + 370 

= 770

a) =-25.( 1+72+27)

=-25.100= - 2500

b) = -36.45 + (-36) . 15 - (-36) . 40

= - 36. ( 45+15-40)

= -36 . 20= -720

c) =37.62 - 27 .62

= 62. ( 37 - 27 )

= 62 . 10 

= 620

1) Ta có: \(\left(-86-x\right)-\left(3+2x\right)=-4-15\)

\(\Leftrightarrow-86-x-3-2x+4+15=0\)

\(\Leftrightarrow-3x-70=0\)

\(\Leftrightarrow-3x=70\)

hay \(x=-\dfrac{70}{3}\)

Vậy: \(x=-\dfrac{70}{3}\)

2) Ta có: \(18+\left(-x\right)-\left(40-28\right)=-32-\left(-18\right)\)

\(\Leftrightarrow18-x-40+28+32-18=0\)

\(\Leftrightarrow-x+20=0\)

\(\Leftrightarrow-x=-20\)

hay x=20

Vậy: x=20

3) Ta có: \(-27-\left(-31+x\right)-25=-5-17\)

\(\Leftrightarrow-27+31-x-25+5+17=0\)

\(\Leftrightarrow-x+1=0\)

\(\Leftrightarrow-x=-1\)

hay x=1

Vậy: x=1

4) Ta có: \(-9-14-x+42-38=-5+13\)

\(\Leftrightarrow-x-19=8\)

\(\Leftrightarrow-x=27\)

hay x=-27

Vậy: x=-27

Đề lỗi rồi. Bạn xem lại

a,x-77-(-73)=34

x-77        =34+(-73)

x-77        =-39

x             =(-39)+77

x             =38

b,25-(x+8)-25=46

25-(X+8)       =46-25

25-(x+8)        =21

x+8               =25-21

x+8               =4

x                   =4-8

x                    =-4

A, 2 x 26 x 5 =( 5 x 2) x 26

10 x 26

=260                   

 b,4 x 37 x 25 =( 4 x 25) x 26

= 100 x 26

= 3700           

 c, 25 x 5 x 4 x 27 x 2 =( 25 x 4 ) x ( 2x 5) x 27

= 100 x 10 x 27 

= 1000x 27 

=27000

d,28 x 64 + 28 x 36 = 28 x ( 64 + 36 )

= 28 x 100

=2800

 e, 769 x 85 - 769 x 75  = 769 x ( 85 - 75 )

=769 x 10

=7690

f, 56 x 37 + 56 x 63 = 56 x ( 37 + 63 )

= 56 x 100

=5600

a. = 26 x (2 x 5)

   = 26 x 10 =260

b.=( 25x4) x37

   =100 x37=3700

c.=(25x4) x(5x2) x27

   =100 x10 x27

   = 27000

d.=28 x( 64+36)

   =28 x100

  = 2800

e.=769 x( 85-75)

    =769 x10 =7690

f. =56 x(37 +63)

  =56 x100

= 5600

 1) 9-25=(7-x)-(25+7)

(7-x)-(25+7)=9-25

(7-x)-(25+7)=-16

(7-x)-32=-16

7-x=-16+32

7-x=16

x=7-16

x=-9

2) (27-514) -(486-73)+x=7

 (27-514) -(486-73)+x=7

-487-413+x=7

-1011+x=7

x=7-(-1011)

x=7+1011

x=1018

3) 25+5+37-25+6-29-x=37

 25+5+37-25+6-29-x=37

67-25+6-29-x=37

42+6-29-x=37

48-29-x=37

19-x=37

x=19-37

x=-18

4) 14+(-12)+x =10-/-15/+ /-3/

14+(-12)+x =10-15+3

14+(-12)+x =-5+3

14+(-12)+x =-2

2+x=-2

x=-2-2

x=-4

1) - 9

2) 1018 

3) -18 

4) -4

tick nha

a)x=37

b)x=-28

c)x=-48

d)x=15

a) Ta có: \(\frac{x-91}{37}+\frac{x-86}{42}+\frac{x-78}{50}+\frac{x-49}{79}=4\)

\(\Leftrightarrow\frac{x-91}{37}-1+\frac{x-86}{42}-1+\frac{x-78}{50}-1+\frac{x-49}{79}-1=0\)

\(\Leftrightarrow\frac{x-91-37}{37}+\frac{x-86-42}{42}+\frac{x-78-50}{50}+\frac{x-49-79}{79}=0\)

\(\Leftrightarrow\frac{x-128}{37}+\frac{x-128}{42}+\frac{x-128}{50}+\frac{x-128}{79}=0\)

\(\Leftrightarrow\left(x-128\right)\left(\frac{1}{37}+\frac{1}{42}+\frac{1}{50}+\frac{1}{79}\right)=0\)

Vì \(\frac{1}{37}+\frac{1}{42}+\frac{1}{50}+\frac{1}{79}>0\)

nên x-128=0

hay x=128

Vậy: x=128

b) Ta có: \(\frac{x-29}{1970}+\frac{x-27}{1972}+\frac{x-25}{1974}+\frac{x-23}{1976}+\frac{x-1970}{29}+\frac{x-1972}{27}+\frac{x-1974}{25}+\frac{x-1976}{23}-8=0\)

\(\Leftrightarrow\frac{x-29}{1970}-1+\frac{x-27}{1972}-1+\frac{x-25}{1974}-1+\frac{x-23}{1976}-1+\frac{x-1970}{29}-1+\frac{x-1972}{27}-1+\frac{x-1974}{25}-1+\frac{x-1976}{23}-1=0\)

\(\Leftrightarrow\frac{x-29-1970}{1970}+\frac{x-27-1972}{1972}+\frac{x-25-1974}{1974}+\frac{x-23-1976}{1976}+\frac{x-1970-29}{29}+\frac{x-1972-27}{27}+\frac{x-1974-25}{25}+\frac{x-1976-23}{23}=0\)

\(\Leftrightarrow\left(x-1999\right)\left(\frac{1}{1970}+\frac{1}{1972}+\frac{1}{1974}+\frac{1}{1976}+\frac{1}{29}+\frac{1}{27}+\frac{1}{25}+\frac{1}{23}\right)=0\)

Vì \(\frac{1}{1970}+\frac{1}{1972}+\frac{1}{1974}+\frac{1}{1976}+\frac{1}{29}+\frac{1}{27}+\frac{1}{25}+\frac{1}{23}>0\)

nên x-1999=0

hay x=1999

Vậy: x=1999

a) Ta có \(\frac{x-91}{37}+\frac{x-86}{42}+\frac{x-78}{50}+\frac{x-49}{79}\)=4

<=>\(\frac{x-91}{37}+\frac{x-86}{42}+\frac{x-78}{50}+\frac{x-49}{79}-4=0\)

<=>\(\frac{x-91}{37}-1+\frac{x-86}{42}-1+\frac{x-78}{50}-1+\frac{x-49}{79}-1=0\)

<=>\(\frac{x-128}{37}+\frac{x-128}{42}+\frac{x-128}{50}+\frac{x-128}{79}=0\)

<=>(x-128)\(\left(\frac{1}{37}+\frac{1}{42}+\frac{1}{50}+\frac{1}{79}\right)=0\)

Vì \(\frac{1}{37}+\frac{1}{42}+\frac{1}{50}+\frac{1}{79}>0\)=>x-128=0<=>x=128

b)Tương tự

<=>x-128=0

<=>x=128

Chú ý \(\frac{1}{37}+\frac{1}{42}+\frac{1}{50}+\frac{1}{79}\)>0

b)tương tự