=32.233+67.233+68.233

=233.(68+32+67)

=233.167

=38911

hok tốt k nhé bạn

\(32\times\left(233+67\right)+68\times233\)

=\(32\times233+67\times233+68\times233\)

=\(233\left(32+67+68\right)\)

=\(233\times167\)

=\(38911\)

#hoctot

\(32\cdot\left(233+67\right)+68\cdot233\)

\(=32\cdot233+67\cdot32+68\cdot233\)

\(=233\cdot\left(32+68\right)+67\cdot32\)

\(=23300+2144\)

\(=25444\)

9765 nha bạn Thu

k mik nha

2: \(=\left(\dfrac{-4}{9}-\dfrac{1}{9}-\dfrac{5}{9}\right)+\left(\dfrac{5}{8}+\dfrac{3}{8}\right)+\dfrac{1}{5}=\dfrac{1}{5}-\dfrac{1}{9}=\dfrac{4}{45}\)

4: \(=\dfrac{3}{11}\cdot\dfrac{1}{3}\cdot\dfrac{121}{15}=\dfrac{11}{15}\)

6: \(=\dfrac{6}{7}\left(\dfrac{8}{13}+\dfrac{9}{13}-\dfrac{3}{13}\right)=\dfrac{6}{7}\cdot\dfrac{16}{13}=\dfrac{96}{91}\)

8: \(=\dfrac{9}{25}\cdot\dfrac{-53}{3}-\dfrac{9}{25}\cdot\dfrac{22}{3}=\dfrac{9}{25}\cdot\left(-25\right)=-9\)

= 4,12 x 0,1 + 3,28 x 0,1 + 2,6 x 0,1 

= 0,1 x ( 4,12 + 3,28 + 2,6)

= 0,1 x 10 

= 1

\(4,12\times0,1+3,28\times\dfrac{1}{10}+2,6\times0,1\)

\(=4,12\times0,1+3,28\times0,1+2,6\times0,1\)

\(=(4,12+3,28+2,6)\times0,1\)

\(=10\times0,1=1\)

= 4,12 x 0,1 + 3,28 x 0,1 + 2,6 x 0,1 

= 0,1 x ( 4,12 + 3,28 + 2,6)

= 0,1 x 10 

= 1

9x24+25=9x24+24.1+1

=24x(9+1)+1

=24x10+1

=240+1=241

9x24 + 25 

= 9 x 24 +24 x 1 + 1 

= 24 x ( 9 + 1) + 1

= 24 x 10 + 1

= 240 + 1 = 241

425 x 32 + 69 x 425 - 425

= 425 x 32 + 69 x 425 - 425 x 1

= 425 x (32+69-1)

= 425 x 100

=  42500

`#3107`

\(\text{32684+41325+316+675}\\ =\left(32684+316\right)+\left(41325+675\right)\\=33000+42000\\ =75000\)

nhóm 32634+316 và 41325+675 nhe 

(32684+316)+(41325+675)

\(33\times77+66\times77+77\)

\(=77\times\left(33+66+1\right)\)

\(=77\times100\)

\(=7700\)

c) \(\dfrac{1}{15}+\dfrac{1}{35}+\dfrac{1}{63}+\dfrac{1}{99}+\dfrac{1}{143}=\dfrac{1}{2}\left(\dfrac{2}{3.5}+\dfrac{2}{5.7}+\dfrac{2}{7.9}+\dfrac{2}{9.11}+\dfrac{2}{11.13}\right)\)

\(=\dfrac{1}{2}\left(\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+...+\dfrac{1}{11}-\dfrac{1}{13}\right)=\dfrac{1}{2}\left(\dfrac{1}{3}-\dfrac{1}{13}\right)=\dfrac{1}{2}.\dfrac{10}{39}=\dfrac{5}{39}\)

e) \(\dfrac{1}{5}.\dfrac{4}{7}+\dfrac{3}{7}.\dfrac{1}{5}-\dfrac{1}{5}=\dfrac{1}{5}\left(\dfrac{4}{7}+\dfrac{3}{7}\right)-\dfrac{1}{5}=\dfrac{1}{5}.1-\dfrac{1}{5}=0\)