a) m = 5555/6666 -246246/369369 + 222222/151515 =
b) A= [ 1+1/2] x [1+1/3] x [1+1/4] x .......... x [1+1/99] =
A, M=5555 \6666 -246246\369369+ 222222\151515
\(M=\frac{5555}{6666}-\frac{246246}{369369}+\frac{222222}{151515}\)
\(M=\frac{5}{6}-\frac{2}{3}+\frac{22}{15}\)
\(M=\frac{49}{30}\)
M=\(\frac{5555}{6666}\)- \(\frac{246246}{369369}\)+ \(\frac{222222}{151515}\)=
\(M=\frac{5555}{6666}-\frac{246246}{369369}+\frac{222222}{151515}=\frac{5}{6}-\frac{2}{3}+\frac{22}{15}=\frac{25}{30}-\frac{20}{30}+\frac{44}{30}=\frac{49}{30}\)
\(\frac{5555}{6666}\)= \(\frac{5}{6}\)
\(\frac{246246}{369369}\)= \(\frac{82}{123}\)
\(\frac{222222}{151515}\)= \(\frac{22}{15}\)
M= \(\frac{5}{6}\)+ \(\frac{82}{123}\)+ \(\frac{22}{15}\)
M= \(\frac{1025}{1230}\)+ \(\frac{820}{1230}\)+ \(\frac{6724}{1230}\)
M= \(\frac{1845}{1230}\)+ \(\frac{6724}{1230}\)
M= \(\frac{8569}{1230}\)
tk nhé
Mình giải thích nhé :\(\frac{5555}{6666}=\frac{5555:1111}{6666:1111}=\frac{5}{6};\frac{246246}{369369}=\frac{246246:123123}{369369:123123}=\frac{2}{3};\frac{222222}{151515}=\frac{222222:10101}{151515:10101}=\frac{22}{15}\)
Đoạn sau là quy đồng phân số rồi cộng lại thôi!
Bài 1: Các số sau là số nguyên tố hay hợp số
a = 1 x 3 x 5 x 7 x ... x 13 + 20
b = 147 x 247 x 347 - 13
c = 13579 + 97531 + 12345
d = 246246 + 122123 + 369369
Bài 2: Tìm số nguyên tố để 5.a + 14 là số nguyên tố < 40
Bài 2:
\(\Leftrightarrow5a+14\in\left\{2;3;5;7;11;13;17;19;23;29;31;37\right\}\)
\(\Leftrightarrow5a\in\left\{5;15\right\}\)
hay a=3(vì a là số nguyên tố)
Tính bằng cách thuận tiện nhất:
A,,1/2 x 3/4 + 1/4 x 1/2
B,A=1212/2121 x 151515/161616
\(A=\frac{1}{2}×\frac{3}{4}+\frac{1}{4}×\frac{1}{2}\)
\(A=\frac{1}{2}×\left(\frac{3}{4}+\frac{1}{4}\right)\)
\(A=\frac{1}{2}×\left(\frac{3+1}{4}\right)\)
\(A=\frac{1}{2}×1\)
\(A=\frac{1}{2}\)
\(B=\frac{1212}{2121}×\frac{151515}{161616}\)
\(B=\frac{1212:101}{2121:101}×\frac{151515:10101}{161616:10101}\)
\(B=\frac{12}{21}×\frac{15}{16}\)
\(B=\frac{12×15}{21×16}\)
\(B=\frac{3×4×3×5}{3×7×4×4}\)
\(B=\frac{15}{28}\)
a)\(\frac{1}{2}:\frac{1}{5}+\frac{1}{3}:\frac{1}{5}+\frac{1}{6}:\frac{1}{5}\)
=\(\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{6}\right):\frac{1}{5}\)
=\(1:\frac{1}{5}\)
=5
b)\(\frac{1515\text{×}161616}{151515\text{×}1616}\)
=1
A=(1+1/2).(1+1/3).(1+1/4)...(1×1/2009)
B=(1-1/2).(1-1/3)...(1-1/100)
B= 1/2.2/3.3/4...99/100
X+1/99+x+2/98+x+3/97+x+4/96
\(A=\frac{3}{2}.\frac{4}{3}.\frac{5}{4}........\frac{2010}{2009}=\frac{3.4.5...2010}{2.3.4....2009}=\frac{2010}{2}=1005\)
\(B=\frac{1.2.3......99}{1.2.3.4.....100}=\frac{1}{100}\)
Câu 2:
Tìm x thuộc Z, biết:
a) x : (9 1/2-3/2)= 0,4+2/9-2/11 phần 1,6+8/9-8/11
b) 1.2+2.3+3.4+...+99.100/x^2 +(x^2+1)+ ...+(x^2 +99)= 6666/131
Giúp mình với nhoa! Thanks mn!!
Bài 1 : Tìm x và y biết :
a, ( x + 1 ) x ( y - 2 ) = 2
b, ( y + 1 ) x ( x x y - 1 ) = 3
c, y0y04 + 40y0y + y040y = 222222
a) Thực hiện phép tính
( 1 - 1/2 ) x ( 1 - 1/3 ) x ( 1 - 1/4 ) x ( 1 - 1/5 ) x ... x ( 1 - 1/99 )
b) Tìm X biết
( X +1/2 ) + ( X +1/6 ) + ( X +1/12 ) + ( X +1/20 ) + ... + ( X +1/90 ) = 99/10