Tính:
a)9^15x25^43/27^10x5^85
b)2^5x49^2/4^3x7^3
thuận tiện 19/20x2/100+19/20x2/100
75/76x102/100-75/76x2/100
3x7/10+7/10x5+2x7/10
giá trị biểu thức
2/5+2/3x3/4
1/2x1/3-1/8
(1/2+1/3):3/9
19/20x2/100+19/20x2/100
= [19/20+19/20]x2/100
= 38/20x2/100
= 19/500
75/76x102/100-75/76x2/100
= [102/100-2/100]x75/76
= 1x75/76
= 75/76
3x7/10+7/10x5+2x7/10
= [3+5+2]x7/10
= 10x7/10
= 7
giá trị biểu thức
2/5+2/3x3/4
= 2/5+1/6
= 17/30
1/2x1/3-1/8
= 1/6-1/8
= 1/24
[1/2+1/3]:3/9
= 5/6:3/9
= 5/2
nhớ tick cho tớ nhé
3x7/10+7/10x5+2x14/20
`3 xx 7/10 + 7/10 xx 5 + 2 xx 14/20`
`= 3 xx 7/10 + 7/10 xx 5 + 2 xx 7/10`
`= (3+5+2) xx 7/10`
`= 10 xx 7/10`
`= 70/10`
`=7`
tính bằng cách thuận tiện nhất:
3x7/10+7/10x5+2x7/10
` 3xx 7/10 + 7/10 xx 5 +2 xx 7/10`
`=7/10 xx (3+5+2)`
`= 7/10 xx 10`
`=7`
\(3\times\dfrac{7}{10}+\dfrac{7}{10}\times5+2\times\dfrac{7}{10}=\dfrac{7}{10}\times\left(3+5+2\right)=\dfrac{7}{10}\times10=7\)
3x7/10+7/10x5+2x7/10 ( tính bằng cách thuận tiện)
(Dấu . là dấu nhân nha e, tại e mới học lớp 4 nên chưa biết)
\(3.\frac{7}{10}+\frac{7}{10}.5+2.\frac{7}{10}=\frac{7}{10}.\left(3+5+2\right)=\frac{7}{10}.10=7\)
tính bằng cách thuận tiện 3x7/10+7/10x5+2x7/10
\(=\dfrac{7}{10}\times\left(3+5+2\right)=7\)
Đáp án của mình là: 7
4^10x8^15 = ?
4^15x5^30 =?
27^16: 9^10 =?
72^3x 54^2 / 108^4 = ?
3^10x11+3^10x5 / 3^9x2^4 =?
2^10x13+ 2^10x65 / 2^8 x 104 =?
Cac ban giup minh nha
b.8/3-x=9/10x5/3 c.x:5/9=2-11/8 d.Xx2/3+Xx7/3=11/4
b,8/3-x=9/10x5/3=3/2
=>x=8/3-3/2=7/6
c,x:5/9=2-11/8=5/8
=>x=5/8x5/9=25/72
d,x\(\cdot\)2/3+x\(\cdot\)7/3=11/4
=>x(2/3+7/3)=11/4
=>x=11/4:(2/3+7/3)=11/4:10/3=33/40.
\(b,\dfrac{8}{3}-x=\dfrac{9}{10}\times\dfrac{5}{3}\\ \Leftrightarrow x=\dfrac{7}{6}\)
\(c,x:\dfrac{5}{9}=2-\dfrac{11}{8}\\ \Leftrightarrow x=\dfrac{25}{72}\)
\(d,x\times\dfrac{2}{3}+x\times\dfrac{7}{3}=\dfrac{11}{4}\\ \Leftrightarrow3x=\dfrac{11}{4}\\ \Leftrightarrow x=\dfrac{11}{12}\)
Tính:
a) \(\dfrac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}\)
b) T=\(\dfrac{5^{16}.27^7}{125^5.9^{11}}\)
a: \(=\dfrac{2^{10}\cdot3^8-2^{10}\cdot3^9}{2^{10}\cdot3^8+2^{10}\cdot3^8\cdot5}=\dfrac{2^{10}\cdot3^8\left(1-3\right)}{2^{10}\cdot3^8\left(1+5\right)}=\dfrac{-2}{6}=\dfrac{-1}{3}\)
b: \(=\dfrac{5^{16}\cdot3^{21}}{5^{15}\cdot3^{22}}=\dfrac{5}{3}\)
Rút gọn rồi tính:
a) \(\dfrac{2}{5}-\dfrac{3}{15}\) b) \(\dfrac{9}{27}-\dfrac{2}{9}\) c) \(\dfrac{18}{24}-\dfrac{4}{8}\) d) \(\dfrac{6}{16}-\dfrac{10}{64}\)
a) \(\dfrac{2}{5}-\dfrac{3}{15}\)
\(=\dfrac{2}{5}-\dfrac{3:3}{15:3}\)
\(=\dfrac{2}{5}-\dfrac{1}{5}\)
\(=\dfrac{1}{5}\)
b) \(\dfrac{9}{27}-\dfrac{2}{9}\)
\(=\dfrac{9:3}{27:3}-\dfrac{2}{9}\)
\(=\dfrac{3}{9}-\dfrac{2}{9}\)
\(=\dfrac{1}{9}\)
c) \(\dfrac{18}{24}-\dfrac{4}{8}\)
\(=\dfrac{18:6}{24:6}-\dfrac{4:2}{8:2}\)
\(=\dfrac{3}{4}-\dfrac{2}{4}\)
\(=\dfrac{1}{4}\)
d) \(\dfrac{6}{16}-\dfrac{10}{64}\)
\(=\dfrac{6\times2}{16\times2}-\dfrac{10:2}{64:2}\)
\(=\dfrac{12}{32}-\dfrac{5}{32}\)
\(=\dfrac{7}{32}\)