\(\frac{\left(456\cdot11+912\right)\cdot37}{1374}\)
Những câu hỏi liên quan
Tính hợp lý:
a) \(\frac{158\cdot168-168\cdot58}{110}\)
b) \(\frac{\left(456\cdot11+912\right)\cdot37}{13\cdot74}\)
c) \(\frac{864\cdot48-432\cdot96}{864\cdot48\cdot432}\)
a) \(\frac{158\cdot168-168\cdot58}{110}\)
\(=\frac{\left(158-58\right)\cdot168}{110}\)
\(=\frac{100\cdot168}{110}=\frac{16800}{110}=\frac{1680}{11}\)
b) \(\frac{\left(456.11+912\right)\cdot37}{13\cdot74}\)
\(=\frac{456\cdot11+456\cdot2\cdot37}{13\cdot37\cdot2}\)
\(=\frac{456\cdot\left(11+2\right)\cdot37}{\left(13\cdot2\right)\cdot37}\)
\(=\frac{456\cdot13\cdot37}{26\cdot37}=228\)
c) \(\frac{864\cdot48-432\cdot96}{864\cdot48\cdot432}\)
\(=\frac{432\cdot2\cdot48-432\cdot48\cdot2}{432\cdot2\cdot48\cdot432}=0\)
Đúng 0
Bình luận (3)
\(\frac{158\times168-168\times58}{110}=\frac{168\times\left(158-58\right)}{110}=\frac{168\times100}{110}=\frac{1680}{11}\)
\(\frac{\left(456\times11+912\right)\times37}{13\times74}=\frac{456\times\left(11+2\right)}{13\times2}=\frac{228\times13}{13}=228\)
\(\frac{864\times48-432\times96}{864\times48\times432}=\frac{864\times\left(48-48\right)}{864\times48\times432}=\frac{864\times0}{864\times48\times432}=0\)
Đúng 0
Bình luận (0)
a) \(\frac{158.168-168.58}{110}\)
\(=\frac{168\left(158-58\right)}{110}\)
\(=\frac{16800}{100}\)
\(=168\)
b) \(\frac{\left(456.11+912\right).37}{13.74}\)
\(=\frac{\left(5016+912\right).37}{13.74}\)
\(=\frac{5928.37}{962}\)
\(=\frac{219336}{962}\)
\(=228\)
c) \(\frac{864.48-432.96}{864.48.432}\)
mình đang tìm cách
Đúng 0
Bình luận (0)
\(\frac{\frac{2}{3}+3\left(\frac{2}{3}\right)^3-\left(\frac{5}{6}\right)^2}{\frac{7}{60}:\left(\frac{35}{31\cdot37}+\frac{35}{37\cdot43}+\frac{105}{43\cdot61}+\frac{35}{61\cdot67}\right)}\)
Giúp mình đi ai giúp đầu tặng 1 like
CMR:Với mọi số tự nhiên n \(\ne\)0 ta đều có:
a.\(\frac{1}{2\cdot5}+\frac{1}{5\cdot8}+\frac{1}{8\cdot11}+...+\frac{1}{\left(3n-1\right)\cdot\left(3n+2\right)}=\frac{n}{6n+4}\)
b.\(\frac{5}{3\cdot7}+\frac{5}{7\cdot11}+\frac{5}{11\cdot15}+...+\frac{5}{\left(4n-1\right)\cdot\left(4n+3\right)}=\frac{5n}{4n+3}\)
a)\(VT=\frac{1}{2\cdot5}+\frac{1}{5\cdot8}+...+\frac{1}{\left(3n-1\right)\left(3n+2\right)}\)
\(=\frac{1}{3}\left[\frac{3}{2\cdot5}+\frac{3}{5\cdot8}+...+\frac{3}{\left(3n-1\right)\left(3n+2\right)}\right]\)
\(=\frac{1}{3}\left[\frac{1}{2}-\frac{1}{5}+\frac{1}{5}-\frac{1}{8}+...+\frac{1}{3n-1}-\frac{1}{3n+2}\right]\)
\(=\frac{1}{3}\left[\frac{1}{2}-\frac{1}{3n+2}\right]=\frac{1}{3}\left[\frac{3n+2}{2\left(3n+2\right)}-\frac{2}{2\left(3n+2\right)}\right]\)
\(=\frac{1}{3}\cdot\frac{3n}{6n+4}=\frac{n}{6n+4}=VP\)
Đúng 0
Bình luận (0)
b) Ta có: \(\frac{5}{3.7}+\frac{5}{7.11}+...+\frac{5}{\left(4n-1\right)\left(4n+3\right)}\)
\(=\frac{5}{4}\left(\frac{4}{3.7}+\frac{4}{7.11}+...+\frac{4}{\left(4n-1\right)\left(4n+3\right)}\right)\)
\(=\frac{5}{4}\left(\frac{1}{3}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+...+\frac{1}{4n-1}-\frac{1}{4n+3}\right)\)
\(=\frac{5}{4}\left(\frac{1}{3}-\frac{1}{4n+3}\right)\)
\(=\frac{5}{4}\left(\frac{4n+3}{12n+9}-\frac{3}{12n+9}\right)\)
\(=\frac{5}{4}.\frac{4n}{12n+9}\)
\(=\frac{5n}{12n+9}\)
( sai đề )
Đúng 0
Bình luận (0)
Trường THCS Lý Tự TrọngĐề thi khảo sát chọn lớp dành cho học sinh thi vào lớp 6 môn toánBài 1 : Tính ( tính nhanh nếu có thể )a) 1001 x 789 + 456 x 128 - 789 + 912 x 436b) left(2016cdot2017+2017cdot2018right)cdotleft(1+frac{1}{2}:1frac{1}{2}-1frac{1}{3}right)c) 5frac{9}{10}:frac{3}{2}-left(2frac{1}{3}cdot4frac{1}{2}-2cdot2frac{1}{3}right):frac{7}{4}
Đọc tiếp
Trường THCS Lý Tự Trọng
Đề thi khảo sát chọn lớp dành cho học sinh thi vào lớp 6 môn toán
Bài 1 : Tính ( tính nhanh nếu có thể )
a) 1001 x 789 + 456 x 128 - 789 + 912 x 436
b) \(\left(2016\cdot2017+2017\cdot2018\right)\cdot\left(1+\frac{1}{2}:1\frac{1}{2}-1\frac{1}{3}\right)\)
c) \(5\frac{9}{10}:\frac{3}{2}-\left(2\frac{1}{3}\cdot4\frac{1}{2}-2\cdot2\frac{1}{3}\right):\frac{7}{4}\)
b)\(\left(2016.1017+2017.2018\right).\left(1+\frac{1}{2}:\frac{3}{2}-\frac{4}{3}\right)\)
\(\left(2016.2017+2017.2018\right)\left(1+\frac{1}{3}-\frac{4}{3}\right)\)
\(\left(2016.2017+2017.2018\right).\left(\frac{4}{3}-\frac{4}{3}\right)\)
\(\left(2016.2017+2017.2018\right).0\)
\(=0\)
Đúng 0
Bình luận (0)
a) \(1001.789+456.128.128-789+912.436\)
\(=\left(1001.789-789\right)+\left(456.2.64.128+912.436\right)\)
\(=789.1000+912.4\left(2048+109\right)\)
\(=789000+912.4.2157\)
\(=8657736\)
Đúng 0
Bình luận (0)
c)\(5\frac{9}{10}+\frac{3}{2}-\left(2\frac{1}{3}.4\frac{1}{2}-2.2\frac{1}{3}\right):\frac{7}{4}\)
\(=\frac{59}{10}+\frac{3}{2}-\left(\frac{7}{3}.\frac{9}{2}-2.\frac{7}{3}\right):\frac{7}{4}\)
\(=\frac{59}{10}+\frac{3}{2}-\left[\frac{7}{3}\left(\frac{9}{2}-2\right)\right]:\frac{7}{4}\)
\(=\frac{59}{10}+\frac{3}{2}-\left(\frac{7}{3}.\frac{5}{2}\right):\frac{7}{4}\)
\(=59+\frac{3}{2}-\frac{35}{6}.\frac{4}{7}\)
\(=\frac{59}{10}+\frac{3}{2}-\frac{10}{3}\)
\(=\frac{177+45-100}{30}=\frac{122}{30}=\frac{61}{15}\)
Đúng 0
Bình luận (0)
\(S=\frac{1}{2\cdot5}+\frac{1}{5\cdot8}+\frac{1}{8\cdot11}+...+\frac{1}{\left(3n-1\right)\left(3n+2\right)}\) giúp em tìm công thức với ạ
\(3S=3\left(\frac{1}{2.5}+....+\frac{1}{\left(3n+1\right)\left(3n+2\right)}\right)\)
Đến đây thì bạn làm như dạng đơn giản nhé
Đúng 0
Bình luận (0)
Tình A=\(\frac{\left(4\cdot7+2\right)\left(6\cdot9+2\right)\left(8\cdot11+2\right)...\left(100\cdot103\right)}{\left(5\cdot8+2\right)\left(7\cdot10+2\right)\left(9\cdot12+2\right)...\left(99\cdot102+2\right)}\)
Tính\(\frac{\left(4\cdot7+2\right)\left(6\cdot9+2\right)\left(8\cdot11+2\right)..........\left(100\cdot103+2\right)}{\left(5\cdot8+2\right)\left(7\cdot10+2\right)\left(9\cdot12+2\right)..........\left(99\cdot102+2\right)}\)
\(\frac{\left(456x11+912\right)x37}{13x74}\)
\(\frac{\left(456.11+912\right)37}{13.74}\)
= \(\frac{5928.37}{13.74}\)
= 228
Đúng 0
Bình luận (0)
\(\frac{\left(456.11+912\right).37}{13.74}\)
\(=\frac{\left[456.\left(11+2\right)\right].37}{13.2.37}\)
\(=\frac{456.13}{13.2}\)
\(=228\)
Đúng 0
Bình luận (0)
Xem thêm câu trả lời
Tính nhanh:
\(\frac{10}{11}:\left(\frac{2}{3\cdot5}+\frac{2}{5\cdot7}+\frac{2}{7\cdot9}+\frac{2}{9\cdot11}\right)\)
\(\frac{10}{11}:\left(\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}\right)\)
\(=\frac{10}{11}:\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}\right)\)
\(=\frac{10}{11}:\left(\frac{1}{3}-\frac{1}{11}\right)\)
\(=\frac{10}{11}:\frac{8}{33}=\frac{10}{11}.\frac{33}{8}\)
\(=\frac{15}{4}\)
Trả lời:
\(\frac{10}{11}\div\left(\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}\right)\)
\(=\frac{10}{11}\div\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}\right)\)
\(=\frac{10}{11}\div\left(\frac{1}{3}-\frac{1}{11}\right)\)
\(=\frac{10}{11}\div\frac{8}{33}\)
\(=\frac{10}{11}\times\frac{33}{8}\)
\(=\frac{15}{4}\)
\(\frac{10}{11}:(\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11})\)
=\(\frac{10}{11}:(\frac{2}{3}-\frac{2}{5}+\frac{2}{5}-\frac{2}{7}+\frac{2}{7}-\frac{2}{9}+\frac{2}{9}-\frac{2}{11})\)
=\(\frac{10}{11}:(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11})\)
=\(\frac{10}{11}:(\frac{1}{3}-\frac{1}{11})\)
=\(\frac{10}{11}:\frac{8}{33}\)
= \(\frac{10}{11}.\frac{33}{8}\)= \(\frac{15}{4}\)