tim x biet
(2x=1)^2 - 4(x=2)^2=9
3(x-1)^2 -3x(x-5)=1
3(x+2)^2+ (2x-1)^2 =7
7(x+3)(x-3)=36
Những câu hỏi liên quan
bai1.tim x biet:
a,(x+2).(x+3)-(x-2).(x+5)=0
b,(2x+3).(x-4)+(x-5).(x-2)=(3x-5).(x-4)
c,(8x-3).(3x+2)-(4x+7).(x+4)=(2x+1).(5x-1)=33
,(8x-3).(3x+2)-(4x+7).(x+4)=(2x+1).(5x-1)-33 đúng không bạn
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Rút gọn :
1. (2x-5)(3x+1)-(x-3)^2+(2x+5)^2-(3x+1)^3
2. (2x-1)(2x+1)-3x-2)(2x+3)-(x-1)^3+(2x+3)^3
3. (x-2)(x^2+2x+4)-(3x-2)^3+(3x-4)^2
4. (7x-1)(8x+2)-(2x-7)^2-(x-4)^3-(3x+1)^3
5. (5x-1)(5x+1)-(x+3)(x^2-3x+9)-(2x+4)^2-(3x-4)^2+(2x-5)^3
6. (4x-1)(x+2)-(2x+5)^2-(3x-7)^2+(2x+3)^3=(3x-1)^3
1: \(=6x^2+2x-15x-5-x^2+6x-9+4x^2+20x+25-27x^3-27x^2-9x-1\)
=-27x^3-18x^2+4x+10
2: =4x^2-1-6x^2-9x+4x+6-x^3+3x^2-3x+1+8x^3+36x^2+54x+27
=7x^3+37x^2+46x+33
5:
\(=25x^2-1-x^3-27-4x^2-16x-16-9x^2+24x-16+\left(2x-5\right)^3\)
\(=8x^3-60x^2+150-125+12x^2-x^3+8x-60\)
=7x^3-48x^2+8x-35
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Tim xthuoc Z biet:
1,|2x-5|-|2x+9|=0
2,|x+1|-|x+2|-|3-x|=7
3,|2x+3|+|3x+2|-|4-x|=10
giup mik voi tim x biet
1, 5-(3x+6)>-2x+1
2, -7.(x+2)-3x<6-11x
3, (x+1).(x+2)-x.(x+3)<4-x
4, 6-2x>17+(4-x)
tim x , biet :
1 ) 2017 - \ x - 2017 \ = x
2) -1/2 . ( 3x - 1 ) + 3/4 . ( 3-2x) = -3 . ( x/2 - 1 ) - ( 4/5) mu -1
tim x bieta/(3x-5)(2x-1)-(x+2)(6x-1)0b/ (3x-5)(3x+2)-(3x-1)2-5c/(3x+2)(x-5)3(x-1)2-2d/ (x+1)2/3 - (x-2)2/2 2x+1/2 (x-3)2/6g/49x2(3x+2)2h/(3x-4)2-(2x-2)2-3(x-2)(2x-1)0i/ (x-2)(x2-2x+4)-x(x2+2)15k/ 6x2-7x-30m/(x+5)(x-3)+x2-250e/ x3+3x24x+12f/ (6x+7)2(3x+4)(x+1)6
Đọc tiếp
tim x biet
a/(3x-5)(2x-1)-(x+2)(6x-1)=0
b/ (3x-5)(3x+2)-(3x-1)2=-5
c/(3x+2)(x-5)=3(x-1)2-2
d/ (x+1)2/3 - (x-2)2/2 = 2x+1/2 (x-3)2/6
g/49x2=(3x+2)2
h/(3x-4)2-(2x-2)2-3(x-2)(2x-1)=0
i/ (x-2)(x2-2x+4)-x(x2+2)=15
k/ 6x2-7x-3=0
m/(x+5)(x-3)+x2-25=0
e/ x3+3x2=4x+12
f/ (6x+7)2(3x+4)(x+1)=6
Giải phương trình
1) 5(x - 3) - 4 2(x - 1)
2) 5(x - 3) - 2(x - 5) x-2
3) 3(x - 2) - 14x 2(3-) + 1
4) (x + 1)²+ 2x x(x + 1) + 6
5) 3 - 4x(3 - 2x) 8x² + x - 30
6) x²-x(5 - x) 8
7) (x - 1)² - 36 0
8) (3x - 1)(4x - 3) + 2x(6x - 1) 2(2x + 7)
9) (x - 2)² + 4(x - 3) (x² + x - 3)
10) (x - 2)² – 2(x + 1) (x - 1)(x - 2)
11) (x - 2)² + 3(x - 5) x² + 3x - 3
12)(x - 3)² + (x + 3)² 2 (x² +9)
13) (3x - 1)2 + (3x +1)² 2(9x² + 4) + 1
14) (x - 1)(x - 2) + (2x + 1) 5x²
Đọc tiếp
Giải phương trình
1) 5(x - 3) - 4 = 2(x - 1)
2) 5(x - 3) - 2(x - 5) = x-2
3) 3(x - 2) - 14x = 2(3-) + 1
4) (x + 1)²+ 2x = x(x + 1) + 6
5) 3 - 4x(3 - 2x) = 8x² + x - 30
6) x²-x(5 - x) = 8
7) (x - 1)² - 36 = 0
8) (3x - 1)(4x - 3) + 2x(6x - 1) = 2(2x + 7)
9) (x - 2)² + 4(x - 3) =(x² + x - 3)
10) (x - 2)² – 2(x + 1) = (x - 1)(x - 2)
11) (x - 2)² + 3(x - 5) = x² + 3x - 3
12)(x - 3)² + (x + 3)² = 2 (x² +9)
13) (3x - 1)2 + (3x +1)² = 2(9x² + 4) + 1
14) (x - 1)(x - 2) + (2x + 1) = 5x²
Dễ thế mà bạn không tự làm ak
Tim x, biet:
a) (-5)-(x+5)=3-(2x-5)
b)2(x-3)-3(x-2)=3(x+1)-5(x-2)
C)4(1-2x)=(-3)-3(2+3x)
Giải ngay nhé, chiều mình đi học rồi.
a. 2/3x-1/2=1/10
b. 39/7:x=13
c. (14/5x-50):2/3=51
d. (x+1/2)(2/3-2x)=0
e. 2/3x-1/2x=5/12
g. (x.44/7+3/7)11/5-3/7=-2
h. x.13/4+(-7/6)x-5/3=5/12
i.93/17:x+(-4/17):x+22/7:52/3=4/11
j. 17/2-|2x-3/4|=-7/4
k. (x+1/5)^2+17/25=26/25
l. -32/27-(3x-7/9)^3=-24/27
a) \(\dfrac{2}{3}x-\dfrac{1}{2}=\dfrac{1}{10}\)
\(\dfrac{2}{3}x=\dfrac{1}{10}+\dfrac{1}{2}=\dfrac{3}{5}\)
\(x=\dfrac{3}{5}:\dfrac{2}{3}=\dfrac{9}{10}\)
b) \(\dfrac{39}{7}:x=13\)
\(x=\dfrac{\dfrac{39}{7}}{13}=\dfrac{3}{7}\)
c) \(\left(\dfrac{14}{5}x-50\right):\dfrac{2}{3}=51\)
\(\dfrac{14}{5}x-50=51\cdot\dfrac{2}{3}=34\)
\(\dfrac{14}{5}x=34+50=84\)
\(x=\dfrac{84}{\dfrac{14}{5}}=30\)
d) \(\left(x+\dfrac{1}{2}\right)\left(\dfrac{2}{3}-2x\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{2}=0\\\dfrac{2}{3}-2x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{2}\\x=\dfrac{1}{3}\end{matrix}\right.\)
e) \(\dfrac{2}{3}x-\dfrac{1}{2}x=\dfrac{5}{12}\)
\(\dfrac{1}{6}x=\dfrac{5}{12}\)
\(x=\dfrac{5}{12}:\dfrac{1}{6}=\dfrac{5}{2}\)
g) \(\left(x\cdot\dfrac{44}{7}+\dfrac{3}{7}\right)\dfrac{11}{5}-\dfrac{3}{7}=-2\)
\(\left(x\cdot\dfrac{44}{7}+\dfrac{3}{7}\right)\cdot\dfrac{11}{5}=-2+\dfrac{3}{7}=-\dfrac{11}{7}\)
\(x\cdot\dfrac{44}{7}+\dfrac{3}{7}=-\dfrac{11}{7}:\dfrac{11}{5}=-\dfrac{5}{7}\)
\(\dfrac{44}{7}x=-\dfrac{5}{7}-\dfrac{3}{7}=-\dfrac{8}{7}\)
\(x=-\dfrac{8}{7}:\dfrac{44}{7}=-\dfrac{2}{11}\)
h) \(\dfrac{13}{4}x+\left(-\dfrac{7}{6}\right)x-\dfrac{5}{3}=\dfrac{5}{12}\)
\(\dfrac{25}{12}x-\dfrac{5}{3}=\dfrac{5}{12}\)
\(\dfrac{25}{12}x=\dfrac{5}{12}+\dfrac{5}{3}=\dfrac{25}{12}\)
\(x=1\)
Mỏi tay woa bn làm nốt nha!!
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