\(a,\dfrac{4}{x}=\dfrac{8}{x+1}\left(x\ne0;x\ne-1\right)\Rightarrow4x+4=8x\\ \Rightarrow x=1\\ b,\dfrac{x}{7}=\dfrac{x+16}{35}\Rightarrow35x=7x+112\\ \Rightarrow28x=112\Rightarrow x=4\\ c,\dfrac{6}{x-3}=\dfrac{7}{x-5}\left(x\ne3;x\ne5\right)\Rightarrow6x-30=7x-21\\ \Rightarrow x=-9\\ d,\dfrac{44-x}{3}=\dfrac{x-12}{5}\Rightarrow220-5x=3x-36\\ \Rightarrow8x=256\Rightarrow x=32\)

a) 2/7 : x = 11/6 : 7/12

2/7 : x = 22/7

x = 2/7 : 22/7

x = 1/11

b) (2 - x)/3 = -3/(x - 2)

(2 - x)(x - 2) = -3.3

-(x - 2)² = -9

(x - 2)² = 9

x - 2 = 3 hoặc x - 2 = -3

*) x - 2 = 3

x = 3 + 2

x = 5

*) x - 2 = -3

x = -3 + 2

x = -1

Vậy x = -1; x = 5

c) (x - 1)/(x + 2) = 2/3

3(x - 1) = 2(x + 2)

3x - 3 = 2x + 4

3x - 2x = 4 + 3

x = 7

a) 2/7 : x = 11/6 : 7/12

2/7 : x = 22/7

x = 2/7 : 22/7

x = 1/11

b) (2 - x)/3 = -3/(x - 2)

(2 - x)(x - 2) = -3.3

-(x - 2)² = -9

(x - 2)² = 9

x - 2 = 3 hoặc x - 2 = -3

*) x - 2 = 3

x = 3 + 2

x = 5

*) x - 2 = -3

x = -3 + 2

x = -1

Vậy x = -1; x = 5

c) (x - 1)/(x + 2) = 2/3

3(x - 1) = 2(x + 2)

3x - 3 = 2x + 4

3x - 2x = 4 + 3

x = 7

a) \(\left(\frac{1}{3}.x\right):\frac{2}{3}=\frac{7}{4}:\frac{2}{5}\)

\(\left(\frac{1}{3}.x\right):\frac{2}{3}=\frac{35}{8}\)

\(\Rightarrow\frac{1}{3}.x=\frac{35}{8}.\frac{2}{3}\)

\(\Rightarrow\frac{1}{3}.x=\frac{35}{12}\)

\(\Rightarrow x=\frac{35}{12}:\frac{1}{3}\)

\(\Rightarrow x=\frac{35}{4}\)

Vậy \(x=\frac{35}{4}\)

a) x= \(\frac{35}{4}\)

\(a.\left(\frac{1}{3}.x\right):\frac{2}{3}=\frac{7}{4}:\frac{2}{5}\)

    \(\left(\frac{1}{3}.x\right):\frac{2}{3}=\frac{35}{8}\)

          \(\left(\frac{1}{3}.x\right)=\frac{35}{8}.\frac{2}{3}\)

          \(\left(\frac{1}{3}.x\right)=\frac{35}{12}\)

                    \(x=\frac{35}{12}:\frac{1}{3}\)

                    \(x=\frac{35}{4}\)

\(b.4,5:0,3=2,25:\left(0,1.x\right)\)

\(\Rightarrow2,25:\left(0,1.x\right)=4,5:0,3\)

     \(2,25:\left(0,1.x\right)=15\)

     \(2,25:\left(0,1.x\right)=2,25:15\)

                \(\left(0,1.x\right)=0,15\)

                          \(x=0,15:0,1\)

                          \(x=1,5\)

\(c.8:\left(\frac{1}{4}.x\right)=2:0,02\)

   \(8:\left(\frac{1}{4}.x\right)=100\)

        \(\left(\frac{1}{4}.x\right)=8:100\)

        \(\left(\frac{1}{4}.x\right)=\frac{2}{25}\)

                  \(x=\frac{2}{25}:\frac{1}{4}\)

                  \(x=\frac{8}{25}\)

\(d.3:\frac{9}{4}=\frac{3}{4}:\left(6.x\right)\)

\(\Rightarrow\frac{3}{4}:\left(6.x\right)=3:\frac{9}{4}\)

     \(\frac{3}{4}:\left(6.x\right)=\frac{4}{3}\)

           \(\left(6.x\right)=\frac{3}{4}:\frac{4}{3}\)

          \(\left(6.x\right)=\frac{9}{16}\)

                \(x=\frac{9}{16}:6\)

                \(x=\frac{3}{32}\)

 ^...^ ^_^

thiên tài cũng phát ngất

1: Ta có: \(P=\dfrac{x-\sqrt{x}}{x-9}+\dfrac{1}{\sqrt{x}+3}-\dfrac{1}{\sqrt{x}-3}\)

\(=\dfrac{x-\sqrt{x}+\sqrt{x}-3-\sqrt{x}-3}{\left(\sqrt{x}+3\right)\left(\sqrt{x}-3\right)}\)

\(=\dfrac{x-\sqrt{x}-6}{\left(\sqrt{x}+3\right)\left(\sqrt{x}-3\right)}\)

\(=\dfrac{\left(\sqrt{x}-3\right)\left(\sqrt{x}+2\right)}{\left(\sqrt{x}-3\right)\left(\sqrt{x}+3\right)}\)

\(=\dfrac{\sqrt{x}+2}{\sqrt{x}+3}\)

2)

a) Thay \(x=\dfrac{9}{4}\) vào P, ta được:

\(P=\left(\dfrac{3}{2}+2\right):\left(\dfrac{3}{2}+3\right)=\dfrac{7}{2}:\dfrac{11}{2}=\dfrac{7}{11}\)

b) Ta có: \(x=\sqrt{27+10\sqrt{2}}-\sqrt{18+8\sqrt{2}}\)

\(=5+\sqrt{2}-4-\sqrt{2}\)

=1

Thay x=1 vào P, ta được:

\(P=\dfrac{1+2}{1+3}=\dfrac{3}{4}\)

bạn ghi rõ đề câu b ra đi ạ

a)\(\dfrac{x}{27}=-\dfrac{2}{3,6}\)

\(\Rightarrow\)\(3,6x=27.(-2)\)

\(\Leftrightarrow\)\(3,6x=54\)

\(x=-15\)

(x-1)(x-2)(x²+2)=0

⇒⎡⎢⎣x−1=0x−2=0x2+2=0⇒[x−1=0x−2=0x2+2=0

⇒⎡⎢⎣x=1x=2x2+2≥2>0(loai)⇒[x=1x=2x2+2≥2>0(loai)

Vậy....