a ) 11 ; b ) − 5 7 ; c ) 5 4 + − 1 2 + − 7 8 = − 1 8 ;

d ) − 5 6 + 3 4 + − 13 15 = − 59 20 ; e ) − 6 7 + − 4 5 + ( − 1 ) = − 93 35 ; f ) 21 10

a, ta có 1 - 47/57 = 10/57

             1 - 66/76 = 10/76

vì 10/57>10/76 nên 47/57<66/67

b, ta có 1- 23/32 =9/32

             1-39/48 =9/48

vì 9/32 > 9/48 nên 23/32<39/48

a) \(5\sqrt{48}-4\sqrt{27}-2\sqrt{57}+\sqrt{108}\)

\(=20\sqrt{3}-12\sqrt{3}-2\sqrt{57}+6\sqrt{3}\)

\(=\left(20-12+6\right)\sqrt{3}-2\sqrt{57}\)

\(=14\sqrt{3}-2\sqrt{57}\)

b) \(2\sqrt{24}-2\sqrt{54}+3\sqrt{6}-\sqrt{150}\)

\(=4\sqrt{6}-6\sqrt{6}+3\sqrt{6}-5\sqrt{6}\)

\(=\left(4-6+3-5\right)\sqrt{6}\)

\(=-4\sqrt{6}\)

Trung bình cộng của 76 và 128 là 102

Trung bình cộng của 35; 48 và 49 là 44

(76+128):2=102

\(a.\dfrac{5}{10}=\dfrac{1}{2}=\dfrac{1\times3}{2\times3}=\dfrac{3}{6}\)

\(\dfrac{25}{75}=\dfrac{1}{3}=\dfrac{1\times2}{3\times2}=\dfrac{2}{6}\)

\(b.\dfrac{42}{56}=\dfrac{3}{4}=\dfrac{3\times2}{4\times2}=\dfrac{6}{8}\)

\(\dfrac{18}{48}=\dfrac{3}{8}\)

\(c.\dfrac{27}{81}=\dfrac{1}{3}=\dfrac{1\times4}{3\times4}=\dfrac{4}{12}\)

\(\dfrac{57}{76}=\dfrac{3}{4}=\dfrac{3\times3}{4\times3}=\dfrac{9}{12}\)

\(\dfrac{35}{84}=\dfrac{5}{12}\)

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a.3/6 va 2/6     b.24/32 va12/32  c.912/2736  2052/2736 1140/2736 

C

c

C

C

c

c