Bai 5 :
a, \(\left(-\frac{5}{6}\right)^6.\left(\frac{6}{5}\right)^8\)
b, \(\left(-\frac{13}{8}\right)^3.\left(-\frac{32}{13}\right)^4\)
c, \(\left(-0,1\right)^7.\left(-10\right)^{13}\)
TÍNH:
a. \(\frac{\left(\frac{1}{9}\right)^6.\left(\frac{3}{8}\right)^7}{\left(\frac{1}{3}\right)^{13}.\left(\frac{1}{2}\right)^{22}.3^6}\)
b. \(\frac{5^{-6}.\left(\frac{1}{2}\right)^{13}}{\left(\frac{1}{5}\right)^7.\left(\frac{1}{8}\right)^4}\)
Giúp mik vs các bạn nha!!!
a, \(\frac{\left(\frac{1}{9}\right)^6\cdot\left(\frac{3}{8}\right)^7}{\left(\frac{1}{3}\right)^{13}\cdot\left(\frac{1}{2}\right)^{22}.3^6}\)
\(=\frac{\left(\frac{1}{\left(3^2\right)^6}\right)\cdot\left(\frac{1}{2}\cdot\frac{1}{2}\cdot\frac{1}{2}\cdot3\right)^7}{\left(\frac{1}{3}\right)^{13}.\left(\frac{1}{2}\right)^{22}.3^6}=\frac{\frac{1}{3^{12}}\cdot\left(\frac{1}{2}\right)^{21}\cdot3^7}{\frac{1}{3^{13}}\cdot\left(\frac{1}{2}\right)^{22}.3^6}\)
\(=\frac{3}{\frac{1}{3}\cdot\frac{1}{2}}=3\div\frac{1}{6}=3.6=18\)
b, Làm tương tự nha bn
a, \(\left(7+\frac{7}{5}-\frac{2}{3}\right)-\left(4+\frac{4}{5}+\frac{3}{8}\right)+\left(3-\frac{3}{5}+\frac{2}{3}+\frac{3}{8}\right)\)
b.\(-\frac{13}{25}.\frac{5}{32}.\left(\frac{25}{-13}\right).\left(-64\right)\)
c.\(\frac{7}{80}:\left(-1\frac{3}{4}\right)-\frac{2}{9}:\left(8-\frac{8}{3}\right)-\left(-\frac{5}{24}\right)\left(-\frac{10}{3}+2\frac{8}{15}\right)\)
a,\(\frac{-1}{24}-\left[\frac{1}{4}-\left(\frac{1}{2}-\frac{7}{8}\right)\right]\)
b,\(\left[\frac{5}{7}-\frac{7}{5}\right]-\left[\frac{1}{2}-\left(\frac{-2}{7}-\frac{1}{10}\right)\right]\)
c,\(\left(\frac{-1}{2}\right)-\left(\frac{-3}{5}\right)+\left(\frac{-1}{9}\right)+\frac{1}{71}-\left(\frac{-2}{7}\right)+\frac{4}{35}-\frac{7}{8}\)
d,\(\left(3-\frac{1}{4}+\frac{2}{3}\right)-\left(5-\frac{1}{3}-\frac{6}{5}\right)-\left(6-\frac{7}{4}+\frac{3}{2}\right)\)
e,\(\left(\frac{1}{2}-\frac{13}{14}\right):\frac{5}{7}-\left(\frac{-2}{21}+\frac{1}{7}\right):\frac{5}{7}\)
g,\(\frac{4}{9}:\left(\frac{-1}{7}\right)+6\frac{5}{9}:\left(\frac{-1}{7}\right)\)
a)\(\left(1-\frac{2}{5}\right)^2+\left|\frac{-3}{5}\right|+\frac{-7}{10}\)
b)\(\frac{6^{15}.9^{10}}{3^{34}.2^{13}}\)
c)\(\frac{\left(-5\right)^{32}.20^{43}}{\left(-8\right)^{29}.125^{25}}\)
Tính :
a, \(\left(\dfrac{-5}{6}\right)^6.\left(\dfrac{6}{5}\right)^8\)
b, \(\left(-\dfrac{13}{8}\right)^3.\left(-\dfrac{32}{13}\right)^4\)
c, \(\left(-0,1\right)^7.\left(-10\right)^{13}\)
a: \(\left(\dfrac{5}{6}\right)^6\cdot\left(\dfrac{6}{5}\right)^6\cdot\left(\dfrac{6}{5}\right)^2=\left(\dfrac{5}{6}\cdot\dfrac{6}{5}\right)^6\cdot\dfrac{36}{25}=\dfrac{36}{25}\)
b: \(=-\left(\dfrac{13}{8}\right)^3\cdot\left(\dfrac{32}{13}\right)^3\cdot\dfrac{32}{13}\)
\(=-\left(\dfrac{13}{8}\cdot\dfrac{32}{13}\right)^3\cdot\dfrac{32}{13}=-4^3\cdot\dfrac{32}{13}=\dfrac{-2048}{13}\)
c: \(=\left(0.1\right)^7\cdot10^{13}=\left(0.1\cdot10\right)^7\cdot10^6=10^6\)
A = \(\frac{\frac{3}{4}-\frac{3}{11}+\frac{3}{13}}{\frac{5}{4}-\frac{5}{11}+\frac{5}{13}}+\frac{\frac{1}{2}-\frac{1}{3}+\frac{1}{4}}{\frac{5}{4}-\frac{5}{6}+\frac{5}{8}}\)
B = \(\frac{2^{12}.3^5-4^6.9^2}{\left(2^2.3\right)^6+8^4.3^5}-\frac{5^{10}.7^3-25^5.49}{\left(125.7\right)^3+5^9.14^3}\)
C = \(\frac{\left(a^{2016}+b^{2016}\right)^{2017}}{\left(c^{2016}+d^{2016}\right)^{2017}}\)= \(\frac{\left(a^{2017}-b^{2017}\right)^{2016}}{\left(c^{2017}-d^{2017}\right)^{2016}}\)
A = \(\frac{\frac{3}{4}-\frac{3}{11}+\frac{3}{13}}{\frac{5}{4}-\frac{5}{11}+\frac{5}{13}}+\frac{\frac{1}{2}-\frac{1}{3}+\frac{1}{4}}{\frac{5}{4}-\frac{5}{6}+\frac{5}{8}}\)
\(=\frac{3.\left(\frac{1}{4}-\frac{1}{11}+\frac{1}{13}\right)}{5.\left(\frac{1}{4}-\frac{1}{11}+\frac{1}{13}\right)}+\frac{\frac{1}{2}-\frac{1}{3}+\frac{1}{4}}{\frac{5}{2}.\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{4}\right)}\)
\(=\frac{3}{5}+\frac{1}{\frac{5}{2}}\)
\(=\frac{3}{5}+\frac{2}{5}=1\)
b) B = \(\frac{2^{12}.3^5-4^6.9^2}{\left(2^2.3\right)^6.8^4.3^5}-\frac{5^{10}.7^3:25^5.49}{\left(125.7\right)^3+5^9.14^3}\)
\(=\frac{2^{12}.3^5-\left(2^2\right)^6.\left(3^2\right)^2}{2^{12}.3^6+\left(2^3\right)^4.3^5}-\frac{5^{10}.7^3-\left(5^2\right)^5.7^2}{\left(5^3\right)^3.7^3+5^9.\left(7.2\right)^3}\)
\(=\frac{2^{12}.3^5-2^{12}.3^4}{2^{12}.3^6+2^{12}.3^5}-\frac{5^{10}.7^3-5^{10}-7^2}{5^9.7^3+5^9.7^3.2^3}\)
\(=\frac{2^{12}.3^4.\left(3-1\right)}{2^{12}.3^5\left(3+1\right)}-\frac{5^{10}.7^2.\left(7-1\right)}{5^9.7^3\left(1+2^3\right)}\)
\(=\frac{1}{3.2}-\frac{5.2}{7.3}\)
\(=\frac{7}{3.2.7}-\frac{5.2.2}{7.3.2}\)
\(=\frac{7}{42}-\frac{20}{42}\)
\(=-\frac{13}{42}\)
cs ng làm đung r
đag định lm
So sánh \(A\) và \(B\) , biết rằng:
\(A=\sqrt[13]{12\times\left(11-\frac{\frac{\left(10\times8\right)^{\left(9+8\right)}}{8}+\frac{6^7\times6-6}{6}}{\frac{5}{4}}\right)\div3+2}\)
\(B=\sqrt[13]{12\div\left(11+\frac{\frac{\left(10\times8\right)^{\left(9-8\right)}}{8}+\frac{6^7\times6+6}{6}}{\frac{5}{4}}\right)\times3-2}\)
a) \(\frac{2}{5}+\left(-\frac{4}{3}\right)+\left(-\frac{1}{2}\right)\)
b) \(\frac{5}{8}-\left(-\frac{2}{5}-\frac{3}{10}\right)\)
c) \(\frac{1}{3}-\left[\left(-\frac{5}{4}\right)-\left(\frac{1}{4}+\frac{3}{8}\right)\right]\)
d) \(\frac{2}{3}-4.\left(\frac{1}{2}+\frac{3}{4}\right)\)
e) \(\left(-\frac{1}{3}+\frac{5}{6}\right).11-7\)
f) \(\left(-\frac{5}{9}\right).\frac{3}{11}+\left(-\frac{13}{18}\right).\frac{3}{11}\)
tính\(\left[\frac{\left(4,6+5.6,25\right).14}{4.0,125+2,3}:\frac{17}{6}\right]:\frac{27.9\frac{3}{5}}{12,4+4\frac{2}{5}}+\left(4\frac{5}{8}-\frac{13}{6}:8\frac{2}{3}\right):\left(3,25:2\frac{1}{4}\right)\)
\(=\dfrac{35.85\cdot14}{0.5+2.3}\cdot\dfrac{6}{17}\cdot\dfrac{16.8}{259,2}-\left(4.625-\dfrac{13}{6}:\dfrac{26}{3}\right):\left(3.25:2.25\right)\)
\(=\dfrac{1673}{408}-\dfrac{315}{104}=\dfrac{1421}{1326}\)