2144

= 32 x (67 + 2 - 2 )  = 32 x 67 = 2144

32 x 67 + 32 x 2 - 32 x 2 

= 32 x (67+2-2)

=32 x 67

=2144

                                             Bài giải

a, \(81+243+19=\left(81+19\right)+243=100+243=343\)

b, \(2\text{ x }25\text{ x }2\text{ x }16\text{ x }4=25\text{ x }4\text{ x }2\text{ x }2\text{ x }16=25\text{ x }8\text{ x }32=200\text{ x }32=6400\)

c, \(32\text{ x }47+32\text{ x }54-32=32\text{ x }\left(47+54-1\right)=32\text{ x }100=3200\)

a,81+19+243

=100+243

b,(2x25)x2x(16x4)

=50x2x64

=100x64

=6400

c,32x47+32x54-32x1

=32x(47+54-1)

=32x100

=3200

a,\(81+243+19=\left(81+19\right)+243\)

                                \(=100+243=343\)

b,\(2\times25\times2\times16\times4=\left(25\times4\right)\times\left(2\times2\times16\right)\)

                                          \(=100\times64=6400\)

c,\(32\times47+32\times54-32=32\times47+32\times54-32\)

                                                  \(=\left(47+54-1\right)\times32\)

                                                  \(=3200\)

x/32=2/x

=xx=32.2

=2x=64

x=64:2

x=32

chúc bạn học tốt

\(\frac{x}{32}=\frac{2}{x}\)

NHÂN CHÉO CHO NHAU TA CÓ:

\(x.x=32.2\)

\(\Leftrightarrow x^2=64\)

\(\Leftrightarrow x^2=8^2\)

\(\Leftrightarrow x=8\)

BẠN KIA LÀM SAI RỒI X.X MÀ BẰNG 2X CÓ PHẢI X+X ĐÂU

ờ nhở mk nhầm h ms nhận ra

sorry bn

32 . ( 2 . x9) = 32

         2 . x9 = 32 : 32

          2 . x9 = 1

                x9 = 1:2

                  x9= 1/2

                  x  = 1/2 : 9

                  x=     1/18

dấu chấm là nhân nha

l-ike đi

a) 32 : 4 : 2 = 8 : 2 = 4 

     32 : 4 : 2 = 32 : 2 = 16 

b) 18 : 2 x 3 = 18 : 6 = 3

     18 : 2 x 3 = 9 x 3 = 18

a) 27 x (-17) + 17 x 127

= 27 x (-17) - 17 x (-127)

= -17 x (27-127)

= -17 x -100 = 1700

b) 2 x (1 +32) - 2 x 32

= 2 x (1 + 32 - 32)

= 2 x 1 = 2

\(\dfrac{1}{1-x}+\dfrac{1}{1+x}+\dfrac{2}{1+x^2}+\dfrac{4}{1+x^4}+\dfrac{8}{1+x^8}+\dfrac{16}{1+x^{16}}\)

\(=\dfrac{1+x+1-x}{1-x^2}+\dfrac{2}{1+x^2}+\dfrac{4}{1+x^4}+\dfrac{8}{1+x^8}+\dfrac{16}{1+x^{16}}\)

\(=\dfrac{2+2x^2+2-2x^2}{1-x^4}+\dfrac{4}{1+x^4}+\dfrac{8}{1+x^8}+\dfrac{16}{1+x^{16}}\)

\(=\dfrac{4+4x^4+4-4x^4}{1-x^8}+\dfrac{8}{1+x^8}+\dfrac{16}{1+x^{16}}\)

\(=\dfrac{8+8x^8+8-8x^8}{1-x^{16}}+\dfrac{16}{1+x^{16}}\)

\(=\dfrac{16+16x^{16}+16-16x^{16}}{1-x^{32}}=\dfrac{32}{1-x^{32}}\)

2x + 32 = 32

2x = 0

x = 0

Chọn A

A nha

\(a,\left(x-36\right):\left(2\cdot3^2\right)=2^3\cdot3\\ \Leftrightarrow x-36=432\\ x=468\\ b,2^x=32\\ \Leftrightarrow x=5\\ \Leftrightarrow x^3=27\\ \Leftrightarrow x^3=3^3\\ \Leftrightarrow x=3\\ d,1579+\left(625-x\right)=2023\\ \Leftrightarrow x=1579+625-2023\\ \Leftrightarrow x=181\)

A. \(\left(x-36\right):\left(2.3^2\right)=2^3.3\)

\(\left(x-36\right):\left(2.9\right)=8.3\)

\(\left(x-36\right):18=24\)

\(x-36=24.18\)

\(x-36=432\)

\(x=432+36\)

\(x=468\)

B. \(2^x=32\)

\(2^x=2^5\)

\(x=5\)

C. \(x^3=27\)

\(x^3=3^3\)

\(x=3\)

D. \(1579+\left(625-x\right)=2023\)

\(625-x=2023-1579\)

\(625-x=444\)

\(x=625-444\)

\(x=181\)

a) \(\left(x-36\right)\div\left(2\times3^2\right)=2^3\times3\)

\(\left(x-36\right)\div\left(2\times9\right)=8\times3\)

\(\left(x-36\right)\div18=24\)

\(x-36=432\)

\(x=468\)

b) \(2^x=32\)

\(2^x=2^5\)

\(x=5\)

c) \(x^3=27\)

\(x^3=3^3\)

\(x=3\)

d) \(1579+\left(625-x\right)=2023\)

\(\left(625-x\right)=2023-1579\)

\(625-x=444\)

\(x=625-444\)

\(x=181\)