Ta có:\(\frac{22}{33}\)=\(\frac{2}{3}\)=\(\frac{12}{18}\)

Do18<19=>\(\frac{12}{19}\)<\(\frac{12}{18}\)

Vậy\(\frac{12}{19}\)<\(\frac{22}{33}\)

bạn tự quy đồng nên rồi so sánh nha

Ta có :22/33=2/3

So sánh : 12/19 và 2/3

Ta có :12/19 giữ nguyên ; 2/3=12/18

vì 12/19<12/18 nên 12/19<22/33

\(\frac{3}{5}>\frac{1}{5}\) 

\(\frac{9}{10}< \frac{11}{10}\)

\(\frac{13}{17}< \frac{15}{17}\)

\(\frac{25}{19}\)>\(\frac{22}{19}\)

3/5 > 1/5

9/10 < 11/10

13/17 < 15/17

25/19 > 22/19

T i c k cho mình nhé bạn!

bn k đi

Ta có : \(A=\frac{19^{30}+15}{19^{31}+15}\)

\(\Rightarrow19A=\frac{19^{31}+285}{19^{31}+15}=\frac{19^{31}+15+270}{19^{31}+15}=1+\frac{270}{19^{31}+15}\)

Lại có \(B=\frac{19^{31}+15}{19^{32}+15}\)

\(\Rightarrow19B=\frac{19^{32}+285}{19^{32}+15}=\frac{19^{32}+15+270}{19^{32}+15}=1+\frac{270}{19^{32}+15}\)

Vì \(\frac{270}{19^{32}+15}< \frac{270}{19^{31}+15}\Rightarrow1+\frac{270}{19^{32}+5}< 1+\frac{270}{19^{31}+15}\Rightarrow19B< 19A\Rightarrow B< A\)

1D 2C 3B 5B 6B

7C 8D 10D 12B 16B

17A 19C 20B 21C 22A

1.D

2.C

3. B 

5. B

6. B

7. C

8. D

9. B

10. D

12. B

16. B

17. A

18. B

19. C

20. B

21. C

22. A

#)Giải :

\(A=\frac{20^{18}+1}{20^{19}+1}\)và \(B=\frac{20^{17}+1}{20^{18}+1}\)

\(A=\frac{20^{18}+1}{20^{18+1}+1}\)và \(B=\frac{20^{17}+1}{20^{17+1}+1}\)

\(A=\frac{1}{20+1}\)và \(B=\frac{1}{20+1}\)

\(A=\frac{1}{21}\)và \(B=\frac{1}{21}\)

\(\Rightarrow A=B\)

       #~Will~be~Pens~#

A>20¹⁸ +1+19/20¹⁹ +1+19

A>20¹⁸+20/20¹⁹+20

A>20(20¹⁷+1)/20(20¹⁸+1)

A>20¹⁷+1/20¹⁸+1

=>A>B

Chúc bạn học tốt

\(A=\frac{20^{18}+1}{20^{19}+1}\)

\(A< \frac{20^{18}+1+19}{20^{19}+1+19}=\frac{20^{18}+20}{20^{19}+20}=\frac{20\left(20^{17}+1\right)}{20\left(20^{18}+1\right)}=B\)

\(\Rightarrow A< B\)

                                     #Louis

a) \(\dfrac{35}{101}=\dfrac{105}{303}< \dfrac{189}{303}\Rightarrow\dfrac{35}{101}< \dfrac{189}{303}\)

b) \(\dfrac{11}{13}< \dfrac{11+2}{13+2}=\dfrac{13}{15}< \dfrac{14}{15}\Rightarrow\dfrac{11}{-13}>\dfrac{-14}{15}\)

c) \(-\dfrac{32}{19}< 0< \dfrac{23}{32}\Rightarrow-\dfrac{32}{19}< \dfrac{23}{32}\)

d) \(1,561< 1,5661\Rightarrow-1,561>-1,5661\)

e) \(0,1=\dfrac{1}{10}=\dfrac{40}{400}< \dfrac{40+56}{400+56}=\dfrac{96}{456}< \dfrac{176}{456}\Rightarrow0,1< \dfrac{176}{456}\)

g) \(0,3=\dfrac{3}{10}=\dfrac{9}{30}< \dfrac{9+8}{30+8}=\dfrac{17}{38}< \dfrac{19}{38}\Rightarrow0,3< \dfrac{19}{38}\Rightarrow-0,3>\dfrac{-19}{38}\)