\(\frac{20^5.5^{10}}{100^5}\)
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\(\frac{20^5.5^{20}}{100^5}\)
\(\frac{20^5.5^{20}}{100^5}=\frac{20^5.5^5.5^{15}}{100^5}=\frac{\left(20.5\right)^5.5^{15}}{100^5}=\frac{100^5.5^{15}}{100^5}=5^{15}\)
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205.520/1005
= 45.55.520/45.255
= 45.525/45.(52)5
= 45.525/45.510
= 515
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\(\frac{20^5.5^{20}}{100^5}\)
\(=\frac{20^5.5^5.5^{15}}{100^5}\)
\(=\frac{100^5.5^{15}}{100^5}\)
\(=5^{15}\)
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2 tháng 10 2021 lúc 15:39
BÀI 2 TÍNH
A = \(\dfrac{20^5.5^{10}}{100^5}\)
B = \(\dfrac{\left(0,9\right)^5}{\left(0,3\right)^6}\)
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\(A=\dfrac{\left(20.5\right)^5.5^5}{100^5}=\dfrac{100^5.3125}{100^5}=3125\)
\(B=\dfrac{\left(0,3.3\right)^5}{\left(0,3\right)^5.0,3}=\dfrac{\left(0,3\right)^5.3^5}{\left(0,3\right)^5.0,3}=\dfrac{3^5}{0,3}=810\)
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\(A=\dfrac{2^{10}\cdot5^5\cdot5^{10}}{2^{10}\cdot5^{10}}=5^5=3125\\ B=\left(\dfrac{0,9}{0,3}\right)^5\cdot\dfrac{1}{0,3}=\dfrac{3^5}{0,3}=\dfrac{243}{0,3}=810\)
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Tính giá trị biểu thức"
a) \(\frac{20^5.5^{10}}{100^5}\) b) \(\frac{\left(0,9\right)^5}{\left(0,3\right)^{^6}}\) c) \(\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
\(\frac{20^5.5^{10}}{100^5}.\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
\(\left(\frac{4}{9}+\frac{1}{3}\right)^2+\left(\frac{3}{4}\right)^3:\left(\frac{3}{4}\right)^2:\left(\frac{-2}{3}\right)^3\)
27 tháng 5 2022 lúc 22:25
Tính hợp lí nếu có thể
b) \(\dfrac{6^3+3.6^2+3^3}{-13}\)
a) \(\dfrac{20^5.5^{10}}{100^5}\)
b:\(=\dfrac{3^3\cdot2^3+3\cdot2^2\cdot3^2+3^3}{-13}=\dfrac{3^3\left(2^3+2^2+1\right)}{-13}=-3^3=-27\)
a: \(=\dfrac{5^5\cdot4^5\cdot5^{10}}{10^{20}}=\dfrac{5^{15}\cdot2^{10}}{5^{20}\cdot2^{20}}=\dfrac{1}{5^5\cdot2^{10}}\)
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b) \(\dfrac{6^3+3.6^2+3^3}{-13}=\dfrac{2^3.3^3+3.3^2.2^2+3^3}{-13}=\dfrac{3^3\left(2^3+2^2+1\right)}{-13}\)
\(=\dfrac{3^3.\left(8+4+1\right)}{-13}=\dfrac{3^3.13}{-13}=\dfrac{27}{-1}=-27\)
a)\(\dfrac{20^5.5^{10}}{100^5}=\dfrac{20^5.5^{10}}{20^5.5^5}=\dfrac{5^5}{1}=3125\)
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Tính
a) \(\left(\frac{2}{5}\right)^5:\left(\frac{9}{25}\right)^5\)
\(b.25.5^3.\frac{1}{625}.5^2\)
c. \(\frac{20^5.5^{10}}{100^5}\)
\(\left(\frac{1}{7}\right)^2.\frac{1}{7}.49^2\)
\(a.\left(\frac{2}{5}\right)^5:\left(\frac{9}{25}\right)^5=\left(\frac{2\cdot25}{9\cdot5}\right)^5=\frac{10}{9}^5\)
\(b.25\cdot5^3\cdot\frac{1}{625}\cdot5^2=\frac{5^7}{5^4}=5^3\)
\(c.\frac{20^5\cdot5^{10}}{100^5}=\frac{2^{10}\cdot5^{15}}{2^{10}\cdot5^{10}}=5^5\)
\(d.\frac{1}{7}^2\cdot\frac{1}{7}\cdot49^2=\frac{7^4}{7^3}=7\)
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a) \(\frac{20^5.5^{10}}{100^5}\)b)\(\frac{0,9^5}{0,3^6}\)
c)\(\frac{6^3+3.6^2+3^3}{-13}\)
d)\(\frac{4^6:9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
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a. \(\frac{20^5.5^{10}}{100^5}\)= \(\frac{20^5.5^{10}}{20^5.5^5}\)= \(5^5\)=\(3125\)
b. \(\frac{0,9^5}{0,3^6}\)= \(\frac{0,9^5}{0,3^5.0,3}\)= \(\left(\frac{0,9}{0,3}\right).\frac{1}{0,3}\)= \(243.\frac{1}{0,3}\)= \(810\)
c.\(\frac{6^3+3.6^2+3^3}{-13}=\frac{\left(3.2\right)^3+3.\left(3.2\right)^{^2}+3^3}{-13}=\frac{3^3.2^3+3.3^2.2^2+3^3}{-13}\)\(=\frac{3^3\left(2^3+2^2+1\right)}{-13}=\frac{3^3.13}{-13}=3^3.\left(-1\right)=-27\)
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Tính giá trị biểu thức: 20^5.5^10/100^5. b)(0.9)^5/(0.3)^6. c)6^3+3.6^2+3^3/-13.
Tính giá trị của biểu thức: 20^5.5^10/100^5. b)(0.9)^5/(0.3)^6. c)6^3+3.6^2+3^3/-13.