\(x=\frac{10^2.5^3.15^6}{3^6.5^{10}}=\frac{\left(2.5\right)^2.\left(3.5\right)^6}{3^6.5^7}=\frac{2^2.5^2.3^6.5^6}{3^6.5^7}=2^2.5=20\)

Vậy x = 20

@Nguyễn Huy Tú bạn có thể viết rõ cách làm có dc ko?

\(x=\frac{10^2.5^3.15^6}{3^6.5^{10}}=\frac{\left(2.5\right)^2.5^3.\left(3.5\right)^6}{3^6.5^{10}}=\frac{2^2.5^2.5^3.3^6.5^6}{3^6.5^{10}}=\frac{2^2.5^{11}.3^6}{3^6.5^{10}}=2^2.5=4.5=20\)

Vậy x=20.

a) \(-45:5.\left(-3-2x\right)=3\)

\(-9.\left(-3-2x\right)=3\)

\(-3-2x=\left(3:-9\right)\)

\(-3-2x=\dfrac{-1}{3}\)

\(-2x=-3-\dfrac{1}{3}\)

-2x=\(\dfrac{-10}{3}\)

\(x=\dfrac{-10}{3}:-2\)

\(x=\dfrac{5}{3}\)

b) 

3x - 28 = x + 36

<=> 3x - x = 36 + 28

<=> 2x = 64

<=> x = 32

Vậy x = 32

c) 

(-12)2.x = 56 + 10.13.x

144.x = 56 + 130.x

144x – 130 x = 56

14x = 56

x = 56: 14

x = 4

Vậy x = 4

\(a,-45:5\cdot\left(-3-2x\right)=3\\ \Leftrightarrow-9\cdot\left(-3-2x\right)=3\\ \Leftrightarrow-2x-3=-\dfrac{1}{3}\\ \Leftrightarrow2x+3=\dfrac{1}{3}\\ \Leftrightarrow2x=-\dfrac{8}{3}\\ \Leftrightarrow x=-\dfrac{4}{3}\\ b,3x-28=x+36\\ \Leftrightarrow2x=64\\ \Leftrightarrow x=32\\ c,\left(-12\right)^2x=56+10\cdot13x\\ \Leftrightarrow144x=56+130x\\ \Leftrightarrow14x=56\\ \Leftrightarrow x=4\)

giúp mình nha mọi người

Vì 56⋮x,70⋮x ➞ x∈ƯC(56;70)

Ta có:

56=2³.7

70=2.5.7

ƯCLN(56;70)=2.7=14

ƯC(56;70)=Ư(14)={1;2;7;14}

Vì 56⋮x,70⋮x và 10<x<20

⇔x=14

Tham khảo:

Ta có:

56 = 2³ . 7

70 = 2 . 5 . 7

⇒ ƯCLN ( 56 ; 70 ) = 2. 7 =14

⇒ ƯC ( 56 ; 70 ) = { 1 ; 2 ; 7 ; 14 }

mà 10<x<20

⇒ x = 14

Ư(56) = {1; 2; 4; 7; 8; 14; 28; 56}

Ư(70) = {1; 2; 5; 7; 10; 14; 35}

=>x ∈ ƯC (56; 70) = {1; 2; 7; 14}

Mà 10 < x < 20; x ∈ N nên x ∈ 14

Đợi tí mình giải cho

\(2\left|x+1\right|=10\)

Th1 : 

\(\left|x+1\right|\ge0\Rightarrow x\ge-1\)

\(2\left(x+1\right)=10\)

\(\Rightarrow2x+2=10\)

\(\Rightarrow2x=8\)

\(\Rightarrow x=4\)

Th2 : \(\left|x+1\right|< 0\Rightarrow x< -1\)

\(2\left(-1-x\right)=10\)

\(\Rightarrow-2-2x=10\)

\(\Rightarrow-2x=8\)

\(\Rightarrow x=-4\)

a, x=4;-6