b: \(=x^2-4x+4-y^2-6y-9\)

\(=\left(x-2\right)^2-\left(y+3\right)^2\)

\(=\left(x-2-y-3\right)\left(x-2+y+3\right)\)

\(=\left(x-y-5\right)\left(x+y+1\right)\)

\(23\left(x-1\right)+19=65\)

           \(23\left(x-1\right)=65-19\)

           \(23\left(x-1\right)=46\)

                    \(x-1=46:23\)

                    \(x-1=2\)

                            \(x=2+1\)

                           \(x=3\) 

     \(5x+3x=88\)

  \(x\left(5+3\right)=88\)

         \(x.8=88\)

            \(x=88:8\)  

            \(x=11\)

\(x^3=64\)

\(x^3=4^3\)

\(\Rightarrow x=4\)

    \(\left(5x-4\right):7-2=6\)

            \(\left(5x-4\right):7=6+2\)

             \(\left(5x-4\right):7=8\)

                      \(5x-4=8.7\)

                       \(5x-4=56\)

                                \(5x=56+4\) 

                                 \(5x=60\)

                                    \(x=60:5\)

                                    \(x=12\)

\(x^{50}=x\)

\(\Rightarrow x=1\)

\(4.2^x-3=125\)

        \(4.2^x=125+3\)

        \(4.2^x=128\)

            \(2^x=128:4\)

            \(2^x=32\)

            \(2^x=2^5\)

\(\Rightarrow x=5\)

k mk nha

\(a)3\left(x-1\right)^2=75\)

\(\Leftrightarrow\left(x-1\right)^2=25\)

\(\Leftrightarrow\orbr{\begin{cases}\left(x-1\right)^2=\left(-5\right)^2\\\left(x-1\right)^2=5^2\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x-1=-5\\x-1=5\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=-4\\x=6\end{cases}}\)

\(b)170+\left(84-5x\right):2^2=186\)

\(\Leftrightarrow\frac{84-5x}{4}=16\)

\(\Leftrightarrow84-5x=64\)

\(\Leftrightarrow5x=20\)

\(\Leftrightarrow x=4\)

\(c)125-5\left(x+4\right)=38\)

\(\Leftrightarrow5\left(x+4\right)=87\)

\(\Leftrightarrow x+4=\frac{87}{5}\)

\(\Leftrightarrow x=\frac{87}{5}-4\)

\(\Leftrightarrow x=\frac{67}{5}\)

Thay x= -1

P(-1)=5(-1)^100+5(-1)^99+...+5(-1)+9

=5+(-5)+5+...+(-5)+9

Từ 1 đén 100 có: (100-1):1+1=100. ta có:50 cặp

P(-1)=[5+(-5)]x50+9=0+9=9

Xin lỗi mình làm tắt :)

Thay x= -1

P(-1)=5(-1)^100+5(-1)^99+...+5(-1)+9

=5+(-5)+5+...+(-5)+9

Từ 1 đén 100 có: (100-1):1+1=100. ta có:50 cặp

P(-1)=[5+(-5)]x50+9=0+9=9

a) 125-(-75)+32-(48+32) = 125 + 75 + 32 - 48 - 32 = 200 - 48 = 152

b) 47.347+347.(-47) = 347.( 14 - 47 ) = 347 . 0 = 0

c) x-10=-14

x = -14 +10

x = -4

d) 15 + x = 13

x = 13 - 15

x = -2

e) 25 . x = -75

x = -75/25

x = -3

g) 5x - 16 = -46

5x = -46 + 16

5x = - 30

x = -6

i) 3x - (-11) = -4

3x + 11 = -4

3x = -4 - 11

3x = -15

x = -5

hok tốt!!

a, 100 - 7 ( x - 5 ) = 31 + 3³

100 - 7 ( x - 5 ) = 31 + 27

100 - 7 ( x - 5 ) = 58

7 ( x - 5 ) = 100 - 58

7 ( x - 5 ) = 42

x - 5 = 42 : 7

x - 5 = 6

=> x = 6 +5

=> x = 11

Vậy x = 11

b, 12 ( x - 1 ) : 3 = 4³ + 2³

12 ( x - 1 ) : 3 = 64 + 8

12 ( x - 1 ) : 3 = 72

12 ( x - 1 ) = 72 . 3

12 ( x - 1 ) = 216

x - 1 = 216 : 12

x - 1 = 18

=> x = 18 + 1

=> x = 19

Vậy x = 19

c, 24 + 5x = 7⁵ : 7³

24 + 5x = 7²

24 + 5x = 49

5x = 49 - 24

5x = 25

=> x = 25 : 5

=> x = 5

Vậy x = 5

d, 5x - 206 = 2⁴ . 4

5x - 206 = 16 . 4

5x - 206 = 64

5x = 64 + 206

5x = 270

=> x = 270 : 5

=> x = 54

Vậy x = 54

e, 125 = x³

5³ = x³

=> x = 5

Vậy x = 5

g, 64 = x²

8² = x²

=> x = 8

Vậy x = 8

a) \(\left(17-229\right)+\left(17-25+229\right)\)

\(=17-229+17-25+229\)

\(=34-25=9\)

b) \(\left(125-679+145\right)-\left(125-679\right)\)

\(=125-679+145-125+679\)

\(=145\)

5(x-1)=125-25

5(x-1)=100

x-1=100:5

x-1=20

x=20+1

x=21

12(x-1):3=64+8

12(x-1):3=72

12(x-1)=72.3

12(x-1)=216

x-1=216:12

x-1=18

x=18+1

x=19

(x-1)^3=5^3

=>x-1=5

x=5+1

x=6

`@` `\text {Ans}`

`\downarrow`

\(\left(\dfrac{1}{5}\right)^{2x-1}=\dfrac{1}{125}\)

`=>`\(\left(\dfrac{1}{5}\right)^{2x-1}=\left(\dfrac{1}{5}\right)^3\)

`=>`\(2x-1=3\)

`=> 2x = 3 + 1`

`=> 2x = 4`

`=> x = 4 \div 2`

`=> x = 2`

Vậy, `x = 2.`

`@` `\text {Kaizuu lv uuu}`