X x 39 + X x 63 - X - X = 3200 

X x (39 + 63 - 1 - 1) = 3200 

X x (102 - 2) = 3200 

X x 100 = 3200

X = 3200 : 100

X = 32 

Vậy X = 32

32,4 nhé

32 x ( x:68) =3200 +40

32 x(x:68)=3240

(x:68) = 3240 : 32

(x:68) = 101,25

x  = 101,25 x 68

x  = 6885

Học tốt<3

bạn ơi bạn phải đưa ra 3 số đầu để mk bt quy luật nó đã

mình ko giúp nhưng mình sẽ gợi ý : tính số cuối của tổng thôi

22222234354235454656546546241234568749788889920992920202022022-2022-2-202012000020220200q dung ko

a) \(x-270:45=120\)

\(x-270=120.45\)

\(x-270=5400\)

\(x=5400+270\)

\(x=5670\)

_____

b) \(575-\left(6\times x+70\right)=445\)

\(6\times x+70=575-445\)

\(6\times x+70=130\)

\(6\times x=130-70\)

\(6\times x=60\)

\(x=60:6\)

\(x=10\)

_____

c) \(x-105:21=15\)

\(x-105=15.21\)

\(x-105=315\)

\(x=315+105\)

\(x=420\)

_____

d) \(3200:\left(405-x\right)=8\)

\(405-x=3200:8\)

\(405-x=400\)

\(x=405-400\)

\(x=5\)

_____

i) \(43575-75\times x=42450\)

\(75.x=43575-42450\)

\(75.x=1125\)

\(x=1125:75\)

\(x=15\)

_____

e) \(8,75\times x+1,25\times x=20\)

\(x\times\left(8,75+1,25\right)=20\)

\(x\times10=20\)

\(x=20:10\)

\(x=2\)

ko cần giải câu b đâu

a) x = 5670

b) x = 10

c) x = 420

d) x = 5

i) x = 15

e) x = 2

a) (x - 1) + (x + 2) + (x - 3) + (x + 4) + (x - 5) + (x + 6) = 21

x - 1 + x + 2 + x - 3 + x + 4 + x - 5 + x + 6 = 21

6x + 3 = 21

6x = 21 - 3

6x = 18

x = 18 : 6 

x = 3

b) (x - 1) + (x + 3) + (x - 5) + (x + 7) + (x - 9) + (x + 11) = 186

x - 1 + x + 3 + x - 5 + x + 7 + x - 9 + x + 11 = 186

6x + 6 = 186

6x = 186 - 6

6x = 180

x = 180 : 6

x = 30

a) \(2^x=16=2^4\Rightarrow x=4\)

b) \(x^3=27=3^3\Rightarrow x=3\)

c) \(x^{50}=x\Rightarrow x\left(x^{49}-1\right)=0\Rightarrow x=0\) hay \(x=1\)

d) \(\left(x-2\right)^2=16=4^2\Rightarrow x-2=4\) hay \(x-2=-4\)

\(\Rightarrow x=6\) hay \(x=-2\)

a) \(2^{300}=2^{3.100}=8^{100}\)

\(3^{200}=3^{2.100}=9^{100}\)

vì \(8^{100}< 9^{100}\)

\(\Rightarrow2^{300}< 3^{200}\)

b) \(3^{500}=3^{5.100}=243^{100}\)

\(7^{300}=7^{3.100}=343^{100}\)

vì \(243^{100}< 343^{100}\)

\(\Rightarrow3^{500}< 7^{300}\)

`@` `\text {Ans}`

`\downarrow`

`1,`

`a,`

`2^x = 16`

`=> 2^x = 2^4`

`=> x = 4`

Vậy, `x = 4`

`b,`

`x^3 = 27`

`=> x^3 = 3^3`

`=> x = 3`

Vậy, `x = 3`

`c,`

\(x^{50}=x\)

`=>`\(x^{50}-x=0\)

`=>`\(x\left(x^{49}-1\right)=0\)

`=>`\(\left[{}\begin{matrix}x=0\\x^{49}-1=0\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=0\\x^{49}=1\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=0\\x=1\end{matrix}\right.\)

Vậy, `x \in {0; 1}`

`d,`

`(x-2^2)=16`

`=> x - 2^2 = 16`

`=> x = 16 + 2^2`

`=> x = 20`

Vậy, `x = 20`

`2,`

`a,`

Ta có:

\(2^{300}=\left(2^3\right)^{100}=8^{100}\)

\(3^{200}=\left(3^2\right)^{100}=9^{100}\)

Vì `8 < 9 =>`\(8^{100}< 9^{100}\)

`=>`\(2^{300}< 3^{200}\)

Vậy, \(2^{300}< 3^{200}\)

`b,`

Ta có:

\(3^{500}=\left(3^5\right)^{100}=243^{100}\)

\(7^{300}=\left(7^3\right)^{100}=343^{100}\)

Vì `243 < 343 =>`\(243^{100}< 343^{100}\)

`=>`\(3^{500}< 7^{300}\)

Vậy, \(3^{500}< 7^{300}.\)

10124235

Lời giải:

$\frac{21\times 45}{63\times 39}=\frac{21\times 15\times 3}{21\times 3\times 39}=\frac{15}{39}=\frac{3\times 5}{3\times 13}=\frac{5}{13}$