6.x-5=19
Đố bn viết thuộc bảng nhân 19 :
19 x 1 =
19 x 2 =
19 x 3 =
19 x 4 =
19 x 5 =
19 x 6 =
19 x 7 =
19 x 8 =
19 x 9 =
19 x 10 =
19 x 1 = 19
19 x 2 = 38
19 x 3 = 57
19 x 4 = 76
19 x 5 = 95
19 x 6 = 114
19 x 7 = 133
19 x 8 = 152
19 x 9 = 172
19 x 10 = 190
Hok tốt ah
MẸO HEN
NẾU DÒNG THẲNG TẮP NHƯ VẦY
9 x 1
9 x 2
9 x 3
9 x 4
9 x 5
9 x 6
9 x 7 6 3
9 x 8 7 2
9 x 9 8 1
9 x 1=9 0
A, 7 x - x = 5^21 : 5^19 + 3 . 2^2 - 7^0
B, 6 x + x = 5^11 : 5^19 + 3^1
C, 7 x - 2x = 6^17 : 6^15 + 44:11
A, 7x - x = 5^21 : 5^19 + 3 . 2^2 - 7^0
6x = 5^2 + 3 . 4 - 1
6x = 25 + 12 - 1
6x = 37 - 1
6x = 36
x = 6.
B, mình giải ra nhưng số to quá. Bạn thử kiểm tra lại đề xem.
C, 7x - 2x = 6^17 : 6^15 + 44 : 11
5x = 6^2 + 4
5x = 40
x = 8.
Tinh Tong
A=1+2+3+....+999
B=21+23+25+...+1001
C=23+24+...+127+128
D=15+17+19+21+...+151+153+155
Bài 1 tìm x biết
a> x=7/25+-1/5
b> x=5/11+4/-9
c> x/3=2/3+-1/7
d> x/5=5/6+-19/30
e> x/6=3/2+-7/15
Bài 2 cộng các phân số sau
a> -650/1430+588/686
b> 2004/2010+8/-670
Bài 3 tìm x biết
a> -5/13+-4/13 < x/13 < 2/13+-7/13
b> 3/2+-1/3 <x/6 < 1/9+31/18
c> -5/19+3/19 < x/19 bé hơn hoặc bằng 13/19+-11/19
d> -7/8+5/6 bé hơn hoặc bằng x/24 bé hơn hoặc bằng 5/8+-5/12
Bài 1 :
\(a)x=\frac{7}{25}+\left(-\frac{1}{5}\right)\)
\(x=\frac{2}{25}\)
\(b)x=\frac{5}{11}+\left(\frac{4}{-9}\right)\)
\(x=\frac{1}{99}\)
Mấy câu kia dễ tự làm :>
Bài 1 tính hợp lí
a) 2017.;1-2018)+2018.2017+(-1)*2017
b) 7/19 8/11+3/11:19/7-2/-19
c) (6 và 4/9+3 và 7/11)-5 và4/9
Bài 2 tìm x
a) 5/6-x=-5/12-1/-4
b) x-2 trên phần -5=6/7
c) 1/2.x-3/4.x=-5/6
1b)\(\frac{7}{19}x\frac{8}{11}+\frac{3}{11}:\frac{19}{7}-\frac{2}{-19}=\frac{7}{19}x\frac{8}{11}+\frac{3}{11}x\frac{7}{19}+\frac{2}{19}=\left(\frac{8}{11}+\frac{3}{11}\right)\frac{7}{19}+\frac{2}{19}=\frac{7}{19}+\frac{2}{19}=\frac{9}{19}\)
c)\(4\left(\frac{4}{9}+\frac{7}{11}-\frac{4}{9}\right)=4\frac{7}{11}\)
từ rồi làm tiếp
2)
a)\(\frac{5}{6}-x=-\frac{5}{12}-\frac{1}{-4}=-\frac{5}{12}+\frac{1}{4}=-\frac{5}{12}+\frac{3}{12}=-\frac{1}{6}.\)
\(x=\frac{5}{6}--\frac{1}{6}=\frac{5}{6}+\frac{1}{6}=1\)
b)\(\frac{x-2}{-5}=\frac{6}{7}\)
\(\frac{\left(x-2\right)\left(-7\right)}{35}=\frac{30}{35}\)
\(\Rightarrow\left(x-2\right)\left(-7\right)=30\)
c)\(\frac{1}{2}x-\frac{3}{4}x=-\frac{5}{6}\)
\(\left(\frac{1}{2}-\frac{3}{4}\right)x=-\frac{5}{6}\)
\(-\frac{1}{4}x=-\frac{5}{6}\)
\(x=\frac{20}{6}=\frac{10}{3}\)
vậy \(x=\frac{10}{3}\)
a,5^x+4-3×5^x+3=2×5^11
b,3×5^x+2+4×5^x-3=19×5^10
c,6×8^x-1+8^x-1=6×8^19+8^21
d,5×2^x+3×2^x+2=5×2^5+3×2^7
a,
\(5^{x+4}-3.5^{x+3}=2.5^{11}\)
\(\Rightarrow5^{x+3}\left(5-3\right)=2.5^{11}\)
\(\Rightarrow5^{x+3}2=2.5^{11}\)
\(\Rightarrow5^{x+3}=5^{11}\)
\(\Rightarrow x+3=11\)
\(\Rightarrow x=8\)
b, (Check lai xem de sai o dau khong nhe)
\(3.5^{x+2}+4.5^{x+3}=19.5^{10}\)
Dat 5x ra ben ngoai
\(\Rightarrow5^x.5^23+5^x:5^{-3}.4\)
\(\Rightarrow5^x\left(5^2.3+5^{-3}.4\right)\)
\(\Rightarrow5^x\left(5^{-3}.5^5.3+5^{-3}.4\right)\)
\(\Rightarrow5^x[5^{-3}\left(5^53+4\right)\)
\(\Rightarrow5^x[5^{-3}\left(3125.3+4\right)\)
\(\Rightarrow5^x\left(5^{-3}\right).9379\)
=> Khong tim duoc gia tri cua x \(\Rightarrow x\in\varnothing\)
5/6 x 4/19 + 7/12 x 4/19 + 18/19
Giúp vs
5/6 x 4/19 + 7/12 x 4/19 + 18/19
=(5/6+7/12)×(4/19+18/19)
= 17/12×22/19
= 187/114
a,-8/3+7/5+-71/15<x<-13/7+19/14+-7/2
b,-19/6+-15/2+11/3<x<-5/4+19/12+-10/3
c,-6/7+3/35<x<-2/5+3/7
d,x=3/4+1/-12
e,x/14=1/7+-3/14
f,11/18+13/6=85/x
g,8/17+5/17<x/17<6/17+9/17
x/5=5/6-(-19/30)
\(\dfrac{x}{5}=\dfrac{5}{6}-\left(-\dfrac{19}{30}\right)\\ =>\dfrac{x}{5}=\dfrac{5}{6}+\dfrac{19}{30}\\ =>\dfrac{x}{5}=\dfrac{25}{30}+\dfrac{19}{30}\\ =>\dfrac{x}{5}=\dfrac{44}{30}\\ =>\dfrac{x}{5}=\dfrac{22}{15}\\ =>15x=22.5\\ =>15x=110\\ =>x=110:15\\ =>x=\dfrac{22}{3}\)
*Thực hiện
1/ (\(\dfrac{2021}{2020}\)+\(\dfrac{2020}{2021}\)) x (\(\dfrac{1}{2}\)-\(\dfrac{1}{3}\)-\(\dfrac{1}{6}\))
2/ (\(\dfrac{7}{19}\)-\(\dfrac{5}{12}\)):\(\dfrac{-5}{8}\)-(\(\dfrac{7}{19}\)-\(\dfrac{29}{12}\)):\(\dfrac{5}{8}\)
3/ \(\dfrac{-5}{6}\)x\(\dfrac{7}{24}\)-\(\dfrac{5}{6}\)x\(\dfrac{14}{24}\)-\(\dfrac{5}{6}\)x\(\dfrac{3}{24}\)
1/ \(\left(\dfrac{2021}{2020}+\dfrac{2020}{2021}\right).\left(\dfrac{1}{2}-\dfrac{1}{3}-\dfrac{1}{6}\right)\)
=\(\left(\dfrac{2021}{2020}+\dfrac{2020}{2021}\right).0\)
=\(0\)
mink chịu bài này nó rất khó
Tính giá trị biểu thức sau một cách hợp lí
A = 6/19 x -7/11 + 6/19 x -4/11 + -13/19 B = 5/7 x -4/13 + 5/7 x 7/13 - 5/13 x 3/7
giúp mình với
A=\(\frac{6}{19}\). \(\frac{-7}{11}\)+\(\frac{6}{19}\).\(\frac{-4}{11}\)+\(\frac{-13}{19}\)
=\(\frac{6}{19}\).(\(\frac{-7}{11}\)+\(\frac{-4}{11}\))+\(\frac{-13}{19}\)
=\(\frac{6}{19}\).\(\frac{-11}{11}\)+\(\frac{-13}{19}\)
=\(\frac{6}{19}\).-1 +\(\frac{-13}{19}\)
=\(\frac{-6}{19}\)+\(\frac{-13}{19}\)
=\(\frac{-19}{19}\)
+1