a) \(\frac{7}{15}+\frac{9}{10}+\frac{8}{15}-\frac{-1}{10}-\frac{20}{10}+\frac{1}{157}\)

\(=\frac{7}{15}+\frac{9}{10}+\frac{8}{15}+\frac{1}{10}-\frac{20}{10}+\frac{1}{157}\)

\(=\left(\frac{7}{15}+\frac{8}{15}\right)+\left(\frac{9}{10}+\frac{1}{10}\right)-2+\frac{1}{157}\)

\(=1+1-2+\frac{1}{157}\)

\(=2-2+\frac{1}{157}\)

\(=0+\frac{1}{157}=\frac{1}{157}\)

b) \(\frac{1}{13}+\frac{16}{7}+\frac{3}{105}-\frac{9}{7}-\frac{-12}{13}\)

\(=\frac{1}{13}+\frac{16}{7}+\frac{1}{35}-\frac{9}{7}+\frac{12}{13}\)

\(=\left(\frac{1}{13}+\frac{12}{13}\right)+\left(\frac{16}{7}-\frac{9}{7}\right)+\frac{1}{35}\)

\(=1+1+\frac{1}{35}\)

\(=2+\frac{1}{35}\)

\(=\frac{70}{35}+\frac{1}{35}=\frac{71}{35}\)

\(M=\frac{\left(-7\right).15.9.15.14}{9.49.7.15}=\frac{-15.2}{7}=\frac{-30}{7}.\)

\(N=\frac{200}{189}+\frac{1}{14}=\)1.12962962963

\(M=\left(\frac{-7}{9}\cdot\frac{9}{7}\right)\cdot\left(\frac{15}{49}\cdot\frac{14}{15}\right)\cdot15\)

\(M=\left(-1\right)\cdot\frac{2}{7}\cdot15\)

\(M=\frac{-30}{7}\)

\(N=\frac{5}{9}\cdot\frac{4}{7}\cdot\frac{10}{3}+\frac{3}{9}\cdot\frac{3}{7}\cdot\frac{1}{2}\)

\(N=\frac{200\cdot2}{189\cdot2}+\frac{9\cdot3}{126\cdot3}\)

\(N=\frac{400}{378}+\frac{27}{378}\)

\(N=\frac{61}{51}\)

T i ck nha

cho mình bỏ đi 1 phân số \(\frac{x}{45}\)ở cuối nhé

đề bài là gì?

\(\left(\frac{5}{12}-\frac{5}{7}-\frac{22}{45}+\frac{7}{12}-\frac{23}{45}\right).\left|x\right|-9=-2\)

\(\left(\frac{12}{12}-\frac{5}{7}-\frac{45}{45}\right).\left|x\right|=-2+9\)

\(\left(1-\frac{5}{7}-1\right).\left|x\right|=7\)

\(\frac{-5}{7}.\left|x\right|=7\)

\(\left|x\right|=7:\left(\frac{-5}{7}\right)\)

\(\left|x\right|=\frac{-49}{5}\)

\(\Rightarrow x\in\varnothing\) vì trị tuyệt đối của 1 số luôn dương 

e) \(E=0,7.2\frac{2}{3}.20.0,375.\frac{5}{28}\)

        \(=\left(0,7.20\right)\left(2\frac{2}{3}.0,375\right)\frac{5}{28}\)

        \(=14.1.\frac{5}{28}\)

        \(=14.\frac{5}{28}\)

        \(=\frac{5}{2}\)

f) \(F=\left(9,75.21\frac{3}{7}+\frac{39}{4}.18\frac{4}{7}\right)\frac{15}{78}\)

       \(=\left(\frac{39}{4}.21\frac{3}{7}+\frac{39}{4}.18\frac{4}{7}\right)\frac{15}{78}\)

       \(=\frac{39}{4}\left(21\frac{3}{7}+18\frac{4}{7}\right)\frac{15}{78}\)

       \(=\frac{39}{4}.40.\frac{15}{78}\)

       \(=390.\frac{15}{78}\)

       \(=78\)

Chúc bạn học tốt môn Toán!!!

Mình ko ghi đề đâu

\(A=49\frac{8}{23}-5\frac{7}{32}-14\frac{8}{23}=\left(49\frac{8}{23}-14\frac{8}{23}\right)-5\frac{7}{32}=35-5\frac{7}{32}=29\frac{25}{32}\)

\(B=71\frac{38}{45}-43\frac{8}{45}+1\frac{17}{57}=\left(71\frac{38}{45}-43\frac{8}{45}\right)+1\frac{17}{57}=28\frac{2}{3}+1\frac{17}{57}=29\frac{55}{57}\)

\(C=-\frac{3}{7}.\left(\frac{5}{9}+\frac{4}{9}\right)+2\frac{3}{7}=-\frac{3}{7}.1+2\frac{3}{7}=-\frac{3}{7}+2\frac{3}{7}=2\)

a) \(A=49\frac{8}{23}-\left(5\frac{7}{32}+14\frac{8}{23}\right)\)

        \(=\left(49\frac{8}{23}-14\frac{8}{23}\right)-5\frac{7}{32}\)

        \(=35-5\frac{7}{32}\) 

        \(=34\frac{32}{32}-5\frac{7}{32}\)       

        \(=29\frac{25}{32}\) 

b) \(B=71\frac{38}{45}-\left(43\frac{8}{45}-1\frac{17}{57}\right)\)

        \(=\left(71\frac{38}{45}-43\frac{8}{45}\right)+1\frac{17}{57}\)

        \(=28\frac{2}{3}+1\frac{17}{57}\)  

        \(=28\frac{38}{57}+1\frac{17}{57}\)

        \(=29\frac{55}{57}\)

c) \(C=\frac{-3}{7}.\frac{5}{9}+\frac{4}{9}.\frac{-3}{7}+2\frac{3}{7}\)

        \(=\frac{-3}{7}\left(\frac{5}{9}+\frac{4}{9}\right)+2\frac{3}{7}\)

        \(=\frac{-3}{7}+2\frac{3}{7}\)

        \(=2\)

d) \(D=\left(19\frac{5}{8}:\frac{7}{12}-13\frac{1}{4}:\frac{7}{12}\right)\frac{4}{5}\)

        \(=\left(19\frac{5}{8}-13\frac{1}{4}\right):\frac{7}{12}.\frac{4}{5}\)

        \(=\frac{51}{8}:\frac{7}{12}.\frac{4}{5}\)

        \(=\frac{153}{14}.\frac{4}{5}\)

        \(=\frac{306}{35}\)