a: \(\Leftrightarrow\left[\left(3x+14\right):4-3\right]:2=1\)

=>(3x+14):4-3=2

=>(3x+14):4=5

=>3x+14=20

=>3x=6

hay x=2

b: \(\Leftrightarrow\left[\left(x:4+17\right):10+3\cdot16\right]:10=5\)

\(\Leftrightarrow\left(x:4+17\right):10=50-48=2\)

=>x:4+17=20

=>x:4=3

hay x=12

c: \(\Leftrightarrow2\cdot15^2+\left[2\cdot125-\left(2x+4\right)\cdot5\right]:19=453\)

\(\Leftrightarrow250-\left(2x+4\right)\cdot5=\left(453-450\right)\cdot19=57\)

=>5(2x+4)=197

=>2x+4=197/5

=>2x=177/5

hay x=177/10

d: \(\Leftrightarrow\left(19x+50\right):14=5^2-4^2=9\)

=>19x+50=126

=>19x=76

hay x=4

e: \(\Leftrightarrow2\cdot3^x=10\cdot3^{12}+8\cdot3^{12}=18\cdot3^{12}\)

\(\Leftrightarrow3^x=3^2\cdot3^{12}=3^{14}\)

hay x=14

f: \(\Leftrightarrow3\left(x+2\right):7=30\)

=>3(x+2)=210

=>x+2=70

hay x=68

g: \(2480-1570+200-x+5=1010\)

=>1115-x=1010

hay x=105

Mọi người ơi, giúp em với ạ

a) \(\left(9^4.8+9^4.5\right):\left(9^2.\left(10-1\right)\right)\)

=\(9^4.13:9^3=13.9=117\)

b) 100-(75-25)=100-50=50

\(a,\left(2^3\cdot9^4+9^3\cdot45\right):\left(9^2\cdot10-9^2\right)\)

\(< =>\left(8\cdot6561+729\cdot45\right):\left(81\cdot10-81\right)\)

\(< =>\left(52488+32805\right):\left(810-81\right)\)

\(< =>85293:729\)

\(< =>117\)

\(b,100-\left[75-\left(7-2\right)^2\right]\)

\(< =>100-\left[75-\left(5\right)^2\right]\)

\(< =>100-\left[75-25\right]\)

\(< =>100-50\)

\(< =>50\)

\(c,\left(20\cdot2^4+12\cdot2^4\right)-\left(48\cdot2^2\right):8^2\)

\(< =>\left[2^4\cdot\left(20+12\right)\right]-\cdot\left(48\cdot4\right):8^2\)

\(< =>\left[2^4\cdot32\right]-192:8^2\)

\(< =>\left[16\cdot32\right]-192:64\)

\(< =>512-3\)

\(< =>509\)

câu b sai rồi,thế này mới đúng nè:

b,(19x+2.5⁵):4=(13-8)²-4²

(19x+2.5²):14=5²-4²

(19x+2.5²):14=8

19x+2.5²+126

19x+50=126

19x=76

x=4

sai rồi 8 phải sửa là 9 mới đúng

10^X=1^X

Do 1^mấy cũng =1

=>10^x=1 

=>x=0

( 19x + 2.5² ) : 14 = ( 13 - 8 )²- 4 ²

( 19x + 2.5² ) : 14 = 5²- 4 ²

( 19x + 2.5² ) : 14 = 25- 16

( 19x + 2.5² ) : 14 =9

( 19x + 50 ) : 14 =9

 19x + 50=9 . 14

 19x + 50=126

19x=126-50

19x=76

x=76:19

x=4

vbawngf 4 bạn nhé chắc chắn 100%

gan gon hon nha

(19x+2*5^2)/14=(13-8)^2-4^

(19x+2*25)/14=(13-8)^2-16

(19x+2.25)/14=5^-16

(19x+2.25)/14=25-16

(19+2.25)=9*14

19X=126+50

x=76/19

x=4

a) \(\frac{3}{7}-\frac{1}{7}x=\frac{2}{3}\)

=> \(\frac{1}{7}x=\frac{3}{7}-\frac{2}{3}=-\frac{5}{21}\)

=> \(x=-\frac{5}{21}:\frac{1}{7}=-\frac{5}{21}\cdot7=-\frac{5}{3}\)

b) \(3x^2-2=72\)=> 3x² = 74 => x² = 74/3 => x không thỏa mãn

c) \(\left(19x+2\cdot5^2\right):14=\left(13-8\right)^2-4^2\)

=> \(\left(19x+2\cdot25\right):14=5^2-4^2=9\)

=> \(\left(19x+50\right):14=9\)

=> \(19x+50=126\)

=> \(19x=76\)

=> x = 4

d) \(x:\frac{1}{2}+x:\frac{1}{4}+x:\frac{1}{8}+x:\frac{1}{16}+x:\frac{1}{32}=343\)

=> \(x\cdot2+x\cdot4+x\cdot8+x\cdot16+x\cdot32=343\)

=> \(x\left(2+4+8+16+32\right)=343\)

=> x . 62 = 343

=> x = 343/62

( x + 2 ) chia hết cho ( x - 1 ) => \(\frac{x+2}{x-1}\in Z\)

\(\frac{x+2}{x-1}=\frac{x-1+3}{x-1}=1+\frac{3}{x-1}\)

\(\Rightarrow x-1\inƯ\left(3\right)\)

\(\Rightarrow x-1\in\left(-1;1-3;3\right)\)

Ta có các giá trị X thỏa mãn :

\(x-1=-3\Rightarrow x=-2\)

\(x-1=1\Rightarrow x=2\)

\(x-1=3\Rightarrow x=4\)

\(\Rightarrow x-1=-1\Rightarrow x=0\)

Điều kiện \(x\ne1\)

Vậy các giá trị của x là : \(=-2;0;2;4\)

a,vi (x-1)chia het cho (x-1) suy ra (x+2)-(x-1) chia het cho (x-1) Suy ra 3 chia het cho (x-19) suy ra x-1 thuoc {1;3} suy ra x thuoc {2;4}

( 19x + 2.52 ) : 14 = ( 13 - 8 )2- 4 2

( 19x + 2.52 ) : 14 = 52- 4 2

( 19x + 2.52 ) : 14 = 25- 16

( 19x + 2.52 ) : 14 =9

( 19x + 50 ) : 14 =9

 19x + 50=9 . 14

 19x + 50=126

19x=126-50

19x=76

x=76:19

x=4

(19x + 2.5²) : 14 = (13 - 8)² - 4²

(19x + 2.25) : 14 = 5² - 16

(19x + 50) : 14 = 25 - 16

(19x + 50) : 14 = 9

19x + 50 = 9 . 14

19x + 50 = 126

19x = 126 - 50

19x = 76

x = 76 : 19

x = 4