Question

Tìm x : a) (19x + 2.5^2) : 14 = (13-8)^2 - 4^2

            b) (x-10):2 = 5-2(x+1)

Giúp mình với đi mà !!!!!Cầu xin các bn đó

Answer 1

\(a.\left(19x+2.5^2\right):14=\left(13-8\right)^2-4^2\)

\(\Leftrightarrow\left(19x+50\right):14=25-16\)

\(\Leftrightarrow\left(19x+50\right):14=9\)

\(\Leftrightarrow19x+50=126\)

\(\Leftrightarrow19x=76\)

\(\Leftrightarrow x=4\)

\(b.\left(x-10\right):2=5-2\left(x+1\right)\)

\(\Leftrightarrow\left(x-10\right):2=5-2x-2\)

\(\Leftrightarrow\frac{1}{2}x-5=3-2x\)

\(\Leftrightarrow\frac{1}{2}x+2x=3+5\)

\(\Leftrightarrow\frac{5}{2}x=8\)

\(\Leftrightarrow x=3,2\)