a) 42 = 2.3.7

58 = 2.29

ƯCLN(42; 58) = 2

ƯC(42; 58) = Ư(2) = {1; 2}

b) 90 = 2.3².5

150 = 2.3.5²

ƯCLN(90; 150) = 2.3.5 = 30

ƯC(90; 150) = Ư(30) = {1; 2; 3; 5; 6; 10; 15; 30}

c) 154 = 2.7.11

13 = 13

ƯCLN(154; 13) = 1

ƯC(154; 13) = Ư(1) = 1

d) 24 = 2³.3

84 = 2².3.7

180 = 2².3².5

ƯCLN(24; 84; 180) = 2².3 = 12

ƯC(24; 84; 180) = Ư(12) = {1; 2; 3; 4; 6; 12)

12 = 2².3

18 = 2.3²

24 = 2³.3

ƯCLN(12; 18; 24) = 2.3 = 6

ƯC(12; 18; 24) = {1; 2; 3; 6}

12 = 2².3

18 = 2.3²

24 = 2³.3

ƯCLN(12; 18; 24) = 2.3 = 6

ƯC(12; 18; 24) = {1; 2; 3; 6}

12=2.2.3    18=2.3.3    24=3.4.2                       ƯC(12,18,24)=2.3=6                                     ƯCLN(12,18,24)=3 mũ 2=6

a)16 và 24

 Ta có: 16= 2⁴                    24=2³.3

ƯCLN{16;24} = 2³ = 8 hay bạn suy ra luôn nhé!

ƯC{16;24} = Ư(8) = {1;2;4;8}

c) Ta có: 60 =2².3.5

               90 = 2.3².5

              135= 3³.5

ƯCLN{ 60;90;135} = 3.5 = 15

ƯC{ 60;90;135} = ƯC(15) = {1;3;5;15}

Bạn tick trước cho mình đã nhé?

a: \(24=2^3\cdot3;40=2^3\cdot5\)

=>\(ƯCLN\left(24;40\right)=2^3=8\)

=>\(ƯC\left(24;40\right)=\left\{1;-1;2;-2;4;-4;8;-8\right\}\)

b: \(12=2^2\cdot3;52=2^2\cdot13\)

=>\(ƯCLN\left(12;52\right)=2^2=4\)

=>\(ƯC\left(12;52\right)=\left\{1;-1;2;-2;4;-4\right\}\)

c: \(45=3^2\cdot5;180=2^2\cdot3^2\cdot5\)

=>\(ƯCLN\left(45;180\right)=3^2\cdot5=45\)

=>\(ƯC\left(45;180\right)=\left\{1;-1;3;-3;5;-5;9;-9;15;-15;45;-45\right\}\)

d: \(27=3^3;45=3^2\cdot5;75=3\cdot5^2\)

=>\(ƯCLN\left(27;45;75\right)=3\)

=>\(ƯC\left(27;45;75\right)=\left\{1;-1;3;-3\right\}\)

Ta có : \(108=2^2.3^3\)

             \(2^3.3^2.5\)

=> ƯCLN(108;180 ) = \(2^2.3^2\) = 36

Mà Ư(36) = { 1 ; 2; 3 ; 4 ;6 ;9 ; 12 ;18 ; 36 }

=> ƯC(108;180) > 15 = { 18 ; 36 } 

\(Tac\text{ó}:108=2^2.3^3\\ 180=2^3.3^2.5\\ =>UCLN\left(108;80\right)=2^2.3^2=36\\ M\text{à}\text{Ư}\left(36\right)=\left\{1;2;3;4;6;9;12;18;36\right\}\)

=>ƯC(108;180)>15={18;36)

108=2^2.3^3

180=2^2.3^2.5

=)UCLN(108;180)=2^2.3^2=36 Ư(36)= 1;2;3;4;6;9;12;18;36

=) ƯC(108;180)=1;2;3;4;6;9;12;18;36

Mà ước chung lại>15

UC (108;180)ϵ18;36

bạn phân tích ra thừa số nguyên tố rồi lấy thừa số chung nhân lại vói nhau là dc 

a) Ta có:

90 = 2 × 3² x 5

126 = 2 × 3² x 7

=> ƯCLN(90; 126) = 2 × 3² =18

=> ƯC(90; 126) = Ư(18) = {1 ; -1 ; 2 ; -2 ; 3 ; -3 ; 6 ; -6 ; 9 ; -9 ; 18 ; -18}

\(1.90và126\)

Ta có : \(90=2.3^2.5\)

          \(126=2.3^2.7\)

\(ƯCLN\left(90,126\right)=2.3^2=18\)

\(ƯC\left(90,126\right)=Ư\left(18\right)=\left\{-18;-9;-6;-3;-2;-1;1;2;3;6;9;18\right\}\)

2. 80 và 680

Ta có : \(80=2^4.5;680=2^3.5.17\)

\(ƯCLN\left(80;680\right)=2^3.5=40\)

\(ƯC\left(80;680\right)=Ư\left(40\right)=\){-40;-20;-10;-8;-5;-4;-2;-1;1;2;4;5;8;10;20;40}

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