tính thuận tiện
5/11 x 27/21 - 5/11 x 2/7
tính thuận tiện
5/11 x 27/11 - 5/11 x 2/7
\(\frac{5}{11}\)x \(\frac{27}{11}\)- \(\frac{5}{11}\) x \(\frac{2}{7}\)
= \(\frac{5}{11}\)x ( \(\frac{27}{11}\) - \(\frac{5}{11}\))
=\(\frac{5}{11}\)x \(\frac{22}{11}\)
=\(\frac{5}{11}\) x 2 = \(\frac{10}{11}\)
5/11 x 27/11 - 5/11 x 2/7
= 5/11(27/11 - 2/7)
=5/11 x 167/77
=835/847
tính bằng cách thuận tiện nhất
a, 20,23 x 21 + 20,23 x 80 - 20,23
b, 5/13 x 7/11 + 5/13 x 2/11 + 8/13 x 9/11
\(\dfrac{5}{13}\times\dfrac{7}{11}+\dfrac{5}{13}\times\dfrac{2}{11}+\dfrac{8}{13}\times\dfrac{9}{11}\)
\(=\dfrac{5}{13}\times\left(\dfrac{7}{11}+\dfrac{2}{11}\right)+\dfrac{8}{13}\times\dfrac{9}{11}\)
\(=\dfrac{5}{13}\times\dfrac{9}{11}+\dfrac{8}{13}\times\dfrac{9}{11}\)
\(=\dfrac{9}{11}\times\left(\dfrac{5}{13}+\dfrac{8}{13}\right)\)
\(=\dfrac{9}{11}\times1\)
\(=\dfrac{9}{11}\)
a) \(20,23\times21+20,23\times80-20,23\)
\(=20,23\times\left(21+80-1\right)\)
\(=20,23\times100\)
\(=2023\)
\(\dfrac{5}{13}\) \(\times\) \(\dfrac{7}{11}\) + \(\dfrac{5}{13}\) \(\times\) \(\dfrac{2}{11}\) + \(\dfrac{8}{13}\) \(\times\) \(\dfrac{9}{11}\)
= \(\left(\dfrac{5}{13}\times\dfrac{7}{11}+\dfrac{5}{13}\times\dfrac{2}{11}\right)\)+ \(\dfrac{8}{13}\) \(\times\) \(\dfrac{9}{11}\)
= \(\dfrac{5}{13}\)\(\times\) (\(\dfrac{7}{11}\) + \(\dfrac{2}{11}\)) + \(\dfrac{8}{13}\) \(\times\) \(\dfrac{9}{11}\)
= \(\dfrac{5}{13}\) \(\times\) \(\dfrac{9}{11}\) + \(\dfrac{8}{13}\) \(\times\) \(\dfrac{9}{11}\)
= \(\dfrac{9}{11}\) \(\times\)( \(\dfrac{5}{13}\) +\(\dfrac{8}{13}\))
= \(\dfrac{9}{11}\) \(\times\) 1
= \(\dfrac{9}{11}\)
Tính bằng cách thuận tiện:
a, 7/9 x 13/25 x 9/7
b, 5/9 x 21/25 + 21/25 x 4/9
c, 19/5 x 11/16 - 9/5 x 11/16
a) \(\dfrac{7}{9}\times\dfrac{13}{25}\times\dfrac{9}{7}=\left(\dfrac{7}{9}\times\dfrac{9}{7}\right)\times\dfrac{13}{25}=1\times\dfrac{13}{25}=\dfrac{13}{25}\)
b) \(\dfrac{5}{9}\times\dfrac{21}{25}+\dfrac{21}{25}\times\dfrac{4}{9}\)
\(=\dfrac{21}{25}\times\left(\dfrac{5}{9}+\dfrac{4}{9}\right)\)
\(=\dfrac{21}{25}\times1=\dfrac{21}{25}\)
c) \(\dfrac{19}{5}\times\dfrac{11}{16}-\dfrac{9}{5}\times\dfrac{11}{16}\)
\(=\dfrac{11}{16}\times\left(\dfrac{19}{5}-\dfrac{9}{5}\right)\)
\(=\dfrac{11}{16}\times2=\dfrac{22}{16}=\dfrac{11}{8}\)
tính bằng cách thuận tiện nhất:
a,7/4 x 11/21 + 11/21 x 5/4
b,23/14 x 6/13 -9/14 x 6/13
a, = \(\frac{11}{21}\)x \(\left(\frac{7}{4}+\frac{5}{4}\right)\)
= \(\frac{11}{21}\)x 3
= \(\frac{33}{21}\)
b) = \(\left(\frac{23}{14}-\frac{9}{14}\right)\)x \(\frac{6}{13}\)
= 1 x \(\frac{6}{13}\)
= \(\frac{6}{13}\)
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a)TÍNH BẰNG CÁCH THUẬN TIỆN
123 x 54 + 27 x 123 - 12 x 123 + 123 x 31
b)TÌM n
121/27 x 54/11 < n < 100/21 : 25/126
\(a,123\times54+27\times123-12\times123+123\times31\)
\(=123\times\left(54+27-12+31\right)\)
\(=123\times100\)
\(=12300\)
\(b,\dfrac{121}{27}\times\dfrac{54}{11}< n< \dfrac{100}{21}:\dfrac{25}{126}\)
\(22< n< \dfrac{100}{21}\times\dfrac{126}{25}\)
\(22< n< 24\)
Vì \(23>22\) và \(23< 24\) nên \(n=23\)
a)TÍNH BẰNG CÁCH THUẬN TIỆN
123 x 54 + 27 x 123 - 12 x 123 + 123 x 31
b)TÌM n
121/27 x 54/11 < n < 100/21 : 25/126
a123x54+27x123-12x123+123x31
=123:54+27:123-12:123+123:31
=6642+27:123-12:123+123:31
=6642+3321-12:123+123:31
=6642+3321-1476+123:31
=6642+3321-1476+3813
=12300
b,121/27x54/11<n>100/21:25/126
=22<n>24
n=23
{(-5/7)-7/9+9/11-11/13}x(3-3/4)
(10/21+14/27-6/11+22/39):(2-2/3)
Bài 3. Một hình bình hành có chiều cao là 5/7 m. Độ dài đáy gấp hai lần chiều cao, cạnh bên là 6/7m. Tính chu vi của hình bình hành.
Bài 4. Tính bằng cách thuận tiện nhất
a) 7/4 x 11/21 + 11/21 x 5/4 =
b) 23/14 x 6/13 - 9/14 x 6/13 =
Bài 4:
a: \(=\dfrac{11}{21}\left(\dfrac{7}{4}+\dfrac{5}{4}\right)=\dfrac{11}{21}\cdot3=\dfrac{11}{7}\)
b: \(=\dfrac{6}{13}\left(\dfrac{23}{14}-\dfrac{9}{14}\right)=\dfrac{6}{13}\)
Bài 3. Một hình bình hành có chiều cao là 5/7 m. Độ dài đáy gấp hai lần chiều cao, cạnh bên là 6/7m. Tính chu vi của hình bình hành.
Bài 4. Tính bằng cách thuận tiện nhất
a) 7/4 x 11/21 + 11/21 x 5/4 =
b) 23/14 x 6/13 - 9/14 x 6/13 =
Bài 4:
a: =11/21(7/4+5/4)=11/21x3=11/7
b: =6/13(23/14-9/14)=6/13