tìm y :
a/ y + y : 3 x 4.5 + y : 2 x 76 = 24
b / 71 + 65 x 4 = y + 140 : y + 260
Tìm y biết 71 +65 x 4 = y +140 / y +260
Ta có: \(71+\left(65\times4\right)=\frac{y+140}{y+260}\)
\(\Leftrightarrow331=\frac{y+140}{y+260}\)
\(\Leftrightarrow331\left(y+260\right)=y+140\)
\(\Leftrightarrow331y+86060=y+140\)
\(\Leftrightarrow331y-y=140-86060\)
\(\Leftrightarrow330y=-85920\)
\(\Leftrightarrow y=\frac{-85920}{330}=\frac{-2864}{11}\)
Bài 3 : Tìm y ,x
a) 71 + 65 x 4 = \(\frac{X+140}{X}+260\)
b) y x 15/2 - 1/3 x ( 1/4 + y ) = \(96\frac{2}{3}\)
\(a,\)\(71+65\times4=\frac{x+140}{x}+260\)
\(\Rightarrow71+260=\frac{x-140}{x}+260\)
\(\Rightarrow71=\frac{x-140}{x}\)
\(\Rightarrow71x=x-140\)
\(\Rightarrow71x-x=-140\)
\(\Rightarrow70x=-140\)
\(\Rightarrow x=-2\)
\(b,\)\(y\times\frac{15}{2}-\frac{1}{3}\times\left(\frac{1}{4}+y\right)=90\frac{2}{3}\)
\(\Rightarrow\frac{15y}{2}-\frac{1}{12}-\frac{y}{3}=\frac{272}{3}\)
\(\Rightarrow\frac{90y}{12}-\frac{1}{12}-\frac{4y}{12}=\frac{1088}{12}\)
\(\Rightarrow90y-1-4y=1088\)
\(\Rightarrow86y=1089\)
\(\Rightarrow y=\frac{1089}{86}\)
e) y x 9,2 + y : 0,25 - y x 3,2 = \(\frac{3}{4}x\left(1\frac{1}{2}-\frac{6}{8}\right)\) g) 71 + 65 x 4 = \(\frac{X+140}{X}+260\)
71+65*4 =y+140/y+260
1,
a, 20,2 x 5,1 - 30,3 x 3,4 + 14,58
14,58 x 460 + 7,29 + 540 x 2
b, 1/1000 + 13/1000 + 25/1000 + ...+ 97/1000 + 109/1000
2,
a, 6/8 = 15/x
b, (x+1) + (x + 4) + (x + 7) + ... + (x + 28) - 155
c, 71 + 65 x 4 = y + 140/y +260
a.1 là phân số nhé. Các bạn giúp mình với mình đang cần gấp
tìm y
71+65x4= ( y +140) : y + 260
Cho ba số x,y,z sao cho \(\frac{x}{3} = \frac{y}{4};\frac{y}{5} = \frac{z}{6}\)
a) Chứng minh: \(\frac{x}{{15}} = \frac{y}{{20}} = \frac{z}{{24}}\)
b) Tìm ba số x,y,z biết x – y + z = - 76
a) Ta có:
\(\begin{array}{l}\frac{x}{3} = \frac{y}{4} \Rightarrow \frac{x}{3}.\frac{1}{5} = \frac{y}{4}.\frac{1}{5} \Rightarrow \frac{x}{{15}} = \frac{y}{{20}};\\\frac{y}{5} = \frac{z}{6} \Rightarrow \frac{y}{5}.\frac{1}{4} = \frac{z}{6}.\frac{1}{4} \Rightarrow \frac{y}{{20}} = \frac{z}{{24}}\end{array}\)
Vậy \(\frac{x}{{15}} = \frac{y}{{20}} = \frac{z}{{24}}\) (đpcm)
b) Áp dụng tính chất của dãy tỉ số bằng nhau, ta có:
\(\frac{x}{{15}} = \frac{y}{{20}} = \frac{z}{{24}} = \frac{{x - y + z}}{{15 - 20 + 24}} = \frac{{ - 76}}{{19}} = - 4\)
Vậy x = 15 . (-4) = -60; y = 20. (-4) = -80; z = 24 . (-4) = -96
r)18*123+9*4567*2+5310*6 / (2+4+6+...+20+22)+48
d)71+65*4=y+140/y+260
b11:Hãy chứng tỏ rằng :
100 - {1+1/2+1/3+...+1/100} = 1/2+2/3+3/4+...+99/100
\(\frac{180\times123+9\times4567\times2+5310\times6}{\left(2+4+6+...+20+22\right)+48}\)
\(=\frac{18\times123+18\times4567+5310\times6}{132}\)
\(=\frac{116280}{132}=\frac{9690}{11}\)
Tìm Y :
a) 24 x y + 76 x y = 1000
b) 125 x y - 100 x y = 1000
a) \(24\times y+76\times y=100\)
\(\Rightarrow\left(24+76\right)\times y=100\)
\(\Rightarrow100\times y=100\)
\(\Rightarrow y=100:100\)
\(\Rightarrow y=1\)
b) \(125\times y-100\times y=1000\)
\(\Rightarrow\left(125-100\right)\times y=1000\)
\(\Rightarrow25\times y=1000\)
\(\Rightarrow y=1000:25\)
\(\Rightarrow y=40\)
a)\(=>y=1000:\left(24+76\right)=1000:100=10\)
b(\(=>y=1000:\left(125-100\right)=1000:25=40\)