a) \(\frac{\frac{2}{7}+\frac{2}{5}+\frac{2}{17}+\frac{2}{293}}{\frac{3}{7}+\frac{3}{5}+\frac{3}{17}+\frac{3}{293}}+\frac{\frac{7}{12}+\frac{5}{6}-1}{5-\frac{3}{4}+\frac{1}{3}}\) \(=\frac{2\left(\frac{1}{7}+\frac{1}{5}+\frac{1}{17}+\frac{1}{293}\right)}{3\left(\frac{1}{7}+\frac{1}{5}+\frac{1}{17}+\frac{1}{293}\right)}+\frac{\frac{5}{12}}{\frac{55}{12}}\)

\(=\frac{2}{3}+\frac{1}{11}=\frac{25}{33}\)

b) \(\left(1-\frac{1}{7}\right).\left(1-\frac{2}{7}\right)....\left(1-\frac{10}{7}\right)=\left(1-\frac{1}{7}\right).\left(1-\frac{2}{7}\right)...\left(1-\frac{7}{7}\right).\left(1-\frac{8}{7}\right).\left(1-\frac{9}{7}\right).\) \(\left(1-\frac{10}{7}\right)\) = 0

a)\(\frac{\frac{2}{7}+\frac{2}{5}+\frac{2}{17}+\frac{2}{293}}{\frac{3}{7}+\frac{3}{5}+\frac{3}{17}+\frac{3}{293}}+\frac{\frac{7}{12}+\frac{5}{6}-1}{5-\frac{3}{4}+\frac{1}{3}}\)

\(=\frac{2\left(\frac{1}{7}+\frac{1}{5}+\frac{1}{17}+\frac{1}{293}\right)}{3\left(\frac{1}{7}+\frac{1}{5}+\frac{1}{17}+\frac{1}{293}\right)}+\frac{\frac{7}{12}+\frac{10}{12}-\frac{12}{12}}{\frac{60}{12}-\frac{9}{12}+\frac{4}{12}}\)

\(=\frac{2}{3}+\frac{\frac{5}{12}}{\frac{55}{12}}\)

\(=\frac{2}{3}+\frac{1}{11}\)

\(=\frac{25}{33}\)

b)\(\left(1-\frac{1}{7}\right)\cdot\left(1-\frac{2}{7}\right)\cdot...\cdot\left(1-\frac{10}{7}\right)\)

Ta nhận thấy trong tích này có 1 thừa số là\(\left(1-\frac{7}{7}\right)=0\)nên tích trên sẽ bằng 0.

Ta có \(\frac{\frac{2}{7}+\frac{2}{5}+\frac{2}{17}+\frac{2}{293}}{\frac{3}{7}+\frac{3}{5}+\frac{3}{17}+\frac{3}{293}}+\frac{\frac{7}{12}+\frac{5}{6}-1}{5-\frac{3}{4}+\frac{1}{3}}\)

 = \(\frac{\frac{2}{7}+\frac{2}{5}+\frac{2}{17}+\frac{2}{293}}{\frac{3}{7}+\frac{3}{5}+\frac{3}{17}+\frac{3}{293}}+\frac{\frac{7}{12}+\frac{10}{12}-\frac{12}{12}}{\frac{60}{12}-\frac{9}{12}+\frac{4}{12}}\)

= \(\frac{2\left(\frac{1}{7}+\frac{1}{5}+\frac{1}{17}+\frac{1}{293}\right)}{3\left(\frac{1}{7}+\frac{1}{5}+\frac{1}{17}+\frac{1}{293}\right)}+\frac{\frac{5}{12}}{\frac{55}{12}}\)

=     \(\frac{2}{3}+\frac{1}{11}\)

=       \(\frac{25}{33}\)

\(A=2\frac{1}{2}\)

ồ cuk dễ nhỉ

Nếu các bn thích thì ...........

cứ cho NTN này nhé !

a) \(\frac{3}{5}.x-\frac{1}{5}=\frac{4}{5}\)

\(\Leftrightarrow\frac{3}{5}.x=\frac{4}{5}+\frac{1}{5}\)

\(\Leftrightarrow\frac{3}{5}.x=1\)

\(\Leftrightarrow x=1:\frac{3}{5}\)

\(\Leftrightarrow x=\frac{5}{3}\)

Vậy : \(x=\frac{5}{3}\)

b) \(\frac{4}{7}+\frac{5}{7}:x=1\)

\(\Leftrightarrow\frac{5}{7}:x=1-\frac{4}{7}\)

\(\Leftrightarrow\frac{5}{7}:x=\frac{3}{7}\)

\(\Leftrightarrow x=\frac{5}{7}:\frac{3}{7}\)

\(\Leftrightarrow x=\frac{5}{3}\)

Vậy : \(x=\frac{5}{3}\)

c) \(-\frac{12}{7}.\left(\frac{3}{4}-x\right).\frac{1}{4}=-1\)

\(\Leftrightarrow\frac{-12.1}{7.4}.\left(\frac{3}{4}-x\right)=-1\)

\(\Leftrightarrow-\frac{3}{7}.\left(\frac{3}{4}-x\right)=-1\)

\(\Leftrightarrow\frac{3}{4}-x=-1:\left(-\frac{3}{7}\right)\)

\(\Leftrightarrow\frac{3}{4}-x=\frac{7}{3}\)

\(\Leftrightarrow x=\frac{3}{4}-\frac{7}{3}=-\frac{19}{12}\)

Vậy : \(x=-\frac{19}{12}\)

d) \(x:\frac{17}{8}=-\frac{2}{5}.-\frac{9}{17}+3\)

\(\Leftrightarrow x:\frac{17}{8}=\frac{273}{85}\)

\(\Leftrightarrow x=\frac{273}{85}.\frac{17}{8}\)

\(\Leftrightarrow x=\frac{273}{40}\)

Vậy : \(x=\frac{273}{40}\)

\(\)

A=\([\)\(\frac{2}{7}\)\(\times\)(\(\frac{1}{4}-\frac{1}{3}\))\(]\)\(\div\)\([\)(\(\frac{2}{7}\times\)(\(\frac{3}{9}-\frac{2}{5}\))\(]\)
  =(\(\frac{2}{7}\times\)\(\frac{-1}{12}\))\(\div(\)\(\frac{2}{7}\times\)\(\frac{-1}{15}\))
=\(\frac{-1}{42}\)\(\div\)\(\frac{-2}{35}\)
=\(\frac{-1}{42}\)\(\times\)\(\frac{35}{-2}\)
=\(\frac{5}{12}\)

a) $\frac{1}{6} \times \frac{2}{3} = \frac{{1 \times 2}}{{6 \times 3}} = \frac{2}{{18}} = \frac{1}{9}$                            

b) $\frac{6}{5} \times \frac{3}{8} = \frac{{6 \times 3}}{{5 \times 8}} = \frac{{18}}{{40}} = \frac{9}{{20}}$

c) $\frac{4}{3} \times \frac{8}{9} = \frac{{4 \times 8}}{{3 \times 9}} = \frac{{32}}{{27}}$        

d) $\frac{5}{{12}} \times \frac{{12}}{5} = \frac{{5 \times 12}}{{12 \times 5}} = \frac{{60}}{{60}} = 1$

\(A=\frac{17\frac{2}{4}\cdot\frac{17}{5}+3\frac{2}{5}\cdot82\frac{1}{4}}{2\cdot34-3\cdot17}\)

\(A=\frac{\frac{71}{4}\cdot\frac{17}{5}+\frac{17}{5}\cdot\frac{329}{4}}{68-51}\)

\(A=\frac{\frac{17}{5}\cdot\left(\frac{71}{4}+\frac{329}{4}\right)}{17}=\frac{\frac{17}{5}\cdot100}{17}\)

\(\Rightarrow A=\frac{340}{17}=20\)

dùng máy tih đc mà