Đặt\(\begin{cases} x+y=S \\ xy=P \end{cases}\)

Ta có:\(\begin{cases} S-2P=0 \\ S-P^2=\sqrt{(P-1)^2+1} \end{cases}\)

\(\Leftrightarrow\)\(\begin{cases} S=2P \\ 2P-P^2=\sqrt{(P-1)^2+1} \end{cases}\)

\(\Leftrightarrow\)\(\begin{cases} S=2P \\ (2P-P^2)^2=(P-1)^2+1 \end{cases}\)

\(\Leftrightarrow\)\(\begin{cases} S=2P \\ 4P^2-4P^3+P^4=P^2-2P+2 \end{cases}\)

\(\Leftrightarrow\)\(\begin{cases} S=2P \\ P^4-4P^3+3P^2+2P-2=0 \end{cases}\)

\(\Leftrightarrow\)\(\begin{cases} S =2+2\sqrt{3}\\ P=1+\sqrt{3} \end{cases}\)(1)hoặc\(\begin{cases} S=2 \\ P=1 \end{cases}\)(2)hoặc\(\begin{cases} S=2-2 \sqrt{3}\\ P=1-\sqrt{3} \end{cases}\)(3)

Còn lại là thay vào biểu thức x²-Sx+P=0 thôi

I

1 will have

2 would have

3 have

4 had

5 will make

6 would make

7 has

8 had

9 is

10 were

II

1 have

2 had

3 had had

4 will go

5 would go

6 would have gone

7 is

8 were - would visit

9 had been - would have visited

10 wouldn't be - were

I.

1. will have

2. would have

3. have

4. had

5. will made

6. would made

7. has

8. had

9. is

10. were

II.

1. have

2. had

3. had had

4. will go

5. would go

6. would have gone

7. is

8. were - would visit

9. had been - would have visited

10. will not be - is

Bài 2 :

a, Ta có đồ thị :

b, Ta có : \(\tan a=3\)

\(\Rightarrow a\approx71,5^o\)

KO BIẾT LÀM NHA BẠN!!!!!!!!!!!!!!!!

Bài 3:

(1) \(N_2+3H_2⇌2NH_3\)

(2) \(NH_3+HNO_3\rightarrow NH_4NO_3\)

(3) \(NH_4NO_3+KOH\rightarrow KNO_3+NH_3+H_2O\)

(4) \(N_2+O_2\xrightarrow[]{t^ocao}2NO\)

(5) \(NO+\dfrac{1}{2}O_2\rightarrow NO_2\)

(6) \(4NO_2+O_2+2H_2O\rightarrow4HNO_3\)

(7) \(4HNO_{3\left(đ\right)}+Cu\rightarrow Cu\left(NO_3\right)_2+2NO_2+2H_2O\)

(8) \(HNO_3+NH_3\rightarrow NH_4NO_3\)

THAM KHẢO:

1 B

2 C

3 C

4 D

5 A

6 A

7 C

8 C

9 B

10 D

11 D

12 B

13 B

14 D

15 A

16 B

17 D

18 D

19 C

20 D

21 C

22 B

23 B

24 B

25 A

26 D

27 A