a: Ta có: \(\left(x+2\right)\left(x^2-2x+4\right)-x\left(x^2+2\right)=15\)

\(\Leftrightarrow x^3+8-x^3-2x=15\)

\(\Leftrightarrow2x=-7\)

hay \(x=-\dfrac{7}{2}\)

b: Ta có: \(\left(x-2\right)^3-\left(x-4\right)\left(x^2+4x+16\right)+6\left(x+1\right)^2=49\)

\(\Leftrightarrow x^3-6x^2+12x-8-x^3+64+6\left(x+1\right)^2=49\)

\(\Leftrightarrow-6x^2+12x+56+6x^2+12x+6=49\)

\(\Leftrightarrow24x=-13\)

hay \(x=-\dfrac{13}{24}\)

a) (x - 2)³ - (x - 3)(x² + 3x + 9) + 6(x + 1)²=49

=> x³ - 6x² + 24x - 8 - x³ + 3x² - 3x² + 9x - 9x + 27 + 6x² + 12x +6 = 49

=> 36x + 25 - 49 = 0 => 36x - 24 = 0 => x = 2/3

b) (x + 2)(x² - 2x + 4)-x(x² + 2)=15

=> x³ + 2x² - 2x² - 4x + 4x + 8 - x3 - 2x = 15

=> 8 - 2x - 15 = 0 => -2x - 7 = 0 => x = -7/2

a) \(x:\frac{2}{3}=150\) 

\(x=150.\frac{2}{3}\) 

\(x=100\) 

b) \(\frac{35}{9}:x=\frac{35}{6}\) 

\(x=\frac{35}{9}.\frac{6}{35}=\frac{2}{3}\) 

c,d tương tự

a )  x : 2/3 = 150                                               c ) x : 4/7 = 180

     x         =    150 x 2/3                                        x         =    180 x  4/7

     x         =       100                                             x         =            720/7

b ) 35/9 : x  = 35/6                                             d )      49/8 : x  = 49/5 

              x  =  35/9 : 35/6                                                      x  =   49/8 : 49/5

             x   =     2/3                                                              x  =   5/8        

a) x : \(\frac{2}{3}\)= 150

   x = 150 x \(\frac{2}{3}\)

   x = 100

b) \(\frac{35}{9}:x=\frac{35}{6}\)

    x = \(\frac{35}{9}\): \(\frac{35}{6}\)

x = \(\frac{2}{3}\)

c) x : 4/7 = 180

x = 180 x 4/7

x = 720/7

d) 49/8 : x = 49/5

x = 49/8 : 49/5

x = 5/8

nhớ k cho mik nha mik đang rất cần cái k của bn

\(a,\left(x+1\right)^2=x+1\)

\(\left(x+1\right)^2-\left(x+1\right)=0\)

\(\left(x+1\right)\cdot\left(x+1-1\right)=0\)

\(x\cdot\left(x+1\right)=0\)

\(\hept{\begin{cases}x=0\\x+1=0\end{cases}\Rightarrow\hept{\begin{cases}x=0\\x=-1\end{cases}}}\)

\(\left(x-2\right)^3-\left(x-3\right)\left(x^2+3x+9\right)+6\left(x+1\right)^2=49\)

\(\Leftrightarrow x^3-6x^2+12x-8-\left(x^3-27\right)+6\left(x^2+2x+1\right)=49\)

\(\Leftrightarrow x^3-6x^2+12x-8-x^3+27+6x^2+12x+6=49\)

\(\Leftrightarrow24x+25=49\)

\(\Leftrightarrow24x=24\Leftrightarrow x=1\)

`(5x+1)=36/49`

`<=> 5x = 36/49-1`

`<=> 5x = -13/49`.

`<=> x = -13/245.`

Vậy `x = -13/245`.

`b, x-2/9 = 2/3`.

`<=> x = 2/3 + 2/9`

`<=> x = 8/9`.

Vậy `x = 8/9`.

c: (8x-1)^(2x+1)=5^(2x+1)

=>8x-1=5

=>8x=6

=>x=3/4

d: Sửa đề: (x-3,5)^2+(y-1/10)^4=0

=>x-3,5=0 và y-0,1=0

=>x=3,5 và y=0,1

a)

x − 5 12 − 4 9 = − 13 18 x = − 13 18 + 5 12 + 4 9 x = − 26 36 + 15 36 + 16 36 x = 5 36

b)

2 − x + 3 7 = 9 − 21 2 − x − 3 7 = − 3 7 − x = − 3 7 + 3 7 − 2 − x = − 2 ⇒ x = 2

a)

\(\left(x+2\right)^2-9=0\)

\(\Rightarrow\left(x+2\right)^2=9=3^2\)

\(\Rightarrow x+2=\pm3\)

\(\Rightarrow x=-5;1\)

b)

\(25x^2-10x+1=0\)

\(\left(5x\right)^2-2\cdot5x+1^2=0\)

\(\Rightarrow\left(5x+1\right)^2=0\)

\(\Rightarrow5x+1=0\)

\(\Rightarrow5x=-1;x=\dfrac{-1}{5}\)

c)

\(x^2+14x+49=0\)

\(\Rightarrow x^2+2\cdot7x+7^2=0\)

\(\Rightarrow\left(x+7\right)^2=0;x+7=0\)

\(\Rightarrow x=-7\)

d)

\(\left(2x-1\right)^2+\left(x+3\right)^2-5\left(x+7\right)\left(x-7\right)=0\)

\(4x^2-4x+1+x^2+6x+9-5x^2+5\cdot49=0\)

\(\Rightarrow5x^2-5x^2-4x+6x+10+245=0\)

\(\Rightarrow2x+255=0\)

\(\Rightarrow2x=-255\)

\(\Rightarrow x=\dfrac{-255}{2}\)

a) 3x + 27 = 9

=> 3x = 9 - 27

=> 3x = -18

=> x = -18 : 3

=> x = -6

b) 2x + 12 = 3(x - 7)

=> 2x + 12 = 3x - 3 . 7

=> 2x + 12 = 3x - 21

=> 3x - 2x = 21 - 12

=> x = 9

c) 2x . 2 - 1 = 49

=> 2x . 2 = 49 + 1

=> 2x . 2 = 50

=> 2x = 50 : 2

=> 2x = 25

=> x =25 : 2

=> x = 25/2

d) |-9 - x| - 5 = 12

=> |-9 - x| = 12 + 5

=> |-9 - x| = 17

=> \(\orbr{\begin{cases}-9-x=17\\-9-x=-17\end{cases}}\)

=> \(\orbr{\begin{cases}x=-9-17\\x=-9-\left(-17\right)\end{cases}}\)

=> \(\orbr{\begin{cases}x=-26\\x=8\end{cases}}\)

3x + 27 = 9

        3x = 9 - 27

         3x = - 18

           x = - 6

b, 2x + 12 = 3.( x - 7 )

    2x + 12 = 3x - 21

     2x - 3x = - 21 - 12

            - x = - 33

              x = 33

c, 2x² - 1 = 49

=> 2x² = 49 + 1

=> 2x² = 50

=> x² = 50 : 2

=> x² = 25

=> x = 5 hoặc x = - 5

d, | - 9 - x | - 5 = 12

         | - 9 - x | = 12 + 5 

         | - 9 - x | = 17

=> - 9 - x = 17 hoặc - 9  - x = - 17

=> x = - 26 hoặc x = 8

S=1-2+3-4+...+99-100