Đề bài sai, pt này ko giải được

Đề đúng: \(\dfrac{4x^2+16}{x^2+6}=...\)

Mẫu số bên trái thừa mất số 1

a, \(\left(\frac{4}{9}.\frac{3}{7}\right).\frac{7}{4}=\frac{4}{9}\left(\frac{3}{7}.\frac{7}{4}\right)=\frac{4}{9}.\frac{3}{4}=\frac{3}{9}=\frac{1}{3}\)

b, \(\left(\frac{6}{5}.\frac{4}{5}\right).\frac{25}{16}=\frac{6}{5}\left(\frac{4}{5}.\frac{25}{16}\right)=\frac{6}{5}.\frac{5}{4}=\frac{6}{4}=\frac{3}{2}\)

c, \(\left(\frac{7}{8}.\frac{16}{9}\right).\frac{3}{14}=\frac{7}{8}\left(\frac{16}{9}.\frac{3}{14}\right)=\frac{7}{8}.\frac{8}{21}=\frac{7}{21}=\frac{1}{3}\)

a, $\left(\frac{4}{9}.\frac{3}{7}\right).\frac{7}{4}=\frac{4}{9}\left(\frac{3}{7}.\frac{7}{4}\right)=\frac{4}{9}.\frac{3}{4}=\frac{3}{9}=\frac{1}{3}$

b, $\left(\frac{6}{5}.\frac{4}{5}\right).\frac{25}{16}=\frac{6}{5}\left(\frac{4}{5}.\frac{25}{16}\right)=\frac{6}{5}.\frac{5}{4}=\frac{6}{4}=\frac{3}{2}$

c, $\left(\frac{7}{8}.\frac{16}{9}\right).\frac{3}{14}=\frac{7}{8}\left(\frac{16}{9}.\frac{3}{14}\right)=\frac{7}{8}.\frac{8}{21}=\frac{7}{21}=\frac{1}{3}$

( 4/9 x 3/7 ) x 7/4 = 4/9 x ( 3/7 x 7/4 ) =4/9 x 21/28 = 84/252

( 6/5 x 4/5 ) x 25/16 = ( 25/16 x 4/5 ) x 6/5 = 100/80 x 6/5 = 600/400

quy đồng ra nhé

( 7/6 + 5/16 + 3/16) x 1/5

= ( 7/6 + 1/2) x 1/5

= ( 7/6 + 3/6) x 1/5

= 10/6 x 1/5

= 5/3 x 1/5 

=1/3

1/5 x 7/6 + 1/5 x 5/16 + 1/5 x 3/16
=1/5 x (7/6 + 5/16 + 3/16)
=1/5 x (7/6 + 1/2)
=1/5 x (7/6 + 3/6)
=1/5 x 10/6
=2/6=1/3

\(5\left(x-3\right)=25\)

\(x-3=25:5=5\)

\(x=5+3=8\)

\(x-3=5=5x=8\)

Hình như sai đề

\(10+2x=16\)

\(2x=6\)

\(x=3\)

mik còn k pit bn hỏi cái dj

trong sách bt

X - 6/5 = 4

X = 4 + 6/5

X= 26/5

X x 4/5 = 23/20

X = 23/20 : 4/5

X = 23/16

8/5

686/65

5/7

3/5+7/12+5/12

=3/5+(7/12+5/12)

=3/5+1

=8/5

a.3/5+1=8/5

b.4/26+52/5=686/65

c.(9/16+7/16)*5/7=1*5/7=5/7