a)5/8 < 8/9

b)8/12> 5/9

c)7/12 < 11/18

a)5/8 < 8/9

b)8/12 > 5/9

c)7/12 < 11/18

a) 5/8 < 8/9

b) 8/12 > 5/9

c) 7/12 < 11/18

a, \(\dfrac{1}{3}\) và \(\dfrac{5}{12}\)

Ta có: \(\dfrac{1}{3}=\dfrac{1\times4}{3\times4}=\dfrac{4}{12};\dfrac{5}{12}\) giữ nguyên

Vì \(4< 5\) nên \(\dfrac{4}{12}< \dfrac{5}{12}\) 

b, \(\dfrac{5}{9}\) và \(\dfrac{8}{3}\)

Ta có: \(\dfrac{5}{9}< 1;\dfrac{8}{3}>1\)

Vậy \(\dfrac{5}{9}< \dfrac{8}{3}\)

c, \(\dfrac{6}{15}\) và \(\dfrac{2}{5}\)

Ta có: \(\dfrac{6}{15}=\dfrac{6\div3}{15\div3}=\dfrac{2}{5}\)

Vậy \(\dfrac{6}{15}=\dfrac{2}{5}\)

chịch

quên cách làm rồi

gì mà thế

Dùng so sánh trung gian : 

\(\frac{7}{9}< 1< \frac{9}{8}\Rightarrow\frac{7}{9}< \frac{9}{8}\)

\(\frac{8}{12}< 1< \frac{16}{10}\Rightarrow\frac{8}{12}< \frac{16}{10}\)

\(\dfrac{36}{23}>\dfrac{36}{24}=\dfrac{3}{2}\)

\(\dfrac{27}{21}< \dfrac{27}{18}=\dfrac{3}{2}\)

\(\Rightarrow\dfrac{36}{23}>\dfrac{27}{21}\)

\(\dfrac{36}{23}>\dfrac{3}{2}\)

\(\dfrac{3}{2}>\dfrac{27}{21}\)

Do đó: \(\dfrac{36}{23}>\dfrac{27}{21}\)

Cảm ơn

\(\frac{22}{27}+\frac{37}{67}=\left(1-\frac{5}{27}\right)+\left(1-\frac{30}{67}\right)\)

\(\frac{31}{36}+\frac{377}{677}=\left(1-\frac{5}{36}\right)+\left(1-\frac{300}{677}\right)\)

+ \(\frac{5}{27}>\frac{5}{36}\Rightarrow1-\frac{5}{27}< 1-\frac{5}{36}\left(1\right)\)

+ \(\frac{30}{67}=\frac{300}{670}>\frac{300}{677}\Rightarrow1-\frac{30}{67}< 1-\frac{300}{677}\) (2)

Từ (1) và (2) \(\Rightarrow\frac{22}{27}+\frac{37}{67}< \frac{31}{36}+\frac{377}{677}\)

Vsu

a) \(1-\frac{13}{17}=\frac{4}{17}\) và \(1-\frac{15}{19}=\frac{4}{19}\)

Vì 4/17 > 4/19 nên 13/17 < 15/19      

b) \(\frac{12}{48}=\frac{1}{4}\) và \(\frac{9}{36}=\frac{1}{4}\)

Vậy 12/48 = 9/36

13/17<15/19

12/48=9/36

**** tớ nhha

ta có thể lấy 4/17+13/17=1.

ta có thể lấy 4/19+15/19=1

ta so sanh 4/17 > 4/19

nên 13/17 > 15/19