a.1+3+5+7+...+2x+1=225

[(2x+1-1):2+1]x(2x+1+1):2=225

(x+1)x(2x+2):2=225

(x+1)x(x+1)=225

(x+1)²=225

(x+1)²=15²

x+1=15

x=14

_______________

b. 130-[5.(9-x)+43]=47

    5.(9-x)+43=83

  5.(9-x)=40

9-x=8

x=1

_______________

c.16^x<32⁴

2^4x<2²⁰

=>x∈{0;1;2;3;4}

a: =>(x+1)^2=225

=>x+1=15

=>x=14

b: =>[5*(9-x)+43]=130-47=83

=>5(9-x)=40

=>9-x=8

=>x=1

c: =>2^4x<2^20

=>4x<20

=>0<x<5

a) 5^x = 125

5^x = 5³

=> x = 3

b) x³ = 64

x³ = 4³

=> x = 4

c) ( x - 1 ) ² = 25

( x - 1 ) ² = 5²

=> x - 1 = 5

=> x = 5 + 1

=> x = 6

d) 5^x + 5^x+2 = 130

5^x . 1 + 5^x . 5² = 130

5^x . ( 1 + 5² ) = 130

5^x . 26 = 130

5^x = 130 : 26

5^x = 5

=> x = 1

\(a.\)\(5^x=125\)

\(5^x=5^3\Rightarrow x=3\)

\(b.\)\(x^3=64\)

\(x^3=4^3\Rightarrow x=4\)

\(c.\)\(\left(x-1\right)^2=25\)

\(x^2=5^2\)mà \(\left(x-1\right)\)nên \(x=5+1=6\)

P/s: Ý d thiếu nhé bạn 

a)5^x=125

5^x=5³

=>x=3

b)tương tụ câu a

c)(x-1)²=25

(x-1)²=5²

=>x-1=5

x=5+1

x=6

d)thiếu đề!

a) x=50-37

x= 13

b) 2.x=11+3

2.x=14

x=14:2=7

c) 2+x=6.5

2.x=30

x=30:2=15

e) \(^{^{^{ }}x^9}\)=25

\(\Rightarrow\)x=5

mình viết sai câu e  là x mũ 4 mới đúng

  Bài 1:

2^\(x\) = 4

2\(^x\) = 2²

 \(x=2\)

Vậy \(x=2\)

Bài 2:

2\(^x\) = 8

2\(^x\) = 2³

\(x=3\)

Vậy \(x=3\)

Bài 3

2\(^x\) = 16

2\(^x\) = 2⁴

  \(x=4\)

Vậy \(x=4\)

Bài 1

a) \(x=x^5\)

\(x^5-x=0\)

\(x\left(x^4-1\right)=0\)

\(x=0\) hoặc \(x^4-1=0\)

* \(x^4-1=0\)

\(x^4=1\)

\(x=1\)

Vậy x = 0; x = 1

b) \(x^4=x^2\)

\(x^4-x^2=0\)

\(x^2\left(x^2-1\right)=0\)

\(x^2=0\) hoặc \(x^2-1=0\)

*) \(x^2=0\)

\(x=0\)

*) \(x^2-1=0\)

\(x^2=1\)

\(x=1\)

Vậy \(x=0\); \(x=1\)

c) \(\left(x-1\right)^3=x-1\)

\(\left(x-1\right)^3-\left(x-1\right)=0\)

\(\left(x-1\right)\left[\left(x-1\right)^2-1\right]=0\)

\(x-1=0\) hoặc \(\left(x-1\right)^2-1=0\)

*) \(x-1=0\)

\(x=1\)

*) \(\left(x-1\right)^2-1=0\)

\(\left(x-1\right)^2=1\)

\(x-1=1\) hoặc \(x-1=-1\)

**) \(x-1=1\)

\(x=2\)

**) \(x-1=-1\)

\(x=0\)

Vậy \(x=0\); \(x=1\); \(x=2\)

a. 3^x+3^x+1+3^x+2=1053

=> 3^x.(1+3+3²)=1053

=> 3^x.(1+3+9)=1053

=> 3^x.13=1053

=> 3^x=1053:13

=> 3^x=81

=> 3^x=3⁴

=> x=4

b. 5^x.5¹⁹=5²⁰.5¹¹

=> 5^19+x=5²⁰⁺¹¹

=> 19+x=20+11

=> 19+x=31

=> x=31-19

=> x=12

\(3^x+3^{x+1}+3^{x+2}=1053\)

\(3^x\left(1+3+3^2\right)=1053\)

\(3^x\cdot13=1053\)

\(3^x=1053:13=81\)

\(3^x=3^4\)

=> x = 4 

A)x=4

B)x=12 100% đó

Bài 2

a) x=5

b)x=1

Bài 9,

6²x73+36x3³=36x73+36x27=36(73+27)=36x100=3600.

197-\([\)6x(5-1)²+2022⁰\(]\):5=197-\([\)6x16+1\(]\):5=197-97:5=197-97/5=888/5.

Bài 10,

21-4x=13

=>4x=21-13=8

=>x=8:4=2.

30:(x-3)+1=4⁵:4³=4²=16

=>30:(x-3)=16-1=15

=>x-3=30:15=2

=>x=2+3=5.

(x-1)³+5x6=38

=>(x-1)³+30=38

=>(x-1)³=38-30=8=2³

=>x-1=2

=>x=3.