Ta có : A = -(a - b + c) - (-a - b - c)

= -a + b - c + a - b + c

= 0

A = (-a - b + c) - (-a - b - c)

= -a - b + c + a + b + c

= (-a + a) + (-b + b) + (c + c)

= 2c

Vậy A = 2c.

A=  (-a-b+c) - (-a- b- c)

= -a-b+c+a- b- c

= (-a+a) + (-b+b) + (c+c) Đã đổi dấu 

= 2c

=> A = 2c

\(M=\left(-a+b-c\right)+\left(a-b\right)-\left(a-b+c\right)\)

\(=-a+b-c+a-b-a+b-c\)

=-a+b-2c

a: =b-c-a+c+1-a-b+c

=-2a+1

b: =a-b-c-b+c+a+c-b-a

=c-3b+a

c: =2(a-b-b+c-c+a)

=2(2a-2b)

=4a-4b

a) \(\left(b-c\right)-\left(a-c-1\right)-\left(a+b-c\right)\)

\(=b-c-a+c+1-a-b+c\)

\(=c-2a+1\)

b) \(\left(a-b-c\right)-\left(b-c-a\right)+\left(c-b-a\right)\)

\(=a-b-c-b+c+a+c-b-a\)

\(=a-3b+c\)

c) \(2\cdot\left(a-b\right)-2\cdot\left(b-c\right)-2\cdot\left(c-a\right)\)

\(=2\cdot\left(a-b-b+c-c+a\right)\)

\(=2\cdot\left(2a-2b\right)\)

\(=4a-4b\)

A = (-a + b - c) - (-a - b - c)

= -a + b - c + a + b + c

= (a - a) + (b + b) + (c - c)

= 0 + 2b + 0

= 2b

 A = ( -a + b - c) - (-a - b - c)

= -a + b - c + a + b + c

= 2b

Cho biểu thức: A = (-a + b - c) - (-a - b - c)

Rút gọn biểu thức A

Giải:

A = (-a + b - c) - (-a - b - c)

Chuyển hai vế ta được:

A = (-a + a) + (b + b) + (-c + c)

A = 0 + 2b + 0

A = 2b

A= -a+b-c+a+b+c =(-a+a) +b+b +(-c+c)

  =  2xb

=a+b+a-b+c=2a+c

A=a(2b-c-c-b)-b(a+c)

=a(b-2c)-b(a+c)

=ab+2ac-ab-bc

=2ac-bc