P=5x3^11+4x3^12/3^9x5^2-3^9x2^3
Tính P.cần khẩnn cấp nha!!!
5x3^11+4x3^12 /3^9x5^2-3^9x2^2
Các tìm kiếm liên quan đến tinh gia tri bieu thuc :(5x3^11+4x3^12):(3^9x5^2-3^9x2^3)
Thực hiên phép tính bằng cách hợp lý:
p=(5x3^11+4x3^12):(3^9x5^2-3^9x2^3)
Q=14x29+14x17+(1+2+3+4+5+....+99)x(199199x198-198198x199)
b)
chứng minh rằng 1x3x5x...x2013x2015+2x4x6x....x2014x2016 chia hết cho 9911
Tính nhanh a) 5x4+9x5-5x3-10. b)4x7+4x6-4x3-4
a, 5 x 4 + 9 x 5 - 5 x 3 - 10
= 5 x ( 4 + 9 - 3) - 10
= 5 x ( 13 - 3) - 10
= 5 x 10 - 10
= 40
b, 4 x 7 + 4 x 6 - 4 x 3 - 4
= 4 x 7 + 4 x 6 - 4 x 3 - 4 x1
= 4 x ( 7 + 6 - 3 -1)
= 4 x 9
= 36
`5xx4+9xx5-5xx3-10`
`= 5 xx (4+9-3 -10)`
`= 5 xx 0`
`=0`
`-----`
`4 xx7 + 4 xx6 - 4xx3-4`
`=4 xx7 + 4 xx6 - 4xx3-4 xx 1`
`= 4xx (7+6-3-1)`
`= 4 xx 9`
`=36`
5.4 + 9.5 - 5.3 - 10
=5.4 + 9.5 - 5.3 - 5.2
=5.(4 + 9 - 3 - 2 )
=5. 8
= 40
b, 4 . 7 + 4 . 6 - 4 . 3 - 4
=4. ( 7 + 6 - 3 - 1 )
= 4. 9
= 36
P=5x311+4x312/39x52-39x22
P = \(\frac{5.3^{11}+4.3^{12}}{3^9.5^2-3^9.2^2}\)
= \(\frac{\left(5+4.3\right).3^{11}}{3^9.\left(5^2-2^2\right)}\)
=\(\frac{17.3^{11}}{3^9.21}\)
= \(\frac{17.3^2}{7.3}\)
= \(\frac{17.3}{7}=\frac{51}{7}\)
Giải các phương trình sau:
a, (9x2 - 4)(x + 1) = (3x +2)(x2 - 1)
b, (x - 1)2 - 1 + x2 = (1 - x)(x + 3)
c, (x2 - 1)(x + 2)(x - 3) = (x - 1)(x2 - 4)(x + 5)
d, x4 + x3 + x + 1 = 0
e, x3 - 7x + 6 = 0
f, x4 - 4x3 + 12x - 9 = 0
g, x5- 5x3 + 4x = 0
h, x4 - 4x3 + 3x2 + 4x - 4 = 0
a, \(\Leftrightarrow\left(9x^2-4\right)\left(x+1\right)-\left(3x+2\right)\left(x-1\right)\left(x+1\right)=0\)
\(\Leftrightarrow\left(x+1\right)\left(\left(9x^2-4\right)-\left(\left(3x+2\right)\left(x-1\right)\right)\right)=0\)
\(\Leftrightarrow\left(x+1\right)\left(9x^2-4-\left(3x^2-x-2\right)\right)=0\)
\(\Leftrightarrow\left(x+1\right)\left(9x^2-4-3x^2+x+2\right)=0\)
\(\Leftrightarrow\left(x+1\right)\left(3x^2+x-2\right)=0\)
\(\Leftrightarrow\left(x+1\right)=0;3x^2+x-2=0\)
=> x=-1
với \(3x^2+x-2=0\)
ta sử dụng công thức bậc 2 suy ra : \(x=\dfrac{2}{3};x=-1\)
Vậy ghiệm của pt trên \(S\in\left\{-1;\dfrac{2}{3}\right\}\)
b: \(\Leftrightarrow x^2-2x+1-1+x^2=x+3-x^2-3x\)
\(\Leftrightarrow2x^2-2x=-x^2-2x+3\)
\(\Leftrightarrow3x^2=3\)
hay \(x\in\left\{1;-1\right\}\)
c: \(\Leftrightarrow\left(x-1\right)\left(x+1\right)\left(x+2\right)\left(x-3\right)-\left(x-1\right)\left(x-2\right)\left(x+2\right)\left(x+5\right)=0\)
\(\Leftrightarrow\left(x-1\right)\left(x+2\right)\left[\left(x+1\right)\left(x-3\right)-\left(x-2\right)\left(x+5\right)\right]=0\)
\(\Leftrightarrow\left(x-1\right)\left(x+2\right)\left(x^2-2x-3-x^2-3x+10\right)=0\)
\(\Leftrightarrow\left(x-1\right)\left(x+2\right)\left(-5x+7\right)=0\)
hay \(x\in\left\{1;-2;\dfrac{7}{5}\right\}\)
giải phương trình sau:
a. (9x2-4)(x+1) = (3x+2) (x2-1)
b. (x-1)2-1+x2 = (1-x)(x+3)
c. (x2-1)(x+2)(x-3) = (x-1)(x2-4)(x+5)
d. x4+x3+x+1=0
e. x3-7x+6 = 0
f. x4-4x3+12x-9 = 0
g. x5-5x3+4x = 0
h. x4-4x3+3x2+4x-4 = 0
m.n jup vs
bài 1 tính
2 3 phần 4 : 1 1phần 3
bài 2 tính nhanh
a) 12x -7/11x5/6x22/7 b) -8/15x7/9x5/8x(-18)
c) -5/11x13/28-13/28x6/11 d) 4/9.7/11+4/9x6/11-4/9x2/11
e) 11/22-3/16x8/18+1/18
giúp mik với ah =))
bài 1:
\(2\dfrac{3}{4}:1\dfrac{1}{3}=\dfrac{11}{4}:\dfrac{4}{3}=\dfrac{33}{16}\)
tính nhanh
(3^8x11+3^9x5):3^9x2^4