125+163+12=
1. (-12)+(-15)+(-31) | 2. 25+37-59 | 3. (-12)+13-(-60)
4. 24:(-2)+(-5) | 5. 32.(-2)+64 | 6. 18.3+(-50):5
7. (-24)+37+163+(-176) | 8. 125+217+(-625)+529 | 9. 29+132+237+868+763
10. (-87)+126+187+74 | 11. 29.87+29.13 | 12. 123.(-29)-23.(-29)
13. 31.(-18)+31.(-81)-31 | 14.(-12).47+(-12).52+(-12) | 15. 24.(16-5)-16.(24-5)
16. 29.(29-3)-19.(29-13) | 17. -452-(-67+75-452) | 18. -(-171+89+223)-(71-111)+223
19. 21.83-3.7.(-17) | 20. 35-{12-[-14+(-2)]} | 21.5+10+15+20+....+1000
22. 3-6+9-12+....+195-198
a) 73+362+163+138+27+237
b) 54.56.58+3.22-100
c) A=12:{390:[500-(125+35.7]}
a) 73 + 362 + 163 + 138 + 27 + 237
= (73 + 27) + (362 + 138) + (163 + 237)
= 100 + 500 + 400
= 1000
b) \(5^4\cdot5^6+3\cdot2^2-10^0\)
\(=5^{10}+3\cdot4-1\)
\(=9765625+12-1\)
\(=9765636\)
c) \(A=12:\left\{390:\left[500-\left(125+35\cdot7\right)\right]\right\}\)
\(=12:\left\{390:\left[500-\left(125+245\right)\right]\right\}\)
\(=12:\left\{390:\left[500-370\right]\right\}\)
\(=12:\left\{390:130\right\}\)
\(=12:3=4\)
125 + 5 x n - 2 = 163
=> 5 x n - 2 = 38
=> 5 x n = 40
=> n = 8
tick đúng cho mình nhé !
Tính nhanh nếu có thể ( áp dụng quy tắc dấu ngoặc )
a, (125 - 679 + 145) - (125 - 679)
b, -37 + 54 + (-70) + (-163) + 246
a) (125 - 679 + 145) - (125 - 679)
= 125 - 679 + 145 - 125 + 679
= ( 125 - 125) - (679 - 679) + 145
= 0 - 0 + 145
= 145
a, (125 - 679 + 145) - (125 - 679)
125-679+145-125+679
=(125-125)+(-679+679)+145
=0+0+145
=145
b, -37 + 54 + (-70) + (-163) + 246
=[-37+(-70)+(-163)]+(54+246)
=[-107+(-163)]+300
=-270+300
=30
Trả lời:
\(a,\)\(\left(125-679+145\right)-\left(125-679\right)\)
\(=125-679+145-125+679\)
\(=\left(125-125\right)-\left(679-679\right)+145\)
\(=0-0+145\)
\(=145\)
\(b,\)\(-37+54+\left(-70\right)+\left(-163\right)+246\)
\(=\left(-37-163\right)+\left(54+246\right)-70\)
\(=-200+300-70\)
\(=100-70\)
\(=30\)
Hok tốt!
Vuong Dong Yet
tính nhanh
a) [ 128 + ( -78) + 100 ] + (-128)
b 125 + [ (-100) + 93 ] + (-218)
c) [ 453 + 74 + ( - 79 )] + ( - 527)
d)) −825 + (775 + 825 )
e) ( 163 - 413 ) - ( 187 - 637 )
Lời giải:
a. $=128-78+100-128=(128-128)+100-78=0+100-78=22$
b. $=125-100+93-218= (125+93-218)-100=0-100=-100$
c. $=453+74-79-527$
$=(453+74-527)-79 =0-79=-79$
d.
$=-825+775+825=(825-825)+775=0+775=775$
e.
$=163-413-187+637 = (163+637)-(413+187) = 800-600=200$
tính nhanh
3+54+(-70)+(-163)+246
25.8.12.2016^0.(-125)
(-5)^2.12+(90-135)-(-1)^15
15.(17-111)-17.(555+15)
Bài 7. Tính nhanh
a/ 498mũ 2
b/ 93. 107
c/ 163 mũ 2+ 74.163 + 37mũ 2
d/ 1995 mũ 2 – 1994.1996
e/ 9 mũ 8.2 mũ 8 – (18mũ 4 – 1)(18 mũ 4+ 1)
f/ 125 mũ 2 - 2. 125. 25 + 25 mũ 2
Bài 8. Rút gọn các biểu thức sau
a/ (x mũ 2+ 3x+ 1)mũ 2 + (3x – 1) mữ 2 – 2(x mũ 2+ 3x+ 1)(3x– 1)
b/ (3x mũ 3+ 3x + 1)(3x mũ 3– 3x +1) – (3xmũ 3+1)mũ 2
c/ (2xmũ2+ 2x + 1)(2xmũ2 – 2x + 1) – (2xmũ 2+ 1)mũ 2
Bài 9. Rút gọn rồi tính giá trị biểu thức
a/ A = (2x + y)mũ 2 - (2x + y) (2x - y)+ y(x - y) vì x= - 2; y= 3.
b/ B = (a - 3b)mũ 2 - (a + 3b)mũ 2 - (a -1)(b -2 ) vì a =1/2; b = -3.
MN GIÚP MIK VS MIK CẦN GẤP
Bài 9:
a) Ta có: \(A=\left(2x+y\right)^2-\left(2x+y\right)\left(2x-y\right)+y\left(x-y\right)\)
\(=4x^2+4xy+y^2-4x^2+y^2-xy-y^2\)
\(=3xy-y^2\)
\(=3\cdot\left(-2\right)\cdot3-3^2=-18-9=-27\)
b) Ta có: \(B=\left(a-3b\right)^2-\left(a+3b\right)^2-\left(a-1\right)\left(b-2\right)\)
\(=a^2-6ab+9b^2-a^2-6ab-9b^2-ab+2a+b-2\)
\(=-13ab+2a+b-2\)
\(=-13\cdot\dfrac{1}{2}\cdot\left(-3\right)+2\cdot\dfrac{1}{2}+\left(-3\right)-2\)
\(=\dfrac{31}{2}\)
Bài 7:
a) \(498^2=\left(500-2\right)^2=250000-2000+4=248004\)
b) \(93\cdot107=100^2-7^2=10000-49=9951\)
c) \(163^2+74\cdot163+37^2=\left(163+37\right)^2=200^2=40000\)
d) \(1995^2-1994\cdot1996=1995^2-1995^2+1=1\)
e) \(9^8\cdot2^8-\left(18^4-1\right)\left(18^4+1\right)\)
\(=18^8-18^8+1=1\)
f) \(125^2-2\cdot125\cdot25+25^2=\left(125-25\right)^2=100^2=10000\)
Bài 8:
a) Ta có: \(\left(x^2+3x+1\right)^2-2\left(x^2+3x+1\right)\left(3x-1\right)+\left(3x-1\right)^2\)
\(=\left(x^2+3x+1-3x+1\right)^2\)
\(=\left(x^2+2\right)^2\)
\(=x^4+4x^2+4\)
b) Ta có: \(\left(3x^3+3x+1\right)\left(3x^3-3x+1\right)-\left(3x^3+1\right)^2\)
\(=\left(3x^3+1\right)^2-9x^2-\left(3x^3+1\right)^2\)
\(=-9x^2\)
c) Ta có: \(\left(2x^2+2x+1\right)\left(2x^2-2x+1\right)-\left(2x^2+1\right)^2\)
\(=\left(2x^2+1\right)^2-4x^2-\left(2x^2+1\right)^2\)
\(=-4x^2\)
Chứng minh: S = 1 5 + 1 13 + 1 14 + 1 15 + 1 61 + 1 62 + 1 63 < 1 2
125+125*12-12