\(\frac{\frac{28}{31}\div\frac{7}{31}}{\frac{8}{9}\div\frac{4}{9}}\)
Tính nhanh
a) \(\frac{2}{3}\div\frac{4}{9}+\frac{1}{3}\div\frac{4}{9}=\)
b) \(\frac{9}{8}\div\frac{5}{7}-\frac{1}{8}\div\frac{5}{7}=\)
c) \(\frac{2}{5}\div\frac{7}{3}-\frac{2}{5}\div\frac{1}{3}=\)
d) \(\frac{3}{7}\div\frac{7}{3}+\frac{3}{7}\div\frac{9}{4}=\)
a)\(\frac{2}{3}:\frac{4}{9}+\frac{1}{3}:\frac{4}{9}\)
=\(\frac{4}{9}:\left(\frac{2}{3}+\frac{1}{3}\right)\)
=\(\frac{4}{9}:1=\frac{4}{9}\)
b
Tính nhanh:
A=\(\left(\frac{2}{5}+\frac{2}{9}+\frac{2}{11}\div\frac{7}{5}+\frac{7}{9}+\frac{7}{11}\right)\div\left(\frac{1}{3}-\frac{1}{4}+\frac{1}{5}\div\frac{7}{6}-\frac{7}{8}+\frac{7}{10}\right)\)
a= (\(\frac{2}{5}\)+\(\frac{2}{9}\)+\(\frac{2}{11}\)\(\times\)\(\frac{5}{7}\)\(+\frac{7}{9}\)\(+\frac{7}{11}\)\()\)
Tính:
a) \(\left(31\frac{6}{13}+5\frac{9}{41}\right)-36\frac{6}{13}\)
b) \(\left(17\frac{29}{31}-3\frac{7}{8}\right)-\left(2\frac{28}{31}-4\right)\)
a, \(\left(31\frac{6}{13}+5\frac{9}{41}\right)-36\frac{6}{13}=31\frac{6}{16}+5\frac{9}{41}-36\frac{6}{13}\)
\(=\left(31\frac{6}{16}-31\frac{6}{16}\right)+5\frac{9}{41}\)
\(=0+5\frac{9}{41}=5\frac{9}{41}\)
b, \(\left(17\frac{29}{31}-3\frac{7}{8}\right)-\left(2\frac{28}{31}-4\right)=17\frac{9}{31}-3\frac{7}{8}-2\frac{28}{31}+4\)
Tìm \(x\in Z\) : \(4\frac{5}{9}\div2\frac{5}{18}-7< x< \left(3\frac{1}{3}\div3,2+4,5\times1\frac{31}{45}\right)\div\left(-21\frac{1}{2}\right)\)
\(\Leftrightarrow-5< x< -\dfrac{1037}{1260}\)
=>\(x\in\left\{-4;-3;-2;-1\right\}\)
tính bằng cách thuận tiện
a. \(\frac{1}{2}\times\frac{2}{3}\div\frac{4}{3}\times\frac{4}{5}\div\frac{6}{5}\times\frac{6}{7}\div\frac{7}{8}\times\frac{8}{9}\div\frac{10}{9}\)
b.\(\frac{27}{49}\times\frac{49}{50}\times\frac{15}{51}\times(\frac{5}{10}-\frac{1}{2})\)
(7x6=5+2+6x7) =
a ) 4\(\frac{5}{9}\)\(\div\)\((-\frac{5}{7})\)\(+\frac{4}{9}\div\frac{\left(-5\right)}{7}\)
b ) \((-\frac{3}{5}+\frac{4}{9})\div\frac{7}{11}+(\frac{-2}{5}+\frac{5}{9})\div\frac{7}{11}\)
c ) \(\frac{6}{7}\div(\frac{3}{26}-\frac{3}{13})+\frac{6}{7}\div(\frac{1}{10}-\frac{8}{5})\)
d ) \(A=(2+4+6+........+100)\orbr{\begin{cases}3\\5\end{cases}}\div0,7+3(\frac{-2}{7})]\div(\frac{1}{2}+\frac{1}{4}+\frac{1}{6}+......+\frac{1}{100})\)
Giải cụ thể hộ mk vs
\(a,4\frac{5}{9}:\frac{\left(-5\right)}{7}+\frac{4}{9}:\frac{-5}{7}\)
\(=\frac{41}{9}.\frac{-7}{5}+\frac{4}{9}.\frac{-7}{5}\)
\(=\frac{-7}{5}.\left(\frac{41}{9}+\frac{4}{9}\right)\)
\(=-\frac{7}{9}.5\)
\(=-7\)
a)Bn Kaito Kid làm rùi!
B)Không viết lại đề
\(=\frac{11}{7}\cdot\left(-\frac{3}{5}+\frac{4}{9}-\frac{2}{5}+\frac{5}{9}\right)=\frac{11}{7}\cdot0=0\)
c)Không viết lại đề
\(A=\left(2+4+...+100\right)\left(\frac{3}{5}\cdot\frac{10}{7}-\frac{6}{7}\right):\left(\frac{1}{2}+\frac{1}{4}+...+\frac{1}{100}\right)\)
\(=\left(2+4+6+...+100\right)\cdot0\cdot\left(\frac{1}{2}+\frac{1}{4}+...+\frac{1}{100}\right)=0\)
\(=\frac{7}{6}\cdot\left(\frac{3}{26}-\frac{3}{13}+\frac{1}{10}-\frac{8}{5}\right)=\frac{7}{6}\left(\frac{-3}{26}+\frac{-17}{10}\right)=\frac{7}{6}\cdot\frac{236}{130}=\frac{413}{195}\)
D)
Dòng trên chữ D) là phần c)
Dưới phần c) là phần d) nha!(Lỗi đánh máy)
Tính
a/ \(A=17\frac{2}{31}-\left(\frac{15}{17}+6\frac{2}{31}\right)\)
b/ \(B=\left(31\frac{6}{13}+5\frac{9}{41}\right)-36\frac{6}{13}\)
c/ \(C=27\frac{51}{59}-\left(7\frac{51}{59}-\frac{1}{3}\right)\)
d/ \(D=\left(13\frac{29}{31}-3\frac{7}{8}\right)-\left(2\frac{28}{31}-4\right)\)
\(A=17\frac{2}{31}-\left(\frac{15}{17}+6\frac{2}{31}\right)=\left(17\frac{2}{31}-6\frac{2}{31}\right)-\frac{15}{17}=11-\frac{15}{17}=10+\left(1-\frac{15}{17}\right)=10\frac{2}{17}\)
\(B=\left(31\frac{6}{13}-36\frac{6}{13}\right)+5\frac{9}{41}=-5+5\frac{9}{41}=\frac{9}{41}\)
C=\(\left(27\frac{51}{59}-7\frac{51}{59}\right)+\frac{1}{3}=20+\frac{1}{3}=20\frac{1}{3}\)
\(D=\left(13\frac{29}{31}-2\frac{28}{31}\right)+\left(4-3\frac{7}{8}\right)=11\frac{1}{31}+\frac{1}{8}=11\frac{8+31}{31.8}=11\frac{39}{248}\)
\(4\frac{5}{9}\) \(\div\)\(2\frac{15}{8}\) - 7 < x < \((\)\(3\frac{1}{5}\)\(\div\)\(3,2\)+4,5\(\div\)\(1\frac{31}{45}\)\()\)\(\div\)\((\)\(\frac{3}{2}\)\()\)\(^{^2}\)
Tính hợp lí (nếu có thể)
a/A=\(49\frac{8}{23}\)- (\(5\frac{7}{32}\)+ \(14\frac{8}{23}\))
b/B=\(\frac{4}{9}\)\(\div\frac{1}{6}+\frac{4}{9}\div\frac{1}{12}-\frac{4}{9}\div\frac{1}{8}\)