rút gọn các phân thức:
a,\(\frac{a^2\left(b-c\right)+b^2\left(c-a\right)+c^2\left(a-b\right)}{ab^2-ac^2-b^3+bc^2}\)b,\(\frac{2x^3-7x^2-12x+45}{3x^3-19x^2+33x-9}\)c,\(\frac{x^3-y^3+z^3+3xyz}{\left(x+y\right)^2+\left(y+z\right)^2+\left(z-x\right)^2}\)
Rút gọn biểu thức :
1. \(\frac{2^{4m}-2^{4n}}{2^{2n}+2^{2m}}\)
2. \(\frac{a^2\left(b-c\right)+b^2\left(c-a\right)+c^2\left(a-b\right)}{ab^2-ac^2-b^3+bc^2}\)
3. \(\frac{2x^3-7x^2-12x+45}{3x^3-19x^2+33x-9}\)
4. \(\frac{x^3-y^3+z^3+3xyz}{\left(x+y\right)^2+\left(y+x\right)^2+\left(z-x\right)^2}\)
5. \(\frac{x^3+y^3+x^3-3xyz}{\left(x-y\right)^2+\left(y-z\right)^2+\left(z-x\right)^2}\)
Please, help me!~~~ Pt2
Rút gọn phân thức
1. \(\dfrac{a^2\left(b-c\right)+b^2\left(c-a\right)+c^2\left(a-b\right)}{ab^2-ac^2-b^3+bc^2}\)
2.\(\dfrac{2x^3-7x^2-12x+45}{3x^3-19x^2+33x-9}\)
3.\(\dfrac{x^3-y^3+z^3+3xyz}{\left(x+y\right)^2+\left(y+z\right)^2+\left(z-x\right)^2}\)
4. \(\dfrac{x^3+y^3+z^3-3xyz}{\left(x-y\right)^2+\left(y-z\right)^2+\left(z-x\right)^2}\)
RUT GON PHAN THUC
1) \(\frac{\left(x-y\right)^3-3xy\left(x+y\right)+y^3}{x-6y}\)
2) \(\frac{a^2\left(b-c\right)+b^2\left(c-a\right)+c^2\left(a-c\right)}{ab^2-ac^2-b^3+bc^2}\)
3) \(\frac{2x^3-7x^2-12x+45}{3x^3-19x^2+33x-9}\)
1. Tìm giá trị của x để các phân thức sau = 0 .
a) \(\dfrac{x^4+x^3+x+1}{x^4-x^3+2x^2-x+1}\)
b)\(\dfrac{x^4-5x^2+4}{x^4-10x^2+9}\)
2. Rút gọn các phân thức :
a) \(\dfrac{a^2\left(b-c\right)+b^2\left(c-a\right)+c^2\left(a-b\right)}{ab^2-ac^2-b^3+bc^2}\)
b) \(\dfrac{2x^3-7x^2-12x+45}{3x^3-19x^2+33x-9}\)
c) \(\dfrac{x^3-y^3+z^3+3xyz}{\left(x+y\right)^2+\left(y+x\right)^2+\left(z-x\right)^2}\)
d)\(\dfrac{x^3+y^3+z^3-3xyz}{\left(x-y\right)^2+\left(y-z\right)^2+\left(z-x\right)^2}\)
Bài 1:
a: \(A=\dfrac{x^4+x^3+x+1}{x^4-x^3+2x^2-x+1}=\dfrac{x^3\left(x+1\right)+\left(x+1\right)}{x^4-x^3+x^2+x^2-x+1}\)
\(=\dfrac{\left(x+1\right)\left(x^3+1\right)}{\left(x^2-x+1\right)\left(x^2+1\right)}=\dfrac{\left(x+1\right)^2}{x^2+1}\)
Để A=0 thì x+1=0
hay x=-1
b: \(B=\dfrac{x^4-5x^2+4}{x^4-10x^2+9}=\dfrac{\left(x^2-1\right)\left(x^2-4\right)}{\left(x^2-1\right)\left(x^2-9\right)}=\dfrac{x^2-4}{x^2-9}\)
Để B=0 thi (x-2)(x+2)=0
=>x=2 hoặc x=-2
Rút gọn phân thức
1/\(\frac{x^{3^{ }}-y^{3^{ }}+z^{3^{ }}+3xyz}{\left(x+y\right)^{2^{ }}+\left(y+z\right)^2+\left(z-x\right)^2}\)
2/\(\frac{x^{3^{ }}+y^{3^{ }}+z^3-3xyz}{\left(x-y\right)^2+\left(y-z\right)^2+\left(z-x\right)^2}\)
3/\(\frac{a^2\left(b-c\right)+b^2\left(c-a\right)+c^2\left(a-b\right)}{a^4\left(b^2-c^2\right)+b^4\left(c^2-a^3\right)+c^4\left(a^2-b^2\right)}\)
Rút gọn các phân thức sau:
a) \(\dfrac{a^3+b^3+c^3-3abc}{a^2+b^2+c^2-ab-bc-ca}\)
b) \(\dfrac{x^3-y^3+z^3+3xyz}{\left(x+y\right)^2+\left(x+z\right)^2+\left(z-x\right)^2}\)
a: \(=\dfrac{\left(a+b\right)^3+c^3-3ab\left(a+b+c\right)-3abc}{a^2+b^2+c^2-ab-bc-ac}\)
\(=\dfrac{\left(a+b+c\right)\left[\left(a+b\right)^2-c\left(a+b\right)+c^2\right]-3ab\left(a+b+c\right)}{a^2+b^2+c^2-ab-bc-ac}\)
\(=\dfrac{\left(a+b+c\right)\left(a^2+2ab+b^2-ac-bc+c^2-3ab\right)}{a^2+b^2+c^2-ab-bc-ac}\)
=a+b+c
b:
Sửa đề: \(=\dfrac{x^3-y^3+z^3+3xyz}{\left(x+y\right)^2+\left(y+z\right)^2+\left(z-x\right)^2}\)
\(=\dfrac{\left(x-y\right)^3+z^3+3xy\left(x-y\right)+3xyz}{\left(x+y\right)^2+\left(y+z\right)^2+\left(z-x\right)^2}\)
\(=\dfrac{\left(x-y+z\right)\left(x^2-2xy+y^2-xz+yz+z^2\right)+3xy\left(x-y+z\right)}{2\left(x^2+y^2+z^2+xy+yz-xz\right)}\)
\(=\dfrac{\left(x-y+z\right)\left(x^2+y^2+z^2+xy-xz+yz\right)}{2\left(x^2+y^2+z^2+xy+yz-xz\right)}\)
\(=\dfrac{x-y+z}{2}\)
a) \(\dfrac{a^3+b^3+c^3-3abc}{a^2+b^2+c^2-ab-bc-ca}\)
\(=\dfrac{\left(a+b+c\right)\left(a^2+b^2+c^2-ab-bc-ca\right)}{a^2+b^2+c^2-ab-bc-ca}\)
\(=a+b+c\)
Bài 1 : Rút gọn
a)\(\frac{x^3+y^3+z^3-3xyz}{\left(x-y\right)^2+\left(y-z\right)^2+\left(z-x\right)^2}\)
b) \(\frac{a^2\left(b-c\right)+b^2\left(c-a\right)+c^2\left(a+b\right)}{a^4\left(b^2-c^2\right)+b^4\left(c^2-a^2\right)+c^4\left(a^2-b^2\right)}\)
Rút gọn các phân thức sau:
a) \(\dfrac{x^6+2x^3y^3+y^6}{x^7-xy^6}\)
b) \(\dfrac{\left(2x^2+2x\right)\left(x-2\right)^2}{\left(x^3-4x\right)\left(x+1\right)}\)
c) \(\dfrac{x^3-x^2y+xy^2}{x^3+y^3}\)
d) \(\dfrac{a^2+b^2-c^2+2ab}{a^2-b^2+c^2+2ac}\)
e) \(\dfrac{2x^3-7x^2-12x+45}{3x^3-19x^2+33x-9}\)
a) \(\dfrac{x^6+2x^3y^3+y^6}{x^7-xy^6}=\dfrac{\left(x^3+y^3\right)^2}{x\left(x^6-y^6\right)}\)
\(=\dfrac{\left(x^3+y^3\right)^2}{x\left(x^3-y^3\right)\left(x^3+y^3\right)}\)
\(=\dfrac{x^3+y^3}{x\left(x^3-y^3\right)}\)
b) \(\dfrac{\left(2x^2+2x\right)\left(x-2\right)^2}{\left(x^3-4x\right)\left(x+1\right)}=\dfrac{2x\left(x+1\right)\left(x-2\right)^2}{x\left(x^2-4\right)\left(x+1\right)}\)
\(=\dfrac{2x\left(x+1\right)\left(x-2\right)^2}{x\left(x-2\right)\left(x+2\right)\left(x+1\right)}\)
\(=\dfrac{2\left(x-2\right)}{x+2}\)
c) \(\dfrac{x^3-x^2y+xy^2}{x^3+y^3}=\dfrac{x\left(x^2-xy+y^2\right)}{\left(x+y\right)\left(x^2-xy+y^2\right)}\)
\(=\dfrac{x}{x+y}\)
d) \(\dfrac{a^2+b^2-c^2+2ab}{a^2-b^2+c^2+2ac}=\dfrac{\left(a^2+2ab+b^2\right)-c^2}{\left(a^2+2ac+c^2\right)-b^2}\)
\(=\dfrac{\left(a+b\right)^2-c^2}{\left(a+c\right)^2-b^2}\)
\(=\dfrac{\left(a+b-c\right)\left(a+b+c\right)}{\left(a-b+c\right)\left(a+b+c\right)}\)
\(=\dfrac{a+b-c}{a-b+c}\)
e) \(\dfrac{2x^3-7x^2-12x+45}{3x^3-19x^2+33x-9}=\dfrac{\left(x-3\right)\left(2x^2-x-15\right)}{\left(x-3\right)\left(3x^2-10x+3\right)}\)
\(=\dfrac{2x^2-x-15}{3x^2-10x+3}\)
\(=\dfrac{\left(x-3\right)\left(2x+5\right)}{\left(x-3\right)\left(3x-1\right)}\)
\(=\dfrac{2x+5}{3x-1}\)
Rút gọn phân thức :
a) A = \(\frac{bc-a^2+ac-b^2+ab-c^2}{a\left(bc-a^2\right)+b\left(ac-b^2\right)+c\left(ab-c^2\right)}\)
b) B = \(\frac{x^5+x+1}{x^3+x^2+x}\)
c) C = \(\frac{y^3-x^3}{x^3-3x^2y+3xy^2-y^3}\)