các bạn ơi giúp mình với , mình cần gấp lắm

Mình chỉ biết là ra 1/16 thôi

125696

Thôi mình tính rồi ra 255

256x236+256x256-256=256x(236+256-1)=256x491=125696

125696

 tick đi 

mình tự làm đó

\(256\cdot236+256\cdot256-256=125696\)

(64 x 64 +256 x 256)/ (256 x 256 + 1024 x 1024)

= (64 x 64 + 64 x4 x 64 x 4)/(256 x 256 + 256 x4 x 256 x4)

= [64 x 64(1+4 x4 )]/[256 x 256(1+ 4x4)]

=64 x 64 /256 x 256

= 64 x 64 / 64 x4 x 64 x4  

= 1/16

\(\frac{\text{(64 x 64 +256 x 256)}}{\text{(256 x 256 + 1024 x 1024) }}\)

= \(\frac{\text{(64 x 64 + 64 x4 x 64 x 4)}}{\text{(256 x 256 + 256 x4 x 256 x4) }}\)

= \(\frac{\text{[64 x 64(1+4 x4 )]}}{\text{[256 x 256(1+ 4x4)] }}\)

=\(\frac{\text{64 x 64}}{\text{256 x 256 }}\) 

= \(\frac{\text{ 64 x 64 }}{\text{64 x4 x 64 x4 }}\)

= \(\frac{1}{\text{16}}\)

má + ba = hai người

-1+3=2

đúng o bạn 

nhé

sai rùi bn ơi đố vui mà!

\(A=256-\dfrac{256}{2}-\dfrac{256}{2^2}-\dfrac{256}{2^3}-.......-\dfrac{256}{2^9}\)
\(\Leftrightarrow A=256\left(1-\dfrac{1}{2}-\dfrac{1}{2^2}-\dfrac{1}{2^3}-.....-\dfrac{1}{2^9}\right)\)
Đặt \(B=\dfrac{1}{2}-\dfrac{1}{2^2}-\dfrac{1}{2^3}-.....-\dfrac{1}{2^9}\)
\(\Leftrightarrow2B=1-\dfrac{1}{2}-\dfrac{1}{2^2}-.....-\dfrac{1}{2^8}\)
\(\Leftrightarrow2B-B=1-\dfrac{1}{2^9}\)
\(\Leftrightarrow B=1-\dfrac{1}{2^9}\)
\(\Leftrightarrow A=256\left(1-\dfrac{1}{2^9}\right)\)
\(\Leftrightarrow A=256-\dfrac{1}{2^9}\)
\(\Leftrightarrow A=2^8-\dfrac{1}{2^9}\)
\(\Leftrightarrow A=\dfrac{2^{17}}{2^9}-\dfrac{1}{2^9}\)
\(\Leftrightarrow A=\dfrac{2^{17}-1}{2^9}\)
Vậy \(\Leftrightarrow A=\dfrac{2^{17}-1}{2^9}\)
Chúc bạn học tốt >w<

\(=\dfrac{64^2+256^2}{256^2+1024^2}=\dfrac{64^2\left(1+4^2\right)}{256^2\left(1+4^2\right)}=\left(\dfrac{64}{256}\right)^2=\dfrac{1}{16}\)

=3153,tk cho mình nha!

= 3153 nhe

= 3153  nhoa