\(15+\dfrac{17}{5}=\dfrac{14,7}{x}+11,4\) 

\(\dfrac{92}{5}=\dfrac{14,7}{x}+11,4\)

\(18,4=\dfrac{14,7}{x}+11,4\)

\(\dfrac{14,7}{x}=18,4-11,4\)

\(\dfrac{14,7}{x}=7\)

\(x=\dfrac{14,7}{7}\)

\(x=2,1\)

giải chi tiết giúp mình nhé

= 20,18 x(15,75+ 72,41 + 11,84)

= 20,18 x 100

= 2018

Lời giải:
$20,18\times 8,5+20,18+20,18:2$

$=20,18\times 8,5+20,18\times 1+20,18\times 0,5$

$=20,18\times (8,5+1+0,5)=20,18\times 10=201,8$

20,18 x ( 31,06 +67,82+1)

= 20,18 x 99,88

= 2015,5704

20,18 x ( 31,06 +67,82+1)

= 20,18 x 99,88

= 2015,5704

a) 25,5 : 0,2 + 25,5 : 0,125 - 25,5 x 2 - 25,5

= 25,5 x 5 + 25,5 x 8 - 25,5 x 2 - 25,5 x 1

= 25,5 x (5 + 8 - 2 - 1)

= 25,5 x 10

= 255

b) 20,18 x 7,5 + 20,18 x 2 + 20,18 : 2

= 20,18 x 7,5 + 20,18 x 2 + 20,18 x 0,5

= 20,18 x (7,5 + 2 + 0,5)

= 20,18 x 10

= 201,8

a) \(25,5:0,2+25,5:0,125-25,5\times2-25,5\)

\(=25,5\times5+25,5\times8-25,5\times2-25,5\)

\(=25,5\times\left(5+8-2-1\right)\)

\(=25,5\times10=255\)

b) \(20,18\times7,5+20,18\times2+20,18:2\)

\(=20,18\times7,5+20,18\times2+20,18\times0,5\)

\(=20,18\times\left(7,5+2+0,5\right)\)

\(=20,18\times10=201,8\)

\(#Nulc`\)

X x 3        "chỗ này bị thiếu dấu"          Y: 0,5 = 14,7 

a, 20,18 x 7,5 + 20,18 + 20,18 + 20,18 : 2

= 20,18 x 7,5 + 20,18 x 1 + 20,18 x 1 + 20,18 x 0,5

= 20,18 x ( 7,5 + 1 + 1 + 0,5)

= 20,18 x 10

= 201,8 

b, 100 : 9   - 79,3 : 9

= (100 - 79,3) : 9

= 20,7 : 9

= 2,3

x = 0

Đáp án B

1. Vì ab3 chia hết cho 9 nên ab= 51, đồng thời 5-1=4

Vậy ab=51

2. ( 14,7-y) = 1/3: 2/9

      14,7-y  = 3/2

              y  = 14,7-3/2

              y  = 14,7- 1,5

             y   = 13,2