#include <bits/stdc++.h>
#define ll long long
using namespace std;
ll i, j, n, a[1000005], dem = 0, m;
int main()
{
    ios::sync_with_stdio(0);
    cin.tie(0);
    cout.tie(0);
    cin >> n;
    for (i = 1; i <= n; i++)
    {
        cin >> a[i];
        if (a[i] % 3 == 0)
        {
            n--;
            i--;
        }
    }
    for (i = 1; i <= n; i++)
    {
        cout << a[i] << " ";
    }
    cout<<endl;
    for(i=1;i<=n;i++)
    {
        if(a[i]%5==0)
        {
            for(j=i;j<=n;j++)
            {
                a[j]=a[j+1];
            }
            n--;
            i--;
        }    
    }
    for(i=1;i<=n;i++)
    {
        cout<<a[i]<<" ";
    }
    return 0;
}

bài 1:

var i,n : integer;

writeln('nhap n');

readln(n);

for i:=1 to 100 do

s:=s+i;

writeln('tong la",s);

readln;

end.

bài 2:

var n:real;

begin

writeln('nhap n');

if n (mod 2=0) and (n mod 3=0) then

writeln('chia het roi')

else writeln(khong chia het');

readln;

end.

def xoa_phan_tu_chia_het_cho_3(arr):
    return [x for x in arr if x % 3 != 0]

# Nhập số phần tử của dãy
n = int(input())

# Nhập dãy số nguyên
day_so = list(map(int, input().split()))

# Xóa các phần tử chia hết cho 3
ket_qua = xoa_phan_tu_chia_het_cho_3(day_so)

# In ra dãy sau khi xóa
print(*ket_qua)

uses crt;

var i,n,d:longint;

begin 

d:=0;

writeln('nhapn=');read(n);

for i:=1 to n do

begin

if i mod 3=0 then write(i,' ');

if i mod 3=0 then d:=d+i;

end;

writeln('tong=',d);

readln;

end;

Cái này mình viết chương trình chính thôi, bạn tự viết ctc nhé

Câu 1: 

uses crt;

var n,i,s:longint;

begin

clrscr;

write('Nhap n='); readln(n);

s:=1;

for i:=1 to n do

 s:=s*i;

writeln(s);

readln;

end.

Câu 2: 

uses crt;

var st:string;

i,d:integer;

begin

clrscr;

write('Nhap xau:'); readln(st);

d:=length(st);

for i:=d downto 1 do 

  write(st[i]);

readln;

end.

Câu 3: 

uses crt;

var n:integer;

st:string;

begin

clrscr;

write('Nhap n='); readln(n);

str(n,st);

writeln('So ',n,' co ',length(st),' chu so');

readln;

end.

uses crt;

var n,i,d,dem,kt,t,kt1,t1,t2,t3,max,min,x,j:integer;   

a,b:array[1..100]of integer;   

st:string;

begin

clrscr;

write('Nhap n='); readln(n);

str(n,st);

d:=length(st);

for i:=1 to d do 

val(st[i],a[i],x);

dem:=1;

b[1]:=a[1];

for i:=1 to d do 

begin     

kt:=0;     

for j:=1 to dem do       

if a[i]=b[j] then kt:=1;     

if kt=0 then       

begin           

inc(dem);           

b[dem]:=a[i];       

end; 

end;

writeln('Cac chu so cua ',n,' la: ');

for i:=1 to dem do 

write(b[i]:4);

writeln;

t:=0;

for i:=1 to d do 

t:=t+a[i];

writeln('Tong cac chu so cua ',n,' la: ',t);

kt1:=0;

for i:=2 to trunc(sqrt(t)) do 

if t mod i=0 then     

begin       

kt1:=1;       

break;     

end;

if (kt1=0) and (t>1) then writeln(t,' la so nguyen to')

else writeln(t,' khong la so nguyen to');

writeln('Cac chu so o vi tri le cua ',n,' la: ');

t1:=0;

for i:=1 to d do 

if i mod 2=1 then     

begin       

write(a[i]:4);       

t1:=t1+a[i];     

end;

writeln;

writeln('Tong cac chu so o vi tri le la: ',t1);

if trunc(sqrt(t1))=sqrt(t1) then writeln(t1,' la so chinh phuong')

else writeln(t1,' khong la so chinh phuong');

writeln('Cac chu so o vi tri chan cua ',n,' la: ');

t2:=0;

for i:=1 to d do 

if i mod 2=0 then     

begin       

write(a[i]:4);       

t2:=t2+a[i];     

end;

writeln('Tong cac chu so o vi tri chan la: ',t2);

t3:=0;

for i:=1 to t2 do 

if t2 mod i=0 then t3:=t3+i;

if (t3=t2) and (t2>0) then writeln(t2,' la so hoan hao')

else writeln(t2,' khong la so hoan hao');

max:=a[1];

min:=a[1];

for i:=1 to d do 

begin     

if max<a[i] then max:=a[i];     

if min>a[i] then min:=a[i]; 

end;

writeln('Chu so lon nhat cua ',n,' la: ',max);

writeln('Chu so nho nhat cua ',n,' la: ',min);

writeln('Tong cua chung la: ',max+min);

readln;

end.

Bài 2: 

uses crt;

var x,i,n,dem:integer;

begin

clrscr;

readln(n);

dem:=0;

for i:=1 to n do 

begin

readln(x);

if x mod 2=0 then inc(dem);

end;

writeln(dem);

readln;

end.

Program HOC24;

var i,n: integer;

begin

write('Nhap N: '); readln(n);

write('Cac so tu 1 den ',n,' chia het cho 2 la: ');

for i:=1 to n do if i mod 2=0 then write(i,' ');

writeln;

for i:=1 to n do if i mod 2=1 then write(i,' ');

readln

end.

Uses CRT;
Var n: word;
Begin
  Clrscr;
  write('Nhap n:  '); readln(n);
       if (n mod 2 = 0) and (n mod 3 = 0) then write('So do chia het cho 2 va 3')
  else if (n mod 2 <>0) and (n mod 3 <> 0) then write('So do khong chia het cho 2 va 3')
  else if (n mod 2 = 0) and (n mod 3 <> 0) then write('So do chia het cho 2 nhung khong chia het cho 3')
  else write('So do chia het cho 3 nhung khong chia het cho 2');
readln
end.