a)8²*32⁴=(2³)²*(2⁵)⁴=2⁶*2²⁰=2²⁶

b)27³*9⁴*24³=(3³)³*(3²)⁴*(3*8)³=3⁹*3⁸*3³*8³=3²⁰*8³

c)7⁷+6*49*7⁵=7⁵+6*7²*7⁵=7⁵+6*7⁷=7⁵(1+6*7²)

bai toán này kho lắm

tớ cũng đanh thắc mắc câu này

Viết các kết quả sau dưới dạng một lũy thừa: 

9¹². 27⁴. 81³ và 4⁸ . 2¹⁰ 

Giúp mk vs

a, 4¹⁰. 2³⁰=2²⁰.2³⁰=2⁵⁰

b,9²⁵.27⁴.81³= 3⁵⁰.3¹².3¹²=3⁷⁴

Tương tự các câu khác....

a, 4¹⁰.2³⁰ = (2²)¹⁰.2³⁰ = 2²⁰.2³⁰ = 2⁵⁰
b, 9²⁵.27⁴.81³ = (3²)²⁵.(3³)⁴.(3⁴)³ = 3⁵⁰.3¹².3¹² = 3⁷⁴
c, 25⁵⁰.125⁵ = (5²)⁵⁰.(5³)⁵ = 5¹⁰⁰.5¹⁵ = 5¹¹⁵
d, 64³.4⁸.16⁴ = (2⁶)³.(2²)⁸.(2⁴)⁴ = 2¹⁸.2¹⁶.2¹⁶ = 2⁵⁰
e, 3⁸ : 3⁶ = 3²
2¹⁰ : 8³ = 2¹⁰ : (2³)³ = 2¹⁰ : 2⁹ = 2
12⁷ : 6⁷ = (12 : 6)⁷ = 2⁷
@Dương Tuyết Mai

a) \(4^3\cdot32^4\)

\(=\left(2^2\right)^3\cdot\left(2^5\right)^4\)

\(=2^6\cdot2^{20}\)

\(=2^{26}\)

b) \(3^{20}\cdot9^{10}\cdot27^2\)

\(=3^{20}\cdot\left(3^2\right)^{10}\cdot\left(3^3\right)^2\)

\(=3^{20}\cdot3^{20}\cdot3^6\)

\(=3^{46}\)

c) \(3^{10}\cdot7^{10}\)

\(=\left(3\cdot7\right)^{10}\)

\(=21^{10}\)

d) \(6^{15}:6^{14}\)

\(=6^{15-14}\)

\(=6\)

e) \(28^3:7^3\)

\(=4^3\cdot7^3:7^3\)

\(=4^3\)

\(=2^6\)

a, 27³ : 3⁵  =  ( 3³)³ : 3⁵ = 3⁹ : 3⁵ = 3⁴

b, 7² . 343 . 49³⁰ = 7². 7³.(7²)³  = 7¹¹

c, 625 : 5³ = 5⁴ : 5³ =  5

d, 1 000 000 : 10³ = 10⁶ . 10³ = 10³

e, 11⁵ : 121= 11⁵ : 11² = 11³

f, 8⁷ : 64 :8 = 8⁷ : 8² : 8¹ = 8⁴

i, 1024 . 16 : 2⁶  = 2¹⁰ . 2³ : 2⁶ = 2⁷

B2:

 số chính phương là:

4 ; 121 ; 196 ; 225.

Bài 2 :

Số chính phương là :

\(4=2^2\)

\(121=11^2\)

\(196=14^2\)

\(225=25^2\)

a) 1024 : 2⁶

= 2¹⁰ : 2⁶

= 2^{10 - 6} = 2⁴

b) 3⁷ : 27

= 3⁷ : 3³

= 3^{7 - 3} = 3⁴

c) 125 : 5²

= 5³ : 5²

= 5^{3 - 2} = 5

\(\dfrac{3}{2}\times\dfrac{9}{4}\times\dfrac{81}{16}=\dfrac{3}{2}\times\left(\dfrac{3}{2}\right)^2\times\left(\dfrac{3}{2}\right)^4=\left(\dfrac{3}{2}\right)^7\)

\(\left(\dfrac{1}{2}\right)^7\times8\times32\times2^8=\left(\dfrac{1}{2}\right)^7\times2^3\times2^5\times2^8=\left(\dfrac{1}{7}\right)^7\times2^{16}\)

\(\left(-\dfrac{1}{7}\right)^4\times125\times5=\left(-\dfrac{1}{7}\right)^4\times5^3\times5=\left(-\dfrac{1}{7}\right)^4\times5^4\)

\(4\times32:\left(2^3\times\dfrac{1}{16}\right)=2^2\times2^5:2^3:2^{-4}=2^0\)

\(\left(\dfrac{1}{7}\right)^2\times\dfrac{1}{7}\times49=\left(\dfrac{1}{7}\right)^3\times7^3=1^3\)
 

6, \(\dfrac{3}{2}\times\dfrac{9}{4}\times\dfrac{81}{16}=\dfrac{3}{2}\times\left(\dfrac{3}{2}\right)^2\times\left(\dfrac{3}{2}\right)^4\)

7,\(\left(\dfrac{1}{2}\right)^7\times8\times32\times2^8=\left(\dfrac{1}{2}\right)^7\times2^3\times2^5\times2^8\)

8,\(\left(-\dfrac{1}{7}\right) ^4\times125\times5=\left(\dfrac{1}{7}\right)^4\times5^3\times5\)

9,\(4\times32:\left(2^3\times\dfrac{1}{16}\right)=2^2\times2^5:\left[2^3\times\left(\dfrac{1}{2}\right)^4\right]\)

10, \(\left(\dfrac{1}{7}\right)^2\times\dfrac{1}{7}\times49=\left(\dfrac{1}{7}\right)^2\times\dfrac{1}{7}\times7^2\)

6) \(...=\dfrac{3}{2}.\left(\dfrac{3}{2}\right)^2.\left(\dfrac{3}{2}\right)^4=\left(\dfrac{3}{2}\right)^7\)

7) \(...=2^{-7}.2^3.2^5.2^8=2^9\)

8) \(...=\left(\dfrac{1}{7}\right)^4.5^3.5=\left(\dfrac{1}{7}\right)^4.5^4\)

9) \(...=2^2.2^5:\left(2^3.2^{-4}\right)=2^8\)

10) \(...=\left(\dfrac{1}{7}\right)^3.\left(\dfrac{1}{7}\right)^2=\left(\dfrac{1}{7}\right)^5\)