the number of solutions to the polynomial x^8+8 is
the number of solutions to the polynomial x^8 + 8 is......
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The number of solutions to the polynomial x^8+8 is...
bài này vòng 1 bài đi tìm kho báu đúng ko bạn , mk cũng gặp
tìm sô lượng nhân tử của đa thức x8 + 8 .
đáp án là 0
The number of solutions of the below polynomial:
\(3x^2+8x^3+x^4+9+\left(-2x\right)^3-3x^2\)
(Giai dum mk nha, ai gioi TA thj dik de dum luon nha!)
We have \(3x^2+8x^3+x^4+9-8x^3-3x^2\)
\(=\left(3x^2-3x^2\right)+\left(8x^3-8x^3\right)+\left(x^4-9\right)\)
\(=x^4-9\)
If my answer is right, I hope you k for me =)) =.='
key: \(3x^2+8x^3+x^4+9+\left(-2x\right)^3-3x^2\)
\(=3x^2+8x^3+x^4+9-2x^3-3x^2\)
\(=\left(3x^2-3x^2\right)+\left(8x^3-2x^3\right)+x^4+9\)
\(=4x^3+x^4+9\)
Bạn Hương sai rồi : đề bài người ta cho là \(\left(-2x\right)^3=-8x^3\)
chứ ko phải là \(\left(-2x^3\right)\)
Với lại \(\left(8x^3-2x^3\right)=6x^3\)chứ đâu phải là \(4x^3\)
the sum of two numbers is equal to 77 if the first number is mutiplied by 8 and the second number by 6, the two product is equal. the larger number of these numbers is ...
tổng của hai số bằng 77 nếu số đầu tiên được nhân 8 và số thứ hai 6, cáctích hai là bằng nhau. số lượng lớn hơn của những con số này là ..
bài toán sai đề rồi vì 77 ko chia hết cho 14
find the value of n such that the polynomial 2x^5 - 3x^3 + x^2 +n is divisible by the polynomial x+2
tìm giá trị của n sao cho đa thức 2x ^ 5 - 3x ^ 3 + x ^ 2 + n chia hết cho đa thức x + 2
The sum of two numbers is equal to 77. If the first number is multiplied by 8 and the second by 6, the two products are equal. The larger of two number is...
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